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How do you graph a linear equation, and how do you read its intercepts and slope from the graph?

Graph linear equations in two variables and identify slope and intercepts, labeling axes and scale (NC.M1.A-CED.2, F-IF.4).

An NC Math 1 EOC answer on graphing linear equations (NC.M1.A-CED.2, F-IF.4): plotting from slope-intercept form, finding x- and y-intercepts, graphing from standard form, and reading slope from a graph.

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  1. What this topic is asking
  2. Graphing from slope-intercept form
  3. Graphing from standard form using intercepts
  4. Reading slope and intercepts from a graph
  5. Horizontal and vertical lines
  6. How the NC Math 1 EOC examines this topic
  7. Why the intercepts and slope are enough
  8. Try this

What this topic is asking

NC.M1.A-CED.2 asks you to graph equations in two variables on coordinate axes, labeling axes and scales. Paired with NC.M1.F-IF.4 (interpreting key features), this means you both draw a line and read its slope and intercepts. On the online EOC you place points and lines with a graphing tool, so accuracy in plotting matters.

Graphing from slope-intercept form

When the equation is y=mx+by = mx + b, the intercept and slope give you everything.

Graphing from standard form using intercepts

When the equation is Ax+By=CAx + By = C, the two intercepts are quickest.

  • x-intercept: set y=0y = 0 and solve for xx. The point is (x,0)(x, 0).
  • y-intercept: set x=0x = 0 and solve for yy. The point is (0,y)(0, y).

Plot both and connect. For 2x+5y=102x + 5y = 10: x-intercept (5,0)(5, 0), y-intercept (0,2)(0, 2).

Reading slope and intercepts from a graph

To read a graph, find the y-intercept where the line crosses the y-axis, then pick two lattice points the line passes through and compute rise over run between them. Counting up/down for rise and right/left for run, with signs, gives the slope. A line falling left to right has a negative slope.

Horizontal and vertical lines

Two special cases appear often:

  • Horizontal line y=cy = c: slope 00, crosses the y-axis at cc, never the x-axis (unless c=0c = 0).
  • Vertical line x=cx = c: slope undefined, crosses the x-axis at cc, and is not a function (it fails the vertical line test).

How the NC Math 1 EOC examines this topic

  • Technology-enhanced. Plot a line by placing points, or drag a line to match an equation.
  • Multiple choice. Match a graph to its equation, or identify an intercept or the slope.
  • Gridded response. Enter the value of an intercept.

Graphing ties to writing linear equations (the same slope and intercept) and to solving systems by graphing, where the intersection of two lines is the solution.

Why the intercepts and slope are enough

A line has no curvature, so two pieces of information fix it entirely: a starting point and a direction. The y-intercept supplies a point on the y-axis, and the slope supplies the direction; alternatively, the two intercepts supply two points. Either pairing determines the unique line, which is why you never need a table of many points to graph a line accurately. This economy, two facts, one line, is the same idea behind writing equations, and it is what makes linear models the simplest and most common functions on the EOC. Reading a graph is just running the process backward: recover the slope and intercept from the picture.

Try this

Q1. Graph y=−2x+3y = -2x + 3 by describing the first two points. [1 point]

  • Cue. Plot (0,3)(0, 3); slope −2-2 means down 22, right 11 to (1,1)(1, 1).

Q2. Find both intercepts of 4x−y=84x - y = 8. [2 points]

  • Cue. x-intercept: y=0⇒x=2y = 0 \Rightarrow x = 2, so (2,0)(2, 0); y-intercept: x=0⇒y=−8x = 0 \Rightarrow y = -8, so (0,−8)(0, -8).

Exam-style practice questions

Practice questions written in the style of NCDPI exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

NC Math 1 EOC (style)2 marksFind the x-intercept and y-intercept of 3x+2y=123x + 2y = 12.
Show worked answer →

The x-intercept is (4,0)(4, 0) and the y-intercept is (0,6)(0, 6).

For the x-intercept, set y=0y = 0: 3x=123x = 12, so x=4x = 4, giving (4,0)(4, 0). For the y-intercept, set x=0x = 0: 2y=122y = 12, so y=6y = 6, giving (0,6)(0, 6). Setting one variable to zero to find each intercept is the standard method for graphing from standard form.

NC Math 1 EOC (style)1 marksA line passes through (0,−2)(0, -2) and rises 33 for every 11 across. What is its equation? (A) y=3x−2y = 3x - 2 (B) y=−2x+3y = -2x + 3 (C) y=3x+2y = 3x + 2 (D) y=13x−2y = \tfrac{1}{3}x - 2
Show worked answer →

The correct answer is (A), y=3x−2y = 3x - 2.

"Rises 33 for every 11 across" is slope m=3m = 3. The point (0,−2)(0, -2) is the y-intercept, so b=−2b = -2. Slope-intercept form gives y=3x−2y = 3x - 2. Reading slope as rise over run from a description is a common graphing item.

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