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How do you add, subtract, and multiply polynomials, and why is the result always another polynomial?

Add, subtract, and multiply polynomials, understanding that polynomials form a system closed under these operations (TN A1.A.APR.A.1).

A TNReady Algebra I answer on adding, subtracting, and multiplying polynomials (TN A1.A.APR.A.1), combining like terms, distributing the subtraction sign, and using the distributive property and FOIL.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. Adding and subtracting: combine like terms
  3. Multiplying: distribute everything
  4. Closure: why the result is still a polynomial
  5. How TNReady examines this topic
  6. Standard form and degree
  7. Try this

What this topic is asking

Standard A1.A.APR.A.1 covers the three basic operations on polynomials, addition, subtraction, and multiplication, and the idea that the result is always another polynomial (the system is closed). The graded skills are combining like terms, distributing the subtraction sign correctly, and multiplying with the distributive property (including the FOIL shortcut for two binomials).

Adding and subtracting: combine like terms

Like terms have the same variable raised to the same power: 3x23x^2 and βˆ’5x2-5x^2 are like terms, but 3x23x^2 and 3x3x are not. To add or subtract polynomials, add the coefficients of like terms.

The danger is subtraction. (A)βˆ’(B)(A) - (B) means subtract every term of BB, so the sign of each term in BB flips.

Multiplying: distribute everything

To multiply, apply the distributive property: each term of the first polynomial multiplies each term of the second. For two binomials, FOIL (First, Outer, Inner, Last) is the same idea in a fixed order. Multiply coefficients and add exponents on matching variables (xβ‹…x=x2x \cdot x = x^2).

Closure: why the result is still a polynomial

Adding, subtracting, or multiplying polynomials never introduces a variable in a denominator, a root, or a negative or fractional exponent, so the answer is always another polynomial. This mirrors how the integers are closed under addition, subtraction, and multiplication: stay inside the system. The exam sometimes asks this directly, for example whether (x2+1)(xβˆ’3)(x^2 + 1)(x - 3) is a polynomial (yes), and the answer follows from closure.

How TNReady examines this topic

  • Equation response. Type the sum, difference, or product in standard form, scored by exact match, so a single sign slip costs the point.
  • Multiple choice. Choose the product of two binomials, with sign-error and missed-middle-term distractors.
  • Drag and drop. Assemble the terms of a product into the correct expression.

A clarifying idea is that multiplication and factoring are inverse operations: expanding (xβˆ’4)(x+4)(x - 4)(x + 4) to x2βˆ’16x^2 - 16 is the reverse of factoring x2βˆ’16x^2 - 16. Fluency in one direction directly supports the other.

Standard form and degree

Always present an answer in standard form, with terms ordered from the highest power down to the constant. The degree of the polynomial is the highest exponent, and the leading coefficient is the number on that term. Writing x3βˆ’x2βˆ’2x+8x^3 - x^2 - 2x + 8 rather than 8βˆ’2x+x3βˆ’x28 - 2x + x^3 - x^2 is not just neatness: exact-match scoring may expect standard form, and the degree and leading coefficient (which control end behavior) are easiest to read off the ordered form. When a product has a missing power, for example no xx term, leave a gap rather than inventing a zero term unless the item asks for placeholders.

Try this

Q1. Simplify (3x2βˆ’x)+(x2+4xβˆ’5)(3x^2 - x) + (x^2 + 4x - 5). [1 point]

  • Cue. 4x2+3xβˆ’54x^2 + 3x - 5.

Q2. Expand (2x+1)2(2x + 1)^2. [2 points]

  • Cue. (2x+1)(2x+1)=4x2+4x+1(2x + 1)(2x + 1) = 4x^2 + 4x + 1 (a perfect-square trinomial).

Exam-style practice questions

Practice questions written in the style of TDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

TNReady (style)2 marksEquation response. Subtract: (4x2βˆ’3x+7)βˆ’(x2+5xβˆ’2)(4x^2 - 3x + 7) - (x^2 + 5x - 2). Write the result in standard form.
Show worked answer β†’

The result is 3x2βˆ’8x+93x^2 - 8x + 9.

Distribute the subtraction sign to every term in the second polynomial: 4x2βˆ’3x+7βˆ’x2βˆ’5x+24x^2 - 3x + 7 - x^2 - 5x + 2. Note that βˆ’(5x)-(5x) becomes βˆ’5x-5x and βˆ’(βˆ’2)-(-2) becomes +2+2. Now combine like terms: 4x2βˆ’x2=3x24x^2 - x^2 = 3x^2, βˆ’3xβˆ’5x=βˆ’8x-3x - 5x = -8x, and 7+2=97 + 2 = 9. The single most common error is subtracting only the first term and forgetting to flip the signs of 5x5x and βˆ’2-2.

TNReady (style)2 marksMultiple choice. What is the product (2xβˆ’3)(x+5)(2x - 3)(x + 5)? (A) 2x2+7xβˆ’152x^2 + 7x - 15 (B) 2x2βˆ’7xβˆ’152x^2 - 7x - 15 (C) 2x2+7x+152x^2 + 7x + 15 (D) 2x2+13xβˆ’152x^2 + 13x - 15
Show worked answer β†’

The correct answer is (A).

Multiply using the distributive property (FOIL): First 2xβ‹…x=2x22x \cdot x = 2x^2; Outer 2xβ‹…5=10x2x \cdot 5 = 10x; Inner βˆ’3β‹…x=βˆ’3x-3 \cdot x = -3x; Last βˆ’3β‹…5=βˆ’15-3 \cdot 5 = -15. Combine the middle terms: 10xβˆ’3x=7x10x - 3x = 7x. The product is 2x2+7xβˆ’152x^2 + 7x - 15. Distractor (B) flips the middle sign, and (D) adds instead of combining 10x10x and βˆ’3x-3x correctly.

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