How does the nth term test show a series diverges, and why can it never prove convergence?
Topic 10.3 The nth Term Test for Divergence: use the limit of the terms to conclude divergence when the terms do not approach zero (BC).
A focused answer to AP Calculus BC Topic 10.3, using the nth term test to conclude divergence when the terms fail to approach zero, and understanding why it can never prove convergence, with worked examples.
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What this topic is asking
The College Board (Topic 10.3, BC only) gives the -th term test for divergence, the quickest divergence check and the one to try first on any series. It uses a simple necessary condition: if a series converges, its terms must shrink to zero, so terms that do not shrink to zero force divergence.
The test and its one-way logic
Why it can only prove divergence
The test rests on a theorem: if converges, then . Logically, the test is the contrapositive: if the terms do not go to zero, the series cannot converge, so it diverges. But the original theorem is a one-way implication; its converse ("terms go to zero implies convergence") is false. The decisive counterexample is the harmonic series , whose terms yet whose partial sums grow without bound. This is why leaves you no conclusion: the condition is necessary for convergence but not sufficient. Explaining this distinction is a recurring free-response request, as in the worked exam question above.
A worked divergence conclusion
When the limit does not exist
The test also fires when the terms have no limit at all, not just a nonzero one. For , the terms alternate and never settle, so does not exist; the series diverges. Likewise has terms that oscillate without approaching anything, giving divergence. The unifying statement is that convergence requires ; any failure of that, whether a nonzero limit or no limit, means divergence. So when you compute the limit of the terms, watch for oscillation as well as nonzero values, and treat both as immediate divergence.
Where it fits in the testing strategy
The -th term test is the first move in any convergence problem because it is cheap and decisive when it applies. If the terms obviously do not tend to zero (a ratio of equal-degree polynomials, a constant, an oscillation), you are done: divergence. If the terms do tend to zero, you have learned only that you need a real test, the integral test, comparison, ratio, alternating-series, or -series, depending on the form. Building the habit of checking first saves time and catches divergent series that a more elaborate test would also catch but more slowly. Just never write "the terms go to zero, so the series converges," which inverts the test illegitimately.
Exam-style practice questions
Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
AP 2021 (BC, style)1 marksSection I (multiple choice, no calculator). The nth term test shows which series diverges? (A) (B) (C) (D) Show worked answer β
The correct answer is (A), .
, so the nth term test gives divergence. The others have terms tending to , so the test is inconclusive for them (and B, D actually converge).
AP 2023 (BC, style)4 marksSection II (free response, no calculator). (a) State the nth term test for divergence. (b) Apply it to . (c) Explain why the test cannot be used to prove a series converges.Show worked answer β
A 4-point conceptual problem.
(a) (1 point) If (or does not exist), then diverges.
(b) (2 points) , so the series diverges.
(c) (1 point) is necessary but not sufficient; when the limit is the test is inconclusive (e.g. has terms tending to yet diverges).
Related dot points
- Topic 10.1 Defining Convergent and Divergent Infinite Series: define the convergence of an infinite series as the limit of its sequence of partial sums (BC).
A focused answer to AP Calculus BC Topic 10.1, defining the convergence and divergence of an infinite series through the limit of its sequence of partial sums, distinguishing a sequence from a series, with worked examples.
- Topic 10.5 Harmonic Series and p-Series: apply the p-series rule (converges iff p greater than 1) and recognize the harmonic series as the divergent p = 1 case (BC).
A focused answer to AP Calculus BC Topic 10.5, applying the p-series convergence rule (converges iff p is greater than 1), recognizing the harmonic series as the divergent borderline case, with worked examples.
- Topic 10.2 Working with Geometric Series: determine convergence of a geometric series by its common ratio and find its sum with the a over one-minus-r formula (BC).
A focused answer to AP Calculus BC Topic 10.2, deciding convergence of a geometric series from its common ratio and computing its sum with the a over one-minus-r formula, with worked examples.
- Topic 10.8 Ratio Test for Convergence: use the limit of the ratio of consecutive terms to decide absolute convergence or divergence, especially for factorials and exponentials (BC).
A focused answer to AP Calculus BC Topic 10.8, using the ratio test to decide absolute convergence or divergence from the limit of consecutive-term ratios, especially for series with factorials and exponentials, with worked examples.
- Topic 1.15 Connecting Limits at Infinity and Horizontal Asymptotes: evaluate limits as x approaches plus or minus infinity and use them to identify horizontal asymptotes, especially for rational functions.
A focused answer to AP Calculus AB Topic 1.15, evaluating limits as x approaches infinity, the degree rule for rational functions, and identifying horizontal asymptotes, with worked examples.
- Topic 10.4 Integral Test for Convergence: use the convergence of a related improper integral to decide convergence of a series with positive, decreasing terms (BC).
A focused answer to AP Calculus BC Topic 10.4, using the integral test to decide convergence of a series with positive decreasing terms by evaluating a related improper integral, with worked examples.
Sources & how we know this
- AP Calculus AB and BC Course and Exam Description β College Board (2020)