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How do you solve a simple exponential equation by rewriting with a common base, and how do you distinguish linear from exponential situations?

Solve exponential equations using the properties of exponents (rewriting with a common base), and distinguish between situations that can be modeled with linear functions and with exponential functions (TEKS A.9D, A.9G).

A STAAR Algebra I answer on solving simple exponential equations by common base (TEKS A.9D) and distinguishing linear from exponential growth (TEKS A.9G) - constant difference versus constant ratio.

Generated by Claude Opus 4.89 min answer

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  1. What this topic is asking
  2. Solving by a common base
  3. Linear versus exponential
  4. Why the distinction matters
  5. How STAAR examines this topic
  6. Recognizing common powers quickly
  7. Where the two models cross
  8. Try this

What this topic is asking

TEKS A.9D and A.9G round out the Exponential Functions category with two skills: solving a simple exponential equation by rewriting both sides with a common base, and distinguishing linear from exponential situations. The second is a recurring conceptual item: linear means a constant difference, exponential a constant ratio.

Solving by a common base

When both sides of an exponential equation can be written with the same base, the exponents must match.

For 32x=813^{2x} = 81: write 81=3481 = 3^4, so 32x=343^{2x} = 3^4, giving 2x=42x = 4 and x=2x = 2. The skill is recognizing the common base: 4,8,16,324, 8, 16, 32 are powers of 2; 9,27,819, 27, 81 are powers of 3.

Linear versus exponential

This is a high-frequency conceptual item. Look at how the outputs change for equal steps in the input:

  • Constant difference: the outputs go up (or down) by the same amount each step. This is linear, y=mx+by = mx + b, where the difference is the slope.
  • Constant ratio: the outputs are multiplied by the same factor each step. This is exponential, y=abxy = ab^x, where the ratio is the base.

For the table 4,12,36,1084, 12, 36, 108: differences 8,24,728, 24, 72 are not constant, but ratios 3,3,33, 3, 3 are, so it is exponential with base 3.

Why the distinction matters

Linear and exponential models behave very differently over time: a linear quantity grows by a fixed amount, but an exponential quantity eventually outpaces any linear one because it multiplies. Recognizing which model fits a description, "increases by 50eachmonth"(linear)versus"increasesby550 each month" (linear) versus "increases by 5% each month" (exponential), is exactly what A.9G tests, and it determines whether you write y = mx + bor or y = ab^x$.

How STAAR examines this topic

  • Multiple choice. Solve a common-base equation, with the "forgot the constant in the exponent" distractor.
  • Inline choice. Classify a table or description as linear or exponential, and pick the matching function.
  • Equation editor and number entry. Enter the solution to an exponential equation.

A clarifying idea is that "by a fixed amount" is linear and "by a fixed percent or factor" is exponential: the wording of a problem usually signals the model before you do any algebra, and a table confirms it through constant difference versus constant ratio.

Recognizing common powers quickly

The whole common-base method depends on spotting that a number is a power of a small base, so it pays to know the short tables cold. Powers of 2 are 2,4,8,16,32,642, 4, 8, 16, 32, 64; powers of 3 are 3,9,27,813, 9, 27, 81; powers of 5 are 5,25,1255, 25, 125; and powers of 4 (4,16,644, 16, 64) and 9 (9,819, 81) overlap with powers of 2 and 3 respectively. When an equation pairs a base with a number on the other side, ask "is that number a power of this base?" If 2x=642^{x} = 64, then 64=2664 = 2^6 gives x=6x = 6 at once. The few cases STAAR uses are always built from these small powers, so recognition is fast once the tables are automatic.

Where the two models cross

Comparing a linear and an exponential model shows why the distinction matters in practice. Suppose one savings plan adds \100ayear(linear)andanothergrows10100 a year (linear) and another grows 10% a year from the same start (exponential). Early on the linear plan may be ahead, because a fixed \100 beats a small percent of a small balance, but the exponential plan's growth accelerates and eventually overtakes it permanently. This crossover is the intuition behind A.9G: the question of which model fits is not just bookkeeping, it changes the long-run behavior, and an item may ask you to identify which description (fixed amount or fixed percent) produces the faster eventual growth.

Try this

Q1. Solve 2x=322^{x} = 32. [1 point]

  • Cue. 32=2532 = 2^5, so x=5x = 5.

Q2. A table shows 5,10,15,205, 10, 15, 20 for inputs 0,1,2,30, 1, 2, 3. Linear or exponential? [1 point]

  • Cue. Constant difference of 5: linear.

Exam-style practice questions

Practice questions written in the style of TEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

STAAR (style)1 marksMultiple choice. What is the solution to 2x+1=162^{x+1} = 16? (A) x=3x = 3 (B) x=4x = 4 (C) x=7x = 7 (D) x=8x = 8
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The correct answer is (A).

Rewrite 16 as a power of the same base: 16=2416 = 2^4. So 2x+1=242^{x+1} = 2^4. With equal bases, the exponents must be equal: x+1=4x + 1 = 4, so x=3x = 3. The property used is the exponent law for equal bases. Choice (B) is the exponent on the right side, forgetting the +1+1; set the exponents equal and solve.

STAAR (style)2 marksInline choice. A table shows outputs 3, 6, 12, 24 for inputs 0, 1, 2, 3. This data is [linear / exponential], because the outputs have a constant [difference / ratio], and a function that models it is [y = 3x / y = 3(2)^x].
Show worked answer →

The data is exponential, because the outputs have a constant ratio, and a function that models it is y = 3(2)^x.

Check the differences: 63=36 - 3 = 3, 126=612 - 6 = 6, not constant, so not linear. Check the ratios: 63=2\frac{6}{3} = 2, 126=2\frac{12}{6} = 2, 2412=2\frac{24}{12} = 2, constant, so exponential with base 2. The initial value (at x=0x = 0) is 3, so y=3(2)xy = 3(2)^x. Constant difference signals linear; constant ratio signals exponential.

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