Skip to main content
North CarolinaMathsSyllabus dot point

How can you use the structure of an expression to rewrite it in an equivalent, more useful form?

Use the structure of an expression to identify ways to rewrite it, and write an equivalent factored form of a quadratic to reveal zeros (NC.M1.A-SSE.2, A-SSE.3).

An NC Math 1 EOC answer on rewriting expressions using structure (NC.M1.A-SSE.2, A-SSE.3): spotting common factors, difference of squares, and perfect-square trinomials, and writing factored form to reveal the zeros of a quadratic.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this topic is asking
  2. The structures you must recognize
  3. Using structure on a difference of squares
  4. Factored form reveals the zeros
  5. When to factor out a GCF first
  6. How the NC Math 1 EOC examines this topic
  7. Why equivalent forms carry different information
  8. Try this

What this topic is asking

Two standards work together. NC.M1.A-SSE.2 asks you to use the structure of an expression to see how it can be rewritten: spotting a common factor, a difference of squares, or a perfect-square pattern. NC.M1.A-SSE.3 narrows this to quadratics: write an equivalent factored form of ax2+bx+cax^2 + bx + c to reveal the zeros of the related equation or function. The theme is that equivalent forms are not equally useful, and the right rewrite exposes information you want.

The structures you must recognize

A-SSE.2 is a pattern-recognition standard. These three patterns cover almost every NC Math 1 item.

Recognizing the pattern is faster than blind trial. If you see x2−16x^2 - 16, the structure (square minus square) tells you to write (x−4)(x+4)(x - 4)(x + 4) at once.

Using structure on a difference of squares

The cancelling middle terms are the signature of a difference of squares: when you multiply (a−b)(a+b)(a - b)(a + b), the +ab+ab and −ab-ab always cancel.

Factored form reveals the zeros

A-SSE.3 is about choosing the form that shows the solutions. A quadratic in factored form displays its zeros directly.

If y=(x−r)(x−s)y = (x - r)(x - s), then y=0y = 0 exactly when one factor is zero, so x=rx = r or x=sx = s. The zeros are also the xx-intercepts of the parabola. This is why factoring is the first tool for solving quadratic equations and for graphing.

For example, y=x2−x−6=(x−3)(x+2)y = x^2 - x - 6 = (x - 3)(x + 2) has zeros x=3x = 3 and x=−2x = -2, so the parabola crosses the xx-axis at (3,0)(3, 0) and (−2,0)(-2, 0).

When to factor out a GCF first

Always check for a common factor before applying another pattern, because pulling out the GCF can expose a simpler structure.

For 2x2−82x^2 - 8, factor the GCF first: 2(x2−4)2(x^2 - 4). Now x2−4x^2 - 4 is a difference of squares, so the full factorization is 2(x−2)(x+2)2(x - 2)(x + 2). Skipping the GCF step would leave the difference of squares hidden.

How the NC Math 1 EOC examines this topic

  • Multiple choice. Choose the equivalent factored form, or identify which factoring pattern applies.
  • Gridded response. State a zero of a function after factoring, or enter a missing factor.
  • Technology-enhanced. Match each expression to its factored form, or select all expressions equivalent to a given one.

A useful exam habit is to expand to check. Because the test scores factored answers by exact match in many formats, multiplying your factors back out catches sign errors before they cost a point.

Why equivalent forms carry different information

The same number can be written as 1212, 3×43 \times 4, or 22×32^2 \times 3, and which you choose depends on what you want to see. Expressions are the same. The expanded form x2+2x−15x^2 + 2x - 15 makes the leading coefficient and constant obvious; the factored form (x+5)(x−3)(x + 5)(x - 3) makes the zeros obvious; later courses add vertex form to make the turning point obvious. A-SSE asks you to move fluently between forms and to pick the one that answers the question, which is a habit that pays off through every Functions item on the test.

Try this

Q1. Factor x2−81x^2 - 81. [1 point]

  • Cue. Difference of squares: (x−9)(x+9)(x - 9)(x + 9).

Q2. Write 5x2+15x5x^2 + 15x in factored form and state the zeros of y=5x2+15xy = 5x^2 + 15x. [2 points]

  • Cue. GCF: 5x(x+3)5x(x + 3); zeros x=0x = 0 and x=−3x = -3.

Exam-style practice questions

Practice questions written in the style of NCDPI exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

NC Math 1 EOC (style)1 marksWhich expression is equivalent to x2−49x^2 - 49? (A) (x−7)2(x - 7)^2 (B) (x−7)(x+7)(x - 7)(x + 7) (C) (x+7)2(x + 7)^2 (D) (x−49)(x+1)(x - 49)(x + 1)
Show worked answer →

The correct answer is (B).

The expression x2−49x^2 - 49 is a difference of squares, x2−72x^2 - 7^2, which factors as (x−7)(x+7)(x - 7)(x + 7). Option (A) and (C) are perfect squares that would expand to x2±14x+49x^2 \pm 14x + 49, not x2−49x^2 - 49. Recognizing a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b) from the structure is exactly what A-SSE.2 asks.

NC Math 1 EOC (style)2 marksWrite x2+2x−15x^2 + 2x - 15 in factored form, then state the zeros of y=x2+2x−15y = x^2 + 2x - 15.
Show worked answer →

Factored form: (x+5)(x−3)(x + 5)(x - 3). The zeros are x=−5x = -5 and x=3x = 3.

Find two numbers that multiply to −15-15 and add to 22: those are +5+5 and −3-3, so x2+2x−15=(x+5)(x−3)x^2 + 2x - 15 = (x + 5)(x - 3). Setting each factor to zero gives x=−5x = -5 and x=3x = 3. Writing factored form to reveal the zeros is the A-SSE.3 skill: the factored form makes the solutions visible at a glance.

Related dot points

Sources & how we know this