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How do arithmetic and geometric sequences differ in the way their terms change?

Topic 2.1 Change in Arithmetic and Geometric Sequences: define arithmetic sequences by a constant common difference and geometric sequences by a constant common ratio, and write their explicit and recursive forms.

A focused answer to AP Precalculus Topic 2.1, covering arithmetic sequences with a common difference, geometric sequences with a common ratio, and their explicit and recursive formulas.

Generated by Claude Opus 4.89 min answer

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  1. What this topic is asking
  2. Arithmetic sequences
  3. Geometric sequences
  4. Telling them apart
  5. Why the indexing matters
  6. Try this

What this topic is asking

The College Board (Topic 2.1) wants you to distinguish two kinds of sequence by how their terms change. An arithmetic sequence adds a constant common difference dd each step; a geometric sequence multiplies by a constant common ratio rr each step. You must write both the explicit formula (the nnth term directly) and the recursive formula (each term from the previous one).

Arithmetic sequences

The explicit form is a linear expression in nn (slope dd, intercept a1βˆ’da_1 - d), which is why arithmetic sequences are the discrete cousins of linear functions: equal steps in position produce equal changes in value.

Geometric sequences

The explicit form is an exponential expression in nn, so geometric sequences are the discrete cousins of exponential functions: equal steps in position produce equal ratios, not equal differences.

Telling them apart

Given a list, test the change: subtract consecutive terms (constant difference means arithmetic) and divide consecutive terms (constant ratio means geometric). A sequence can be neither. The distinction mirrors the difference-versus-ratio tests for functions in Topics 1.3 and 2.2.

Why the indexing matters

The most common slip is the exponent and the multiplier of (nβˆ’1)(n - 1) rather than nn. Both explicit forms count steps from the first term, and there are nβˆ’1n - 1 steps to reach the nnth term, which is why arithmetic uses (nβˆ’1)d(n - 1)d and geometric uses r nβˆ’1r^{\,n-1}. Anchoring on "how many steps from term 11 to term nn" prevents the off-by-one errors that otherwise creep in, and it also explains why g1g_1 has the exponent r0=1r^0 = 1, leaving the first term unchanged.

A deeper connection worth noting is that arithmetic and geometric sequences are the discrete templates for the two function families of this unit. Plot an arithmetic sequence and the points lie on a line; plot a geometric sequence and they lie on an exponential curve. This is exactly why Topic 2.2 pairs linear with exponential change: the sequence behavior you classify here becomes the continuous-function behavior you model next, and recognizing the bridge makes the whole unit cohere.

Try this

Q1. Write the recursive formula for the geometric sequence 2,6,18,54,…2, 6, 18, 54, \dots. [1 point]

  • Cue. Common ratio r=3r = 3, so gn=3gnβˆ’1g_n = 3 g_{n-1} with g1=2g_1 = 2.

Q2. Find the 1010th term of the geometric sequence with g1=4g_1 = 4 and r=2r = 2. [1 point]

  • Cue. g10=4β‹…29=4β‹…512=2048g_{10} = 4 \cdot 2^{9} = 4 \cdot 512 = 2048.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2023 (style)1 marksSection I, Part A (multiple choice, no calculator). The sequence 3,6,12,24,…3, 6, 12, 24, \dots is which type, and what is its defining constant? (A) Arithmetic with common difference 33 (B) Geometric with common ratio 22 (C) Arithmetic with common difference 66 (D) Geometric with common ratio 33
Show worked answer β†’

The correct answer is (B), geometric with common ratio 22.

Each term is the previous term times 22: 6=3β‹…26 = 3 \cdot 2, 12=6β‹…212 = 6 \cdot 2, 24=12β‹…224 = 12 \cdot 2. A constant ratio means the sequence is geometric, and the common ratio is r=2r = 2. The differences (3,6,123, 6, 12) are not constant, so it is not arithmetic.

AP 2024 (style)3 marksSection II (free response, calculator allowed). An arithmetic sequence has first term a1=7a_1 = 7 and common difference d=4d = 4. (a) Write an explicit formula for the nnth term ana_n. (b) Find the 2020th term.
Show worked answer β†’

A 3-point question on the explicit form of an arithmetic sequence.

(a) Explicit formula (1 point): an=a1+(nβˆ’1)d=7+(nβˆ’1)(4)=4n+3a_n = a_1 + (n - 1)d = 7 + (n - 1)(4) = 4n + 3.
(b) Twentieth term (2 points): a20=4(20)+3=80+3=83a_{20} = 4(20) + 3 = 80 + 3 = 83. (Equivalently 7+19β‹…4=7+76=837 + 19 \cdot 4 = 7 + 76 = 83.)

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