Skip to main content
United StatesChemistrySyllabus dot point

How do we describe and calculate the composition of a mixture, as distinct from a pure compound?

Topic 1.4 Composition of Mixtures: distinguish pure substances from mixtures and use elemental analysis and mass relationships to determine the composition of a mixture.

A focused answer to AP Chemistry Topic 1.4, covering pure substances versus mixtures, elemental analysis, mass percent of a component, and using simultaneous mass relationships to find the make-up of a mixture, with full worked examples.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this topic is asking
  2. Pure substances versus mixtures
  3. Mass percent of a component
  4. Solving mixture problems with mass relationships
  5. Distinguishing the question types
  6. Try this

What this topic is asking

The College Board (Topic 1.4) wants you to tell a pure substance from a mixture, and to use mass relationships and elemental analysis to work out the composition of a mixture. Pure substances have a fixed composition and fixed properties; mixtures vary, and that variability is what these calculations quantify.

Pure substances versus mixtures

The decisive difference is variability. Carbon dioxide is always CO2\text{CO}_2 with the same melting point and density. A salt-water solution can be made stronger or weaker, and its freezing point changes with concentration, because it is a mixture. Mixtures can be homogeneous (uniform throughout, like a solution or a metal alloy) or heterogeneous (non-uniform, like sand in water), but in either case the components are not chemically bonded and can in principle be separated by physical means.

Mass percent of a component

A common way to describe a mixture's composition is the mass percent of each component:

mass percent of component=mass of componentmass of mixture×100%\text{mass percent of component} = \frac{\text{mass of component}}{\text{mass of mixture}} \times 100\%

For a solution, the related quantity is the concentration (for example molarity), but for solid mixtures and for AP-style stoichiometry problems, mass percent is the usual target. The mass percents of all components add to 100%100\%, which gives you a built-in check.

Solving mixture problems with mass relationships

Many AP mixture problems give you a total mass and one measured quantity (such as the total mass of a particular element, or the mass of a product formed) and ask for the make-up of the mixture.

The skill being tested is connecting an analytical measurement back to composition. Elemental analysis, the experimental technique behind it, burns or otherwise decomposes the sample and measures how much of one element it contained. Because each component contributes that element in a different, calculable proportion, the measured total constrains the mixture's make-up. If a problem gives you two independent measurements (for example total mass and total moles), you can even handle a mixture with two unknowns by solving two simultaneous equations.

Distinguishing the question types

Watch for the phrase that signals which calculation is wanted. "Percent composition of the compound" (Topic 1.3) asks about a single pure substance's formula. "Composition of the mixture" asks what fraction of the sample is each separate substance. They use the same mole and mass tools but answer different questions, so read carefully.

Try this

Q1. Classify each as a pure substance or mixture: (a) distilled water, (b) bronze, (c) oxygen gas. [3 points]

  • Cue. (a) pure substance (compound); (b) mixture (alloy); (c) pure substance (element).

Q2. A 2.002.00 g sample of a mixture is 30%30\% copper by mass. Calculate the mass of copper present. [1 point]

  • Cue. 0.30×2.00=0.600.30 \times 2.00 = 0.60 g of copper.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2022 (style)3 marksSection II (short FRQ). A 4.004.00 g mixture of sodium chloride (NaCl\text{NaCl}) and potassium chloride (KCl\text{KCl}) contains 2.002.00 g of chloride ion by mass. (a) Set up an expression for the total chloride mass in terms of the unknown masses. (b) Calculate the mass of NaCl\text{NaCl} in the mixture. Justify your method.
Show worked answer →

A 3-point quantitative FRQ on a two-component mixture.

(a) Set up (1 point): let xx = mass of NaCl and (4.00x)(4.00 - x) = mass of KCl. The chloride mass fraction of NaCl is 35.45/58.44=0.606635.45/58.44 = 0.6066 and of KCl is 35.45/74.55=0.475535.45/74.55 = 0.4755. So total chloride =0.6066x+0.4755(4.00x)=2.00= 0.6066x + 0.4755(4.00 - x) = 2.00.
(b) Solve (2 points): 0.6066x+1.9020.4755x=2.000.6066x + 1.902 - 0.4755x = 2.00, so 0.1311x=0.0980.1311x = 0.098, giving x=0.75x = 0.75 g of NaCl.

Markers reward defining one unknown with the total mass as a constraint, using each compound's chloride mass fraction, and solving the linear equation.

AP 2020 (style)1 marksSection I (multiple choice). Which of the following is a pure substance rather than a mixture? (A) air (B) seawater (C) carbon dioxide gas (D) brass. Justify your reasoning.
Show worked answer →

A 1-point conceptual MCQ. The answer is (C).

Carbon dioxide is a compound with a fixed formula CO2\text{CO}_2 and a single set of properties, so it is a pure substance. Air is a mixture of gases, seawater is a solution of water and dissolved salts, and brass is a solid mixture (alloy) of copper and zinc; their compositions can vary, which is the hallmark of a mixture.

Related dot points

Sources & how we know this