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How do you tell a linear model from an exponential one, and how do you build each from a context?

Distinguish linear from exponential growth (constant difference versus constant ratio), construct linear and exponential functions from descriptions, tables, or two points, and interpret their parameters (initial value, rate of change, growth factor) in context.

A NY Regents Algebra I answer on linear and exponential models: recognizing constant difference versus constant ratio, building each model from a context or table, and interpreting the slope, initial value, and growth factor.

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  1. What this topic is asking
  2. Linear versus exponential
  3. Building a linear model
  4. Building an exponential model
  5. Interpreting parameters and comparing models
  6. Try this

What this topic is asking

The Regents Algebra I exam (the Linear, Quadratic, and Exponential Models, F-LE, and Building Functions, F-BF, clusters) wants you to tell linear growth from exponential growth, to build each kind of function from a description, a table, or two points, and to interpret the parameters: the initial value, the rate of change or slope, and the growth or decay factor. Modeling questions are among the most frequent constructed-response items.

Linear versus exponential

The defining test is how a quantity changes from one step to the next.

In a table where xx increases by 1 each row, look at the outputs. If they go 3,7,11,153, 7, 11, 15 (adding 4 each time), the model is linear with rate 4. If they go 3,6,12,243, 6, 12, 24 (multiplying by 2), it is exponential with growth factor 2. This single check answers most Part I model-identification questions.

Building a linear model

A linear function needs a rate of change (slope) and an initial value (the yy-intercept). From two points, the slope is m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}; from a description, it is the per-unit amount ("\25permonth").Theinitialvalueistheamountat per month"). The initial value is the amount at x = 0("a ("a \5050 sign-up fee").

For a phone plan costing a \50feeplus fee plus \2525 per month, C(m)=50+25mC(m) = 50 + 25m. The 5050 is the starting cost and the 2525 is the slope.

Building an exponential model

An exponential function needs an initial value aa and a growth factor b=1+rb = 1 + r (growth) or b=1rb = 1 - r (decay), where rr is the percent change written as a decimal.

Interpreting parameters and comparing models

Every parameter has a meaning to state in context. In f(x)=a(b)xf(x) = a(b)^x, aa is the value at the start, and bb tells the per-step multiplier (and thus the percent change). A clarifying idea the Regents tests is that exponential growth eventually outpaces any linear growth: even if a linear model is larger at first, a positive exponential rate means the exponential function overtakes it and stays ahead. When a question gives a table or two models and asks which is greater "in the long run", the exponential one wins for large inputs. Always justify a linear-versus-exponential claim by naming the constant difference or constant ratio, because that is where the credit sits.

Try this

Q1. A table shows outputs 5,10,20,405, 10, 20, 40 as xx goes 0,1,2,30, 1, 2, 3. Linear or exponential? [1 credit]

  • Cue. Constant ratio of 2, so exponential: f(x)=5(2)xf(x) = 5(2)^x.

Q2. Write a linear model for a tank starting at 80 liters and draining 6 liters per minute. [2 credits]

  • Cue. L(t)=806tL(t) = 80 - 6t: initial value 80, rate 6-6.

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (style)2 marksPart I (multiple choice). A bacteria culture starts at 200 and doubles every hour. Which function models the count after tt hours? (1) f(t)=200+2tf(t) = 200 + 2t (2) f(t)=200(2)tf(t) = 200(2)^t (3) f(t)=2(200)tf(t) = 2(200)^t (4) f(t)=200t2f(t) = 200t^2
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The correct answer is (2).

Doubling every hour is a constant ratio of 2, which is exponential with growth factor 2 and initial value 200: f(t)=200(2)tf(t) = 200(2)^t. Choice (1) is linear (adds 2 each hour, the wrong pattern). Choice (3) swaps the base and the initial value. A quick check: at t=1t = 1, 200(2)1=400200(2)^1 = 400, which is the count doubled, as required.

Regents (style)4 marksPart III (constructed response). A savings account is modeled by A(t)=1500(1.025)tA(t) = 1500(1.025)^t, where tt is in years. (a) State the initial deposit and the annual interest rate. (b) Determine the balance after 10 years, rounded to the nearest cent, and explain whether the growth is linear or exponential.
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A 4-credit question with credits spread across the parts.

(a) Initial deposit is 1500(thevalueat1500 (the value at t = 0).Thebase). The base 1.025 = 1 + 0.025$, so the annual rate is 2.5%.
(b) A(10) = 1500(1.025)^{10} \approx 1500(1.2801) \approx \1920.17$. The growth is exponential, because the balance is multiplied by a constant factor (1.025) each year rather than increased by a constant amount. Omitting the linear-versus-exponential justification, or rounding the base instead of the final value, costs credits.

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