How does a titration curve reveal the equivalence point, the pH at key points, and the pKa of a weak acid?
Topic 8.5 Acid-Base Titrations: interpret titration curves to find the equivalence point and pH at key points, and use the half-equivalence point to find pKa for a weak acid.
A focused answer to AP Chemistry Topic 8.5, covering titration curves for strong and weak acids and bases, the equivalence point, the half-equivalence point where pH equals pKa, the buffer region, and choosing an indicator, with full worked examples.
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What this topic is asking
The College Board (Topic 8.5) wants you to interpret titration curves to find the equivalence point and the pH at key points, and to use the half-equivalence point to find the pKa of a weak acid. This builds on the basic titration of Unit 4 with the pH detail that the acids-and-bases unit demands.
Reading the titration curve
The equivalence point is found from the volume at the midpoint of the steep jump. The shape of the curve depends on the strengths of the acid and base: strong-strong titrations have a long, sharp jump centered at pH 7; titrations involving a weak species have a shorter jump centered above or below 7.
pH at the equivalence point
So the equivalence point is not always at pH 7; only the strong-strong case is neutral. For a weak acid titrated with strong base, the solution at equivalence is a solution of the conjugate base , which makes it basic. This is a frequent exam discriminator.
The buffer region and the half-equivalence point
Before the equivalence point in a weak-acid titration, both the weak acid and its conjugate base are present, so the solution is a buffer and the curve rises only gently (the buffer region). At the half-equivalence point, exactly half the weak acid has been converted to conjugate base, so . By the Henderson-Hasselbalch equation (Topic 8.7), when these are equal, so the pH at the half-equivalence point directly gives the of the acid. Reading off the curve this way is a classic AP task.
Choosing an indicator
An indicator is a weak acid or base whose two forms have different colors; it changes color over a small pH range near its own . You choose an indicator whose color-change range brackets the pH at the equivalence point of the titration, so the endpoint (the observed color change) closely matches the equivalence point.
Try this
Q1. A strong acid is titrated with a strong base. State the pH at the equivalence point. [1 point]
- Cue. pH (the salt is neutral).
Q2. At the half-equivalence point of a weak-acid titration the pH is 5.0. State the of the acid. [1 point]
- Cue. , because there.
Exam-style practice questions
Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
AP 2023 (style)4 marksSection II (long FRQ, part). A weak acid HA is titrated with NaOH. The titration curve shows a gradual rise, a steep jump at mL of NaOH, and a plateau before that. At mL of NaOH the pH is . (a) Identify the volume of the equivalence point. (b) Determine the of the acid and justify. (c) State whether the pH at the equivalence point is above, below or equal to 7, and justify. (d) Explain why the region around mL is a buffer region.Show worked answer β
A 4-point conceptual FRQ on a weak-acid titration curve.
(a) Equivalence point (1 point): the steep jump occurs at mL, so the equivalence point is at mL of NaOH.
(b) pKa (1 point): the half-equivalence point is at half the equivalence volume, mL, where pH ; so .
(c) Equivalence pH (1 point): at the equivalence point the solution contains the conjugate base , a weak base, so the pH is above 7 (basic).
(d) Buffer region (1 point): near mL the solution contains comparable amounts of HA and , so it is a buffer and the pH changes only slowly with added base.
Markers reward the equivalence volume, from the half-equivalence point, the basic equivalence pH, and the buffer-region reasoning.
AP 2021 (style)1 marksSection I (multiple choice). At the half-equivalence point of a weak acid titrated with strong base, (A) pH = 7 (B) pH = (C) all the acid has reacted (D) pH = 14. Justify your choice.Show worked answer β
A 1-point conceptual MCQ. The answer is (B).
At the half-equivalence point, half the weak acid has been converted to its conjugate base, so and the Henderson-Hasselbalch equation gives pH . The trap is (A): pH = 7 is the equivalence point only for a strong-acid, strong-base titration.
Related dot points
- Topic 8.4 Acid-Base Reactions and Buffers: predict the products of acid-base reactions, identify the salts formed, and explain how a buffer made from a weak acid and its conjugate base resists pH change.
A focused answer to AP Chemistry Topic 8.4, covering neutralisation reactions and the salts produced, the composition of a buffer, and how a buffer of a weak acid and its conjugate base resists pH change, with full worked examples.
- Topic 8.7 pH and pKa: use the Henderson-Hasselbalch equation to relate the pH of a buffer to the pKa and the ratio of conjugate base to weak acid, and explain buffer capacity.
A focused answer to AP Chemistry Topic 8.7, covering the Henderson-Hasselbalch equation, how the pH of a buffer relates to the pKa and the conjugate-base-to-acid ratio, how to design a buffer, and buffer capacity, with full worked examples.
- Topic 8.3 Weak Acid and Base Equilibria: use Ka or Kb with an ICE table to calculate the pH and percent ionization of a weak acid or base, and relate Ka, Kb and Kw.
A focused answer to AP Chemistry Topic 8.3, covering the acid and base ionization constants Ka and Kb, ICE-table calculations of pH and percent ionization for weak acids and bases, and the relationship Ka times Kb equals Kw, with full worked examples.
- Topic 4.6 Introduction to Titration: use titration data and reaction stoichiometry to determine the concentration of an unknown solution, distinguishing the equivalence point from the endpoint.
A focused answer to AP Chemistry Topic 4.6, covering the titration method, the equivalence point versus the endpoint, and how to use moles, the reaction mole ratio and volume to calculate an unknown concentration, with full worked examples.
- Topic 8.2 pH and pOH of Strong Acids and Bases: calculate pH and pOH from concentration for strong acids and bases, using the autoionisation of water and the relationship pH plus pOH equals 14 at 25 degrees Celsius.
A focused answer to AP Chemistry Topic 8.2, covering the definitions of pH and pOH, the autoionisation of water and Kw, the relationship pH plus pOH equals 14 at 25 degrees Celsius, and calculating pH for strong acids and bases, with full worked examples.
Sources & how we know this
- AP Chemistry Course and Exam Description β College Board (2020)