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How do you write a function that models a relationship between two quantities from a description, a table, or a graph?

Write a function that describes a relationship between two quantities, building a linear or exponential model from a context (LA A1: F-BF.A.1, F-LE.A.2).

A Louisiana LEAP 2025 Algebra I answer on building functions (LA A1: F-BF.A.1, F-LE.A.2): writing a linear or exponential rule from a context, table, or graph, and identifying the starting value and rate.

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  1. What this topic is asking
  2. Linear: constant amount added
  3. Exponential: constant factor multiplied
  4. Reading the type from a table
  5. How LEAP examines this topic
  6. Why the kind of change determines the model
  7. Try this

What this topic is asking

Standards A1: F-BF.A.1 and F-LE.A.2 ask you to build a function that models a relationship, writing a linear or exponential rule from a description, a table, or a graph. On LEAP 2025 these are Type I and Type III items. The central decision is linear versus exponential: a constant added each step is linear, a constant multiplier each step is exponential.

Linear: constant amount added

A linear model adds the same amount each step. The starting value is the constant term; the per-step change is the slope.

Exponential: constant factor multiplied

An exponential model multiplies by the same factor each step. The starting value is aa; the factor is bb (greater than 11 for growth, between 00 and 11 for decay).

A growth of rr (as a decimal) gives factor 1+r1 + r; a decay of rr gives 1r1 - r. These exponential model forms are not on the reference sheet.

Reading the type from a table

In a table with equally spaced inputs, look at the outputs: if consecutive outputs have a common difference (subtract to a constant), it is linear; if they have a common ratio (divide to a constant), it is exponential.

How LEAP examines this topic

  • Equation response. Write the function from a described situation.
  • Multiple choice. Pick the rule that matches a context, with linear-versus-exponential distractors.
  • Type III modeling. Build the model, then use it to predict a value.

A clarifying idea: the word that decides the model is the kind of change. "Adds 1212 a day" (same amount) is linear; "grows 12 percent a year" (same factor) is exponential. Watch for it.

Why the kind of change determines the model

The choice between a linear and an exponential model comes down to what stays constant as the input increases, and recognizing it is the heart of F-LE.A.2. In a linear relationship the difference between successive outputs is constant: each step adds the same fixed amount, so the graph is a straight line and the rate of change never varies. In an exponential relationship the ratio between successive outputs is constant: each step multiplies by the same fixed factor, so the amount added grows (or shrinks) as the quantity itself grows. This is why savings under a fixed weekly deposit are linear, while a balance earning a fixed percent interest is exponential, the interest is a percent of a changing balance, so the dollar amount added increases every period. Reading a context for "same amount added" versus "same factor multiplied," or reading a table for a common difference versus a common ratio, tells you which model to build before you write a single symbol. Getting this distinction right is also what the comparing-function-families topic tests directly, because exponential growth eventually outpaces any linear growth precisely due to that compounding multiplier.

Try this

Q1. A savings account has 300andtheowneradds300 and the owner adds 25 a week. Write f(w)f(w) for the balance after ww weeks. [2 points]

  • Cue. Linear: f(w)=300+25wf(w) = 300 + 25w.

Q2. A population of 500 grows 4 percent per year. Write f(t)f(t). [2 points]

  • Cue. Exponential: f(t)=500(1.04)tf(t) = 500(1.04)^t.

Exam-style practice questions

Practice questions written in the style of LDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

LA LEAP 2025 Math (style)2 marksEquation response. A pool has 50 gallons and is filled at 8 gallons per minute. Write a function f(t)f(t) for the gallons after tt minutes.
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The function is f(t)=50+8tf(t) = 50 + 8t.

This is a linear model: it changes by the same amount each minute (a constant rate). The starting amount 5050 is the yy-intercept, and the rate 88 gallons per minute is the slope. So f(t)=50+8tf(t) = 50 + 8t. Recognizing a "per minute" constant rate as a linear function, with the starting value as the constant term, is the F-BF.A.1 move.

LA LEAP 2025 Math (style)2 marksMultiple choice. A bacteria count starts at 100 and doubles every hour. Which models the count after hh hours? (A) 100(2)h100(2)^h (B) 100+2h100 + 2h (C) 100(2h)100(2h) (D) 2(100)h2(100)^h
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The correct answer is (A).

"Doubles every hour" is a constant multiplier (×2\times 2 per hour), which is exponential growth, not a constant addition. The form is f(h)=abhf(h) = a \cdot b^h with starting value a=100a = 100 and growth factor b=2b = 2: f(h)=100(2)hf(h) = 100(2)^h. Choice (B) is linear (adding), which would fit "increases by 2 each hour," not "doubles." Distinguishing repeated multiplication (exponential) from repeated addition (linear) is the key.

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