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How does a titration curve reveal the equivalence point, the pH at key points, and the pKa of a weak acid?

Topic 8.5 Acid-Base Titrations: interpret titration curves to find the equivalence point and pH at key points, and use the half-equivalence point to find pKa for a weak acid.

A focused answer to AP Chemistry Topic 8.5, covering titration curves for strong and weak acids and bases, the equivalence point, the half-equivalence point where pH equals pKa, the buffer region, and choosing an indicator, with full worked examples.

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  1. What this topic is asking
  2. Reading the titration curve
  3. pH at the equivalence point
  4. The buffer region and the half-equivalence point
  5. Choosing an indicator
  6. Try this

What this topic is asking

The College Board (Topic 8.5) wants you to interpret titration curves to find the equivalence point and the pH at key points, and to use the half-equivalence point to find the pKa of a weak acid. This builds on the basic titration of Unit 4 with the pH detail that the acids-and-bases unit demands.

Reading the titration curve

The equivalence point is found from the volume at the midpoint of the steep jump. The shape of the curve depends on the strengths of the acid and base: strong-strong titrations have a long, sharp jump centered at pH 7; titrations involving a weak species have a shorter jump centered above or below 7.

pH at the equivalence point

So the equivalence point is not always at pH 7; only the strong-strong case is neutral. For a weak acid titrated with strong base, the solution at equivalence is a solution of the conjugate base Aβˆ’\text{A}^-, which makes it basic. This is a frequent exam discriminator.

The buffer region and the half-equivalence point

Before the equivalence point in a weak-acid titration, both the weak acid and its conjugate base are present, so the solution is a buffer and the curve rises only gently (the buffer region). At the half-equivalence point, exactly half the weak acid has been converted to conjugate base, so [HA]=[Aβˆ’][\text{HA}] = [\text{A}^-]. By the Henderson-Hasselbalch equation (Topic 8.7), pH=pKa\text{pH} = \text{p}K_a when these are equal, so the pH at the half-equivalence point directly gives the pKa\text{p}K_a of the acid. Reading pKa\text{p}K_a off the curve this way is a classic AP task.

Choosing an indicator

An indicator is a weak acid or base whose two forms have different colors; it changes color over a small pH range near its own pKa\text{p}K_a. You choose an indicator whose color-change range brackets the pH at the equivalence point of the titration, so the endpoint (the observed color change) closely matches the equivalence point.

Try this

Q1. A strong acid is titrated with a strong base. State the pH at the equivalence point. [1 point]

  • Cue. pH =7= 7 (the salt is neutral).

Q2. At the half-equivalence point of a weak-acid titration the pH is 5.0. State the pKa\text{p}K_a of the acid. [1 point]

  • Cue. pKa=5.0\text{p}K_a = 5.0, because [HA]=[Aβˆ’][\text{HA}] = [\text{A}^-] there.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2023 (style)4 marksSection II (long FRQ, part). A weak acid HA is titrated with NaOH. The titration curve shows a gradual rise, a steep jump at 25.025.0 mL of NaOH, and a plateau before that. At 12.512.5 mL of NaOH the pH is 4.744.74. (a) Identify the volume of the equivalence point. (b) Determine the pKa\text{p}K_a of the acid and justify. (c) State whether the pH at the equivalence point is above, below or equal to 7, and justify. (d) Explain why the region around 12.512.5 mL is a buffer region.
Show worked answer β†’

A 4-point conceptual FRQ on a weak-acid titration curve.

(a) Equivalence point (1 point): the steep jump occurs at 25.025.0 mL, so the equivalence point is at 25.025.0 mL of NaOH.
(b) pKa (1 point): the half-equivalence point is at half the equivalence volume, 12.512.5 mL, where pH =pKa= \text{p}K_a; so pKa=4.74\text{p}K_a = 4.74.
(c) Equivalence pH (1 point): at the equivalence point the solution contains the conjugate base Aβˆ’\text{A}^-, a weak base, so the pH is above 7 (basic).
(d) Buffer region (1 point): near 12.512.5 mL the solution contains comparable amounts of HA and Aβˆ’\text{A}^-, so it is a buffer and the pH changes only slowly with added base.

Markers reward the equivalence volume, pKa\text{p}K_a from the half-equivalence point, the basic equivalence pH, and the buffer-region reasoning.

AP 2021 (style)1 marksSection I (multiple choice). At the half-equivalence point of a weak acid titrated with strong base, (A) pH = 7 (B) pH = pKa\text{p}K_a (C) all the acid has reacted (D) pH = 14. Justify your choice.
Show worked answer β†’

A 1-point conceptual MCQ. The answer is (B).

At the half-equivalence point, half the weak acid has been converted to its conjugate base, so [HA]=[Aβˆ’][\text{HA}] = [\text{A}^-] and the Henderson-Hasselbalch equation gives pH =pKa= \text{p}K_a. The trap is (A): pH = 7 is the equivalence point only for a strong-acid, strong-base titration.

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