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How do you graph an exponential function and identify its y-intercept, horizontal asymptote, domain, range, and growth or decay behavior?

Graph exponential functions and identify key features including the y-intercept, the horizontal asymptote, domain, range, and whether the function is increasing or decreasing (MA.912.F.1.3, MA.912.AR.5.6).

A B.E.S.T. Algebra 1 EOC answer on graphing exponentials (MA.912.F.1, AR.5), the y-intercept at the initial value, the horizontal asymptote at y = 0, the domain and range, and growth versus decay shape.

Generated by Claude Opus 4.810 min answer

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  1. What this topic is asking
  2. The shape of an exponential
  3. Key features
  4. How the B.E.S.T. EOC examines this topic
  5. Why the y-intercept is always a and the asymptote is y = 0
  6. Distinguishing growth from decay on sight
  7. Try this

What this topic is asking

MA.912.F.1 and AR.5 ask you to graph an exponential function f(x)=abxf(x) = a \cdot b^x and read its key features: the yy-intercept, the horizontal asymptote, the domain and range, and whether it shows growth or decay. Because the B.E.S.T. Algebra 1 EOC calculator does not graph, you build the shape from the equation and a few points.

The shape of an exponential

An exponential f(x)=abxf(x) = a \cdot b^x has a distinctive curve, not a straight line and not a parabola. It hugs a horizontal asymptote on one end and shoots off steeply on the other. The base decides which way:

  • b>1b > 1 (growth): low and flat on the left, rising ever more steeply to the right.
  • 0<b<10 < b < 1 (decay): high on the left, falling and flattening toward the asymptote on the right.

Key features

  • yy-intercept: f(0)=ab0=af(0) = a \cdot b^0 = a. The intercept is always the initial value aa.
  • Horizontal asymptote: y=0y = 0 for the basic form. The graph gets arbitrarily close to the xx-axis but never reaches it.
  • Domain: all real numbers (you can raise bb to any power).
  • Range: y>0y > 0 (the output is always positive when a>0a > 0).

How the B.E.S.T. EOC examines this topic

  • Multiple choice and editing task. Identify the yy-intercept, the asymptote, or growth versus decay.
  • GRID and matching. Match an equation to its curve, or plot the intercept.
  • Multiselect. Select all true statements about an exponential graph.

A clarifying idea: an exponential graph's end behavior is its signature, one end flattens against the asymptote, the other end runs away to infinity. That asymmetry is how you tell an exponential from a line (straight) or a parabola (symmetric, turns around).

Why the y-intercept is always a and the asymptote is y = 0

Both features fall out of the form f(x)=abxf(x) = a \cdot b^x. At x=0x = 0, any positive base satisfies b0=1b^0 = 1, so f(0)=a1=af(0) = a \cdot 1 = a; the starting coefficient is the yy-intercept, no computation needed. For the asymptote, consider the decay direction: as xx grows for 0<b<10 < b < 1 (or as xx goes very negative for b>1b > 1), bxb^x becomes a tinier and tinier positive number, halving or shrinking without limit, but it can never actually be zero because a positive base raised to any power stays positive. So abxa \cdot b^x approaches 00 from above without ever reaching it, which is exactly what a horizontal asymptote at y=0y = 0 means. This also explains the range y>0y > 0: the output is a positive coefficient times a positive power, never zero or negative.

Distinguishing growth from decay on sight

On the EOC you often must label a graph or equation as growth or decay quickly. From the equation, look at the base: above 11 is growth, between 00 and 11 is decay. From a graph, look at the direction: rising left to right is growth, falling left to right is decay (with the flat asymptote end on the right for decay, on the left for growth). From a table, check the multiplier between consecutive equally spaced outputs: a factor above 11 grows, below 11 decays. All three views agree because they describe the same base, so pick whichever representation the item gives you.

Try this

Q1. What is the yy-intercept of f(x)=72xf(x) = 7 \cdot 2^x? [1 point]

  • Cue. f(0)=7f(0) = 7, so (0,7)(0, 7).

Q2. Does f(x)=6(0.4)xf(x) = 6 \cdot (0.4)^x grow or decay? [1 point]

  • Cue. Base 0.4<10.4 < 1, so it decays.

Exam-style practice questions

Practice questions written in the style of FLDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

B.E.S.T. (style)1 marksMultiple choice. What is the yy-intercept of f(x)=32xf(x) = 3 \cdot 2^{x}? (A) (0,3)(0, 3) (B) (0,2)(0, 2) (C) (0,6)(0, 6) (D) (0,1)(0, 1)
Show worked answer →

The correct answer is (A).

The yy-intercept is f(0)f(0): f(0)=320=31=3f(0) = 3 \cdot 2^0 = 3 \cdot 1 = 3, so the point is (0,3)(0, 3). For f(x)=abxf(x) = a \cdot b^x, the yy-intercept is always the initial value aa, because b0=1b^0 = 1. Choice (B) confuses the base with the intercept; the base 22 is the growth factor, not the starting value.

B.E.S.T. (style)2 marksFor f(x)=5(12)xf(x) = 5 \cdot \left(\frac{1}{2}\right)^{x}, state whether it represents growth or decay, give the yy-intercept, and give the horizontal asymptote.
Show worked answer →

It is decay; the yy-intercept is (0,5)(0, 5); the horizontal asymptote is y=0y = 0.

The base 12\frac{1}{2} is between 0 and 1, so the function decays (decreases as xx increases). The yy-intercept is f(0)=51=5f(0) = 5 \cdot 1 = 5. As xx grows, the output approaches but never reaches 00, so the horizontal asymptote is y=0y = 0 (the xx-axis). Markers reward identifying decay from the base, the intercept from aa, and the asymptote at y=0y = 0.

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