Skip to main content
United StatesCalculusSyllabus dot point

What is a slope field, and how do you draw one from a differential equation?

Topic 7.3 Sketching Slope Fields: construct a slope field by computing the slope at grid points from a differential equation.

A focused answer to AP Calculus AB Topic 7.3, constructing a slope field by evaluating the differential equation at grid points to draw short tangent segments, with a worked grid example and the meaning of the field.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this topic is asking
  2. Constructing the field
  3. A worked grid of slopes
  4. Reading structure in the field
  5. Why slope fields matter
  6. Special slopes that organize the field
  7. A practical tip for hand-drawn fields

What this topic is asking

The College Board (Topic 7.3) introduces the slope field: a grid of short line segments, each drawn with the slope the differential equation gives at that point. It is a graphical picture of all the solution curves at once, built without solving the equation.

Constructing the field

A worked grid of slopes

Reading structure in the field

Certain features make slope fields quick to draw and to recognize. Where dydx=0\frac{dy}{dx} = 0, the segments are horizontal, marking where solution curves level off; this set is often a line or curve. Where dydx\frac{dy}{dx} depends only on xx, the field looks the same in every horizontal row (slopes vary across, not up and down); where it depends only on yy, the field repeats in every vertical column. The exam often gives a slope field and asks which differential equation produced it, answered by checking these structural clues at a few sample points rather than every point.

Why slope fields matter

A slope field visualizes the behavior of solutions to a differential equation that may be hard or impossible to solve in closed form. By following the segments, you can trace the approximate shape of the solution curve through any starting point, which is the next topic. The single most common construction error is using the yy-value as the slope when the equation gives the slope as a formula in xx and yy: the slope is dydx\frac{dy}{dx} evaluated at the point, not the height of the point. Computing the slope from the equation at each grid point, segment by segment, builds the field correctly.

Special slopes that organize the field

Two kinds of grid point are worth computing first because they anchor the whole field. Zero-slope points, where dydx=0\frac{dy}{dx} = 0, get horizontal segments and mark where solution curves level off; the set of such points is often a recognizable line or curve. Points where dydx\frac{dy}{dx} is very large in magnitude get nearly vertical segments and show where solutions rise or fall steeply. Locating the zero-slope locus and any steep regions first gives the field its skeleton, after which the remaining grid points fill in the detail. This is faster than computing every point cold, and it makes the structure of the solutions visible immediately.

A practical tip for hand-drawn fields

When sketching by hand under exam conditions, you only need a few representative segments to convey the field, not a dense grid. Choose grid points that capture the key behavior, near equilibria, along an axis, and in each region the zero-slope locus separates, and draw short segments of the correct slope. Keep the segments uniformly short so the eye reads slope rather than length, and make sure horizontal segments are clearly flat where dydx=0\frac{dy}{dx} = 0. A clean sparse field that correctly shows the slopes at meaningful points earns full credit and is quicker to produce than an over-dense one.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2022 (style)1 marksSection I (multiple choice). For dydx=x\frac{dy}{dx} = x, the slope-field segment drawn at the point (2,5)(2, 5) has slope (A) 55 (B) 22 (C) 25\frac{2}{5} (D) 00
Show worked answer →

The correct answer is (B), 22.

The slope at a point is dydx\frac{dy}{dx} evaluated there. Since dydx=x\frac{dy}{dx} = x, at (2,5)(2, 5) the slope is x=2x = 2 (the yy-value does not enter).

AP 2024 (style)3 marksSection II (free response). Consider dydx=xy\frac{dy}{dx} = x - y. (a) Find the slope of the field at the points (0,0)(0, 0), (1,0)(1, 0), and (0,1)(0, 1). (b) On the line y=xy = x, what is special about the slope-field segments?
Show worked answer →

A 3-point slope-field question.

(a) (2 points) dydx=xy\frac{dy}{dx} = x - y: at (0,0)(0,0), slope =0= 0; at (1,0)(1,0), slope =1= 1; at (0,1)(0,1), slope =1= -1.
(b) (1 point) On y=xy = x, xy=0x - y = 0, so every segment along the line y=xy = x is horizontal (slope 00).

Related dot points

Sources & how we know this