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What shape are the orbits of the planets, and how do we measure how stretched an orbit is?

Calculate the eccentricity of an elliptical orbit using the Reference Tables equation (distance between foci divided by length of the major axis) and relate eccentricity to orbital shape and orbital velocity.

A Regents answer on orbital eccentricity: ellipses and foci, the Reference Tables formula (distance between foci over the length of the major axis), worked calculations rounded to the nearest thousandth, and how eccentricity and the Sun's off-center position affect orbital velocity and apparent solar diameter.

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  1. What this topic is asking
  2. Ellipses and foci
  3. The eccentricity equation
  4. Eccentricity and orbital velocity
  5. Try this

What this topic is asking

Planets orbit the Sun in ellipses, not circles. The Regents wants you to calculate eccentricity with the page-1 Reference Tables equation and to relate eccentricity to the shape of an orbit and to changes in orbital velocity. This is the single most reliable calculation in the astronomy unit.

Ellipses and foci

You can draw an ellipse with two pins (the foci) and a loop of string: the more the pins are spread apart, the more flattened the ellipse. Spread them to the same point and you get a circle.

The eccentricity equation

The Reference Tables (page 1) give:

eccentricity=distance between focilength of major axis\text{eccentricity} = \frac{\text{distance between foci}}{\text{length of major axis}}

Key features the Regents tests:

  • Eccentricity is unitless (the lengths cancel), so never write a unit on the answer.
  • Round to the nearest thousandth (three decimal places) unless told otherwise.
  • A value of 0 is a perfect circle; values approaching 1 are very flattened. The value can never reach or exceed 1 for a closed orbit.
  • The smaller the distance between the foci (for a given major axis), the closer to circular the orbit.

Eccentricity and orbital velocity

Because the Sun is at one focus and not at the center, a planet's distance from the Sun changes through its orbit:

  • Perihelion is the closest point to the Sun. Here the planet moves fastest, and the Sun appears largest in the sky.
  • Aphelion is the farthest point. Here the planet moves slowest, and the Sun appears smallest.

This follows Kepler's second law (a planet sweeps out equal areas in equal times). Earth's orbit is nearly circular, so this effect is small but real, and the Regents asks about it.

Try this

Q1. State the formula for eccentricity and the unit of the answer. [2 points]

  • Cue. Distance between foci divided by length of the major axis; the answer is unitless.

Q2. An orbit has foci 2.0 cm apart and a major axis of 10.0 cm. Calculate the eccentricity. [2 points]

  • Cue. 2.010.0=0.20\dfrac{2.0}{10.0} = 0.20, written as 0.2000.200.

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (style)2 marksPart B-2. An ellipse is drawn with two foci. The distance between the foci is 3.2 cm and the length of the major axis is 8.0 cm. Calculate the eccentricity of this ellipse. Show the equation, the substitution and the answer rounded to the nearest thousandth.
Show worked answer →

A 2-point calculation using the Reference Tables equation.

1 point for the correct setup and substitution, 1 point for the correct answer rounded to the nearest thousandth.

Equation (from page 1 of the Reference Tables): eccentricity = distance between foci divided by length of major axis.
Substitution: 3.2 cm / 8.0 cm.
Answer: 0.40, written to the nearest thousandth as 0.400.

Markers reward showing the equation and substitution; eccentricity is unitless because the centimeters cancel.

Regents (style)1 marksPart A. As the eccentricity of a planet's orbit increases, the shape of the orbit becomes (1) more circular (2) more elliptical (flattened) (3) a perfect circle (4) a straight line. Justify your choice.
Show worked answer →

A 1-point multiple-choice question. The answer is (2).

Eccentricity measures how stretched (flattened) an ellipse is. An eccentricity of 0 is a perfect circle; as eccentricity increases towards 1 the ellipse becomes more elongated and flattened. Planetary orbits have low eccentricities (Earth's is about 0.017, almost circular). (1) and (3) describe decreasing eccentricity; (4) would need an eccentricity of essentially 1. The trap is thinking a higher eccentricity is "rounder".

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