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How do you build a function that models a situation, write a linear function from a description or two points, and use it to make predictions?

Build a function that models a relationship, write a linear function from a context, table, or two points, and interpret its parameters in context (Ohio F-BF.1, F-LE.2, F-IF.7).

An Ohio Algebra I answer on building functions (F-BF.1, F-LE.2): writing a linear function from a verbal description, a table, or two points, interpreting the slope and intercept as rate and starting value, and using the function to predict.

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Jump to a section
  1. What this topic is asking
  2. Building from a description
  3. Building from two points
  4. Building from a table
  5. Using the function to predict
  6. How Ohio examines this topic
  7. Why the slope is the rate and the intercept is the start
  8. Why two points are enough for a line
  9. Try this

What this topic is asking

Ohio standards F-BF.1 and F-LE.2 ask you to build a function that models a relationship, often a linear function written from a description, a table, or two points, and to interpret its parts. This is modeling in function notation: identify the rate (slope) and the starting value (intercept), write f(x)=mx+bf(x) = mx + b, and use it to predict. It is a core Functions skill across both parts.

Building from a description

Most linear models hand you the two parts in words: a fixed starting amount and a constant rate.

For "a tank holds 5050 liters and drains 44 liters per hour," the rate is βˆ’4-4 (draining) and the start is 5050, so L(t)=50βˆ’4tL(t) = 50 - 4t.

Building from two points

When you are given two input-output pairs, find the slope, then the intercept.

Building from a table

A table is linear when the output changes by a constant amount for each equal input step. That constant change is the slope; the output at x=0x = 0 (or extended back to it) is the intercept. If a table shows (0,7),(1,10),(2,13)(0, 7), (1, 10), (2, 13), the output rises 33 each step, so f(x)=3x+7f(x) = 3x + 7.

Using the function to predict

Once the rule is built, evaluate it to predict an output, or solve f(x)=kf(x) = k to find when the output reaches a target. For L(t)=50βˆ’4tL(t) = 50 - 4t, the tank is empty when 50βˆ’4t=050 - 4t = 0, so t=12.5t = 12.5 hours.

How Ohio examines this topic

  • Equation response. Write the function rule from a context or two points, then evaluate it.
  • Multiple choice and multiple-select. Match a description, table, or pair of points to the correct rule.
  • Tables. Complete a function table consistent with a linear rule.

Why the slope is the rate and the intercept is the start

The structure f(x)=mx+bf(x) = mx + b maps cleanly onto a real situation, which is what makes it such a useful model. The term mxmx grows in proportion to the input, so mm is exactly the amount of change per one unit of input, the rate. The term bb stands alone, unaffected by xx, so it is the output when x=0x = 0, the starting value before any change has happened. Reading a word problem this way, "starts at" supplies bb and "per" supplies mm, lets you write the rule almost directly. Interpreting them back, with units, is the modeling habit the test rewards: mm dollars per month, bb dollars at the start.

Why two points are enough for a line

A straight line is completely determined by two points, which is why "passes through these two points" is enough to recover the whole rule. The two points fix the slope (rise over run between them), and either point then fixes the intercept, leaving no freedom. This is the same idea as writing a line's equation, now phrased in function notation. It also means a third given point is a check: if it does not satisfy the rule you built, either the data is not linear or you made an arithmetic slip, so substituting the extra point is a quick way to catch an error before it costs the item.

Try this

Q1. A gym charges \25tojoinplus to join plus \1010 per month. Write C(m)C(m) and find C(6)C(6). [2 points]

  • Cue. C(m)=25+10mC(m) = 25 + 10m; C(6)=25+60=85C(6) = 25 + 60 = 85.

Q2. Write the linear function through (0,βˆ’1)(0, -1) and (4,7)(4, 7). [2 points]

  • Cue. m=7βˆ’(βˆ’1)4=2m = \frac{7 - (-1)}{4} = 2, b=βˆ’1b = -1, so f(x)=2xβˆ’1f(x) = 2x - 1.

Exam-style practice questions

Practice questions written in the style of ODEW exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Ohio Algebra I EOC (style)3 marksEquation response. A pool has 200200 gallons and is filling at 1515 gallons per minute. Write a function V(t)V(t) for the volume after tt minutes, then find V(8)V(8).
Show worked answer β†’

V(t)=200+15tV(t) = 200 + 15t and V(8)=320V(8) = 320 gallons.

A constant rate makes this linear. The starting value 200200 is the yy-intercept and the rate 1515 gallons per minute is the slope: V(t)=200+15tV(t) = 200 + 15t. Evaluate at t=8t = 8: V(8)=200+15(8)=200+120=320V(8) = 200 + 15(8) = 200 + 120 = 320 gallons. Reading "starts at" as the constant and "per minute" as the coefficient is the standard way to build a linear model, and the units confirm the answer is in gallons.

Ohio Algebra I EOC (style)2 marksMultiple choice. A line passes through (0,5)(0, 5) and (3,11)(3, 11). Which function rule fits? (A) f(x)=2x+5f(x) = 2x + 5 (B) f(x)=5x+2f(x) = 5x + 2 (C) f(x)=3x+5f(x) = 3x + 5 (D) f(x)=2x+11f(x) = 2x + 11
Show worked answer β†’

The correct answer is (A).

Find the slope from the two points: m=11βˆ’53βˆ’0=63=2m = \dfrac{11 - 5}{3 - 0} = \dfrac{6}{3} = 2. The point (0,5)(0, 5) is the yy-intercept, so b=5b = 5, giving f(x)=2x+5f(x) = 2x + 5. Check (3,11)(3, 11): 2(3)+5=112(3) + 5 = 11, correct. Building from two points means finding the slope first, then using the intercept (or point-slope), the same skill as writing a line's equation, now in function notation.

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