How do you use the quadratic formula to solve any quadratic, and what does the discriminant tell you about the number of real solutions?
Solve quadratic equations using the quadratic formula from the reference sheet, and use the discriminant to determine the number and nature of the real solutions (MA.912.AR.3.4, MA.912.AR.3.5).
A B.E.S.T. Algebra 1 EOC answer on the quadratic formula from the reference sheet (MA.912.AR.3), substituting correctly, simplest radical form, and using the discriminant to count the real solutions.
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What this topic is asking
The quadratic formula is the universal solver in MA.912.AR.3: it works on every quadratic, factorable or not, and it is printed on the B.E.S.T. reference sheet, so the credit is for substituting correctly and simplifying. The discriminant (the part under the radical) tells you the number of real solutions without fully solving, a frequent quick item.
Using the quadratic formula
Set the equation to , identify , , , and substitute.
The two error-prone spots are the sign of and the sign of . When is negative, becomes positive, which increases the discriminant.
The discriminant: counting real solutions
The discriminant is , the expression under the radical. Its sign tells you how many real solutions exist, equivalently how many times the parabola meets the -axis.
- : two real solutions (crosses the -axis twice).
- : one real solution, a double root (touches the -axis).
- : no real solutions (misses the -axis).
For : , so there are no real solutions. Computing just the discriminant is far faster than solving when the question only asks how many.
How the B.E.S.T. EOC examines this topic
- Equation editor. Solve with the formula and enter solutions in simplest radical form.
- Multiple choice. Count real solutions from the discriminant, with sign-error distractors.
- Inline choice. State the number of solutions and whether the parabola crosses the axis.
A clarifying idea: the discriminant lives inside the formula, so the formula and the count are the same computation. If the discriminant is negative, the square root of a negative number has no real value, which is exactly why there are no real solutions.
Why the quadratic formula always works
The quadratic formula is derived by completing the square on the general equation , which is why it solves every quadratic, including those that do not factor with integers. That universality makes it the safe fallback: if a quick check shows no integer pair multiplies to and adds to , go straight to the formula rather than hunting for a factorization that does not exist. The trade-off is more arithmetic, so reserve it for quadratics that resist factoring, and keep factoring or square roots for the cases where they are faster. Because the formula comes from completing the square, the at its heart is also the axis of symmetry, tying the solver to the graph.
Connecting the discriminant to the graph
The discriminant has a clean graphical meaning. Because the solutions are the -intercepts of , a positive discriminant means the parabola crosses the -axis at two distinct points, a zero discriminant means it touches the axis at exactly one point (the vertex sits on the axis), and a negative discriminant means the parabola never reaches the axis, sitting entirely above or below it. Reading the discriminant therefore tells you the shape of the picture, not just a count, which is useful on inline-choice items that ask both how many solutions there are and whether the graph crosses the axis.
Try this
Q1. Solve in simplest radical form. [2 points]
- Cue. .
Q2. How many real solutions does have? [1 point]
- Cue. , so one (double) solution.
Exam-style practice questions
Practice questions written in the style of FLDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
B.E.S.T. (style)2 marksEquation editor. Solve using the quadratic formula. Give the solutions in simplest radical form.Show worked answer →
The solutions are .
The reference sheet gives . With , , : . Simplify : . The sign error on (with negative, ) is the most common slip.
B.E.S.T. (style)1 marksMultiple choice. How many real solutions does have? (A) none (B) one (C) two (D) infinitely manyShow worked answer →
The correct answer is (A).
The discriminant is . A negative discriminant means no real solutions (the parabola does not cross the -axis). A positive discriminant gives two real solutions, and a zero discriminant gives one. Computing the discriminant is faster than solving when only the count is asked.
Related dot points
- Solve quadratic equations in one variable by factoring and applying the zero-product property, and interpret the solutions as the zeros of the related function (MA.912.AR.3.4).
A B.E.S.T. Algebra 1 EOC answer on solving quadratics by factoring (MA.912.AR.3), setting the equation to zero, the zero-product property, and reading solutions as the x-intercepts of the parabola.
- Solve quadratic equations by taking square roots and by completing the square, including writing the equation in vertex form (MA.912.AR.3.4, MA.912.AR.3.8).
A B.E.S.T. Algebra 1 EOC answer on the square-root property and completing the square (MA.912.AR.3), when each applies, the plus-or-minus, simplest radical form, and producing vertex form.
- Model real-world situations with quadratic functions and solve, interpreting the vertex as a maximum or minimum and the zeros as start or end points, and rejecting solutions that do not fit the context (MA.912.AR.3.6, MA.912.AR.3.9).
A B.E.S.T. Algebra 1 EOC answer on quadratic applications (MA.912.AR.3), projectile motion and area models, using the vertex for the maximum or minimum and the zeros for landing or break-even, and rejecting impossible solutions.
- Graph a quadratic function and identify and interpret its key features: vertex, axis of symmetry, x- and y-intercepts, direction of opening, and maximum or minimum value (MA.912.AR.3.7, MA.912.F.1.3).
A B.E.S.T. Algebra 1 EOC answer on graphing parabolas (MA.912.AR.3), finding the vertex with x = -b/2a, the axis of symmetry, intercepts, direction of opening, and the maximum or minimum value.
- Apply the laws of exponents to numerical and algebraic expressions with integer and rational exponents, and rewrite radical expressions using rational exponents (MA.912.NSO.1).
A B.E.S.T. Algebra 1 EOC answer on the laws of exponents (MA.912.NSO.1), simplifying with negative and zero exponents, converting between radical and rational-exponent form, and the equation-editor entry the test rewards.
Sources & how we know this
- B.E.S.T. Algebra 1 EOC Reference Sheet — Florida Department of Education (2024)
- B.E.S.T. Mathematics Standards — Florida Department of Education (2020)