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How do we measure whether a population is evolving?

Use allele and genotype frequencies, and the Hardy-Weinberg model, to describe how a gene pool stays constant or changes over time (Ohio's Learning Standards for Science, Biology, B.E.2).

A standard-level answer on population genetics for Ohio's Biology EOC: gene pools and allele frequencies, the Hardy-Weinberg equilibrium model and its conditions, and how to use p and q to predict genotype frequencies and detect evolution.

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  1. What this topic is asking
  2. Gene pools and allele frequencies
  3. The Hardy-Weinberg model
  4. The five conditions
  5. Using the model
  6. Try this

What this topic is asking

Ohio standard B.E.2 asks students to understand variation of organisms within a species due to population genetics and gene frequency, and the standards reserve using statistical mathematics to predict changes in a gene pool for high school biology. The Ohio Biology EOC turns this into items where you work with allele and genotype frequencies and use the Hardy-Weinberg model as a baseline. The crosscutting idea is stability and change and the practice is using mathematics: the model describes a population that stays constant, so any departure from it signals evolution. This builds on the allele vocabulary from chromosomes, genes, and alleles.

Gene pools and allele frequencies

A population is a group of the same species living in one area and interbreeding. Its gene pool is the total collection of alleles for every gene carried by all its members. Population genetics studies how the frequencies of those alleles change.

An allele frequency is the proportion of a particular allele among all copies of that gene in the population. If a gene has just two alleles, a dominant one and a recessive one, their frequencies are written pp and qq, and because every copy is one or the other:

p+q=1p + q = 1

Evolution, at the population level, is simply a change in allele frequencies over time. If pp and qq stay the same generation after generation, the population is not evolving; if they shift, it is.

The Hardy-Weinberg model

The Hardy-Weinberg principle describes the special case of a population whose allele frequencies stay constant, called Hardy-Weinberg equilibrium. It connects allele frequencies (pp and qq) to genotype frequencies using the expansion of (p+q)2(p + q)^2:

p2+2pq+q2=1p^2 + 2pq + q^2 = 1

Reading each term:

  • p2p^2 is the frequency of the homozygous dominant genotype.
  • 2pq2pq is the frequency of the heterozygous genotype.
  • q2q^2 is the frequency of the homozygous recessive genotype.

Because a recessive phenotype shows only in homozygous recessive individuals, q2q^2 is often the one quantity you can measure directly (count the recessive individuals), and from it you can work back to qq, then pp, then the other genotype frequencies.

The five conditions

Hardy-Weinberg equilibrium holds only if a population meets five conditions. Each one, if broken, is a mechanism of evolution (it changes allele frequencies):

  • No mutation. Mutation adds or removes alleles.
  • No gene flow (no migration). Individuals entering or leaving carry alleles in or out.
  • A very large population. Small populations drift by chance (genetic drift).
  • Random mating. Non-random (selective) mating shifts genotype proportions.
  • No natural selection. Selection favors some alleles over others.

A real population almost never meets all five, so its allele frequencies change over time. The model's value is as a null baseline: it tells you what to expect with no evolution, so any difference points to one of these five mechanisms.

Using the model

The model lets you predict genotype frequencies from a known allele frequency, or recover allele frequencies from a measured genotype frequency.

Try this

Q1. Define evolution in terms of a gene pool. [1]

  • Cue. A change in the allele (gene) frequencies of a population over time.

Q2. In a population, p=0.8p = 0.8 and q=0.2q = 0.2. Calculate the frequency of heterozygous individuals using the Hardy-Weinberg model. [1]

  • Cue. 2pq=2×0.8×0.2=0.322pq = 2 \times 0.8 \times 0.2 = 0.32 (32%).

Exam-style practice questions

Practice questions written in the style of ODEW exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Ohio Biology EOC (style)2 marksIn a population, the recessive allele frequency for a gene is q=0.3q = 0.3 and the dominant allele frequency is p=0.7p = 0.7. Using the Hardy-Weinberg model, (a) calculate the frequency of homozygous recessive individuals, and (b) calculate the frequency of heterozygous individuals.
Show worked answer →

A 2-point Hardy-Weinberg calculation. Genotype frequencies follow p2+2pq+q2=1p^2 + 2pq + q^2 = 1.

(a) 1 point: homozygous recessive frequency is q2=(0.3)2=0.09q^2 = (0.3)^2 = 0.09, or 9% of the population.

(b) 1 point: heterozygous frequency is 2pq=2×0.7×0.3=0.422pq = 2 \times 0.7 \times 0.3 = 0.42, or 42% of the population. (As a check, p2=0.49p^2 = 0.49, and 0.49+0.42+0.09=1.000.49 + 0.42 + 0.09 = 1.00.)

Ohio Biology EOC (style)2 marksA population's allele frequencies for a gene are measured every generation and are found to be changing steadily over time. (a) State whether this population is evolving. (b) State two factors that could be causing the change.
Show worked answer →

A 2-point item linking allele-frequency change to evolution.

(a) 1 point: yes, the population is evolving, because evolution is defined as a change in allele (gene) frequencies in a population over time.

(b) 1 point for any two of: natural selection, mutation, genetic drift, gene flow (migration), or non-random mating. The population is not meeting the Hardy-Weinberg conditions for a constant gene pool.

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