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How do the degree and leading coefficient of a polynomial determine what its graph does at the far left and far right?

Topic 1.6 Polynomial Functions and End Behavior: determine the end behavior of a polynomial from its degree and leading term, and express that behavior using limit notation.

A focused answer to AP Precalculus Topic 1.6, covering how the degree and leading coefficient control the end behavior of a polynomial, the four end-behavior cases, and writing end behavior in limit notation.

Generated by Claude Opus 4.89 min answer

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  1. What this topic is asking
  2. The leading term dominates
  3. The four cases
  4. Limit notation
  5. Why end behavior matters
  6. Try this

What this topic is asking

The College Board (Topic 1.6) wants you to determine the end behavior of a polynomial: what the output does as xx runs off to βˆ’βˆž-\infty and +∞+\infty. End behavior is controlled entirely by the leading term, that is, by the polynomial's degree (even or odd) and its leading coefficient (positive or negative). You must also write the behavior using limit notation.

The leading term dominates

This is why you can read end behavior at a glance: ignore everything but the highest-power term.

The four cases

A quick mnemonic: even degree gives matching ends (both up or both down, like a parabola), odd degree gives opposite ends (like a line or cubic), and the leading coefficient's sign decides which way.

Limit notation

The exam expects end behavior written with limits. The statement lim⁑xβ†’+∞p(x)=+∞\lim_{x \to +\infty} p(x) = +\infty reads "as xx increases without bound, p(x)p(x) increases without bound". You give one limit for each end. This notation reappears throughout the course, including for rational functions in Topics 1.7 and 1.9.

Why end behavior matters

End behavior is more than a graphing detail; it constrains what a polynomial can do. An odd-degree polynomial runs from one infinity to the opposite one, so by continuity it must cross the xx-axis at least once, guaranteeing a real zero. An even-degree polynomial has both ends pointing the same way, so it has a global minimum (if the ends go up) or a global maximum (if they go down). These structural facts let you reason about zeros and extrema before doing any algebra.

A useful clarification is that the leading coefficient's magnitude does not affect the direction of the ends, only the steepness. Whether the leading coefficient is 22 or 200200, an even-degree positive-leading polynomial still has both ends going to +∞+\infty; the larger coefficient simply makes the graph climb faster. So when classifying end behavior, only the sign of the leading coefficient and the parity of the degree matter, which is what makes the four-case rule so quick to apply on the no-calculator section.

Try this

Q1. State the end behavior of p(x)=7x6βˆ’x3+2p(x) = 7x^6 - x^3 + 2 in words. [1 point]

  • Cue. Even degree, positive leading coefficient: both ends rise to +∞+\infty.

Q2. Write lim⁑xβ†’βˆ’βˆžq(x)\lim_{x \to -\infty} q(x) for q(x)=βˆ’x5+4xq(x) = -x^5 + 4x. [1 point]

  • Cue. Odd degree, negative leading coefficient: the left end rises, so lim⁑xβ†’βˆ’βˆžq(x)=+∞\lim_{x \to -\infty} q(x) = +\infty.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2023 (style)1 marksSection I, Part A (multiple choice, no calculator). What is the end behavior of p(x)=βˆ’3x4+2x2βˆ’7p(x) = -3x^4 + 2x^2 - 7? (A) As xβ†’Β±βˆžx \to \pm\infty, p(x)β†’+∞p(x) \to +\infty (B) As xβ†’Β±βˆžx \to \pm\infty, p(x)β†’βˆ’βˆžp(x) \to -\infty (C) As xβ†’βˆ’βˆžx \to -\infty, p(x)β†’+∞p(x) \to +\infty and as xβ†’+∞x \to +\infty, p(x)β†’βˆ’βˆžp(x) \to -\infty (D) As xβ†’βˆ’βˆžx \to -\infty, p(x)β†’βˆ’βˆžp(x) \to -\infty and as xβ†’+∞x \to +\infty, p(x)β†’+∞p(x) \to +\infty
Show worked answer β†’

The correct answer is (B), both ends go to βˆ’βˆž-\infty.

End behavior depends only on the leading term βˆ’3x4-3x^4. The degree 44 is even, so both ends behave the same way; the leading coefficient βˆ’3-3 is negative, so both ends go to βˆ’βˆž-\infty. Hence as xβ†’Β±βˆžx \to \pm\infty, p(x)β†’βˆ’βˆžp(x) \to -\infty.

AP 2024 (style)3 marksSection II (free response, calculator allowed). A polynomial ff has odd degree and a positive leading coefficient. (a) Write the end behavior of ff using limit notation. (b) Explain why a polynomial of odd degree must have at least one real zero.
Show worked answer β†’

A 3-point question on end behavior and real zeros.

(a) Limit notation (1 point each side): lim⁑xβ†’βˆ’βˆžf(x)=βˆ’βˆž\lim_{x \to -\infty} f(x) = -\infty and lim⁑xβ†’+∞f(x)=+∞\lim_{x \to +\infty} f(x) = +\infty, because odd degree with a positive leading coefficient sends the left end down and the right end up.
(b) At least one real zero (1 point): the graph runs from βˆ’βˆž-\infty at the far left to +∞+\infty at the far right, so by continuity it must cross the xx-axis somewhere, giving at least one real zero.

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