How do we draw a Lewis diagram that correctly shows the bonding and lone pairs in a molecule or ion?
Topic 2.5 Lewis Diagrams: draw Lewis diagrams for molecules and polyatomic ions, applying the octet rule and accounting for valence electrons, multiple bonds, and common exceptions.
A focused answer to AP Chemistry Topic 2.5, covering counting valence electrons, the octet rule, single and multiple bonds, lone pairs, polyatomic ions, and common octet exceptions, with a full worked drawing procedure.
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What this topic is asking
The College Board (Topic 2.5) wants you to draw Lewis diagrams for molecules and polyatomic ions: structures that show every bonding pair and lone pair of valence electrons. You apply the octet rule (most atoms want eight valence electrons around them, hydrogen wants two), use multiple bonds when needed, and recognize common exceptions. A correct Lewis diagram is the gateway to resonance, formal charge (Topic 2.6) and molecular shape (Topic 2.7).
What a Lewis diagram shows
The goal is a structure in which each atom (except hydrogen) is surrounded by eight valence electrons, the octet rule, reflecting the stability of a full outer shell. Hydrogen is the exception that wants only two (a full first shell).
The drawing procedure
For a polyatomic ion, draw the final structure in brackets with the overall charge written outside. Counting electrons correctly is the step students most often get wrong, so add for negative charge and subtract for positive before you start placing electrons.
Multiple bonds and exceptions
When there are not enough electrons to give the central atom an octet using single bonds, convert outer-atom lone pairs into double or triple bonds. Carbon dioxide () and nitrogen () are examples.
A few species break the octet rule, and the College Board expects you to recognize them:
- Incomplete octets: boron and beryllium often have fewer than eight electrons (for example has six around boron).
- Expanded octets: atoms in period 3 and beyond (such as sulfur or phosphorus) can hold more than eight electrons (for example ).
- Odd-electron species (radicals): molecules with an odd total, such as , cannot give every atom a full octet.
A good Lewis diagram is the foundation for the rest of the unit. Once you have the bonding and lone pairs right, formal charge (Topic 2.6) tells you which of several possible structures is best, and the count of bonding regions and lone pairs on the central atom feeds straight into VSEPR (Topic 2.7) to predict the shape. Because so much downstream reasoning depends on it, it is worth checking your electron total twice, especially the charge adjustment for ions.
Try this
Q1. State the total number of valence electrons to use when drawing the Lewis diagram of the ammonium ion, . [1 point]
- Cue. N (5) 4 H () 1 (for the charge) electrons.
Q2. Identify the octet-rule exception shown by boron trifluoride, . [1 point]
- Cue. An incomplete octet; boron has only six valence electrons around it.
Exam-style practice questions
Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
AP 2023 (style)3 marksSection II (short FRQ). (a) Draw the Lewis diagram of the carbonate ion, . (b) State the total number of valence electrons you used. (c) Explain how the charge is accounted for in the electron count.Show worked answer →
A 3-point FRQ on drawing a polyatomic ion.
(a) Lewis diagram (1 point): carbon in the center bonded to three oxygens, with one C=O double bond and two C-O single bonds; each singly bonded O carries three lone pairs and the double-bonded O carries two; the whole structure is enclosed in brackets with a charge.
(b) Electron count (1 point): C contributes 4, each O contributes 6 (), and the charge adds 2, giving valence electrons (12 pairs).
(c) Explain (1 point): the ion has gained two electrons relative to the neutral atoms, so two extra electrons are added to the total valence count before distributing them.
Markers reward a valid octet-satisfying structure, the correct total of 24 electrons, and adding electrons for the negative charge.
AP 2021 (style)1 marksSection I (multiple choice). How many lone pairs are on the central nitrogen atom in the ammonia molecule, ? (A) 0 (B) 1 (C) 2 (D) 3. Justify your choice.Show worked answer →
A 1-point conceptual MCQ. The answer is (B).
Nitrogen has 5 valence electrons. In it forms three N-H single bonds, using three of its electrons (one per bond), which leaves two electrons as one lone pair. So the central nitrogen has exactly one lone pair, which is why is trigonal pyramidal rather than trigonal planar.
Related dot points
- Topic 2.6 Resonance and Formal Charge: draw resonance structures and use formal charge to select the most reasonable Lewis diagram, and explain how resonance describes delocalised bonding.
A focused answer to AP Chemistry Topic 2.6, covering resonance structures, the resonance hybrid, calculating formal charge, and using formal charge to choose the best Lewis diagram, with full worked examples.
- Topic 2.7 VSEPR and Bond Hybridization: use VSEPR theory to predict molecular geometry and bond angles, assign the hybridization of the central atom, and relate geometry to molecular polarity.
A focused answer to AP Chemistry Topic 2.7, covering VSEPR theory, electron-domain geometry, molecular shapes and bond angles, the effect of lone pairs, hybridization of the central atom, and how shape determines molecular polarity, with full worked examples.
- Topic 2.1 Types of Chemical Bonds: classify bonds as ionic, covalent (polar or nonpolar), or metallic using electronegativity and the elements involved, and relate bond type to properties.
A focused answer to AP Chemistry Topic 2.1, covering ionic, covalent and metallic bonding, electronegativity difference, bond polarity, and how bond type explains the macroscopic properties of a substance, with full worked examples.
- Topic 2.2 Intramolecular Force and Potential Energy: interpret a potential-energy versus internuclear-distance curve to define bond length and bond energy, and explain how bond order, atomic size and charge affect bond strength.
A focused answer to AP Chemistry Topic 2.2, covering the potential-energy versus internuclear-distance curve, equilibrium bond length, bond energy, and how bond order, atomic radius and ionic charge control bond strength, with full worked reasoning.
- Topic 1.8 Valence Electrons and Ionic Compounds: relate the number of valence electrons to an element's group and reactivity, and predict the ions main-group elements form and the formulas of the ionic compounds they make.
A focused answer to AP Chemistry Topic 1.8, covering valence electrons, the link between group number and reactivity, the ions main-group elements form, and writing ionic-compound formulas, with full worked examples.
Sources & how we know this
- AP Chemistry Course and Exam Description — College Board (2020)