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How do you turn a chemical name into a formula and a formula into a name?

Naming compounds and writing formulas: name and write formulas for ionic compounds (including polyatomic ions), binary molecular compounds and simple acids.

A focused Virginia SOL Chemistry answer on nomenclature under CH.3: writing formulas for ionic compounds by balancing charges (the crossover method), using polyatomic ions and roman numerals, and naming binary molecular compounds with prefixes and simple acids.

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  1. What this topic is asking
  2. Ionic compounds
  3. Polyatomic ions and transition metals
  4. Binary molecular compounds
  5. Simple acids
  6. Try this

What this topic is asking

Standard CH.3 requires fluent nomenclature: writing a correct formula from a name and a correct name from a formula. Virginia expects you to handle ionic compounds (including those with polyatomic ions and transition metals), binary molecular compounds, and simple acids. A correct formula is the starting point for molar mass, balancing equations and every calculation that follows.

Ionic compounds

For example, aluminum (Al3+\text{Al}^{3+}) and oxygen (O2βˆ’\text{O}^{2-}) cross over to Al2O3\text{Al}_2\text{O}_3. To name an ionic compound, write the metal name, then the nonmetal name ending in -ide (sodium chloride, magnesium oxide). The charge of a main-group metal is fixed by its group, so no roman numeral is needed.

Polyatomic ions and transition metals

Transition metals can form more than one charge, so the name uses a roman numeral to state it: iron(II) is Fe2+\text{Fe}^{2+} and iron(III) is Fe3+\text{Fe}^{3+}. Reading a formula in reverse, you find the metal's charge from the charge needed to balance the anion.

Binary molecular compounds

A binary molecular compound contains two nonmetals and is named with Greek prefixes that state the number of each atom: mono- (1), di- (2), tri- (3), tetra- (4), penta- (5). The first element keeps its name (and drops mono- if it is one), the second ends in -ide. So CO\text{CO} is carbon monoxide, CO2\text{CO}_2 is carbon dioxide, and P2O5\text{P}_2\text{O}_5 is diphosphorus pentoxide. Prefixes are used only for molecular compounds, never for ionic ones.

Simple acids

An acid produces hydrogen ions in water and is named from its anion. If the anion has no oxygen (a binary acid), use "hydro...ic acid": HCl\text{HCl} is hydrochloric acid. If the anion is a polyatomic oxyanion, drop the ending and add -ic (for -ate) or -ous (for -ite): sulfate gives sulfuric acid (H2SO4\text{H}_2\text{SO}_4), nitrate gives nitric acid (HNO3\text{HNO}_3).

Try this

Q1. Write the formula for magnesium nitrate (magnesium Mg2+\text{Mg}^{2+}, nitrate NO3βˆ’\text{NO}_3^-). [1 point]

  • Cue. Mg(NO3)2\text{Mg}(\text{NO}_3)_2; one Mg2+\text{Mg}^{2+} needs two nitrate ions, which take parentheses.

Q2. Name the molecular compound SF6\text{SF}_6. [1 point]

  • Cue. Sulfur hexafluoride (hexa- for six fluorine, second element ends in -ide).

Exam-style practice questions

Practice questions written in the style of VDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SOL (multiple choice)1 marksWhat is the correct formula for calcium phosphate, formed from Ca2+\text{Ca}^{2+} and PO43βˆ’\text{PO}_4^{3-}? (A) CaPO4\text{CaPO}_4 (B) Ca2(PO4)3\text{Ca}_2(\text{PO}_4)_3 (C) Ca3(PO4)2\text{Ca}_3(\text{PO}_4)_2 (D) Ca3PO4\text{Ca}_3\text{PO}_4
Show worked answer β†’

The answer is (C) Ca3(PO4)2\text{Ca}_3(\text{PO}_4)_2.

Balance the charges so the compound is neutral. The calcium charge (2+2+) and the phosphate charge (3βˆ’3-) cross over to give the subscripts: three calcium ions and two phosphate ions, since 3Γ—(2+)=6+3 \times (2+) = 6+ and 2Γ—(3βˆ’)=6βˆ’2 \times (3-) = 6-. The polyatomic ion phosphate is enclosed in parentheses because there is more than one.

The trap is forgetting the parentheses or not balancing the charges; the total positive and negative charge must be equal.

SOL (tech-enhanced, fill in the blank)2 marks(a) Write the name of the compound N2O4\text{N}_2\text{O}_4. (b) Write the formula for iron(III) oxide.
Show worked answer β†’

A 2-point nomenclature item testing both directions.

(a) Name (1 point): dinitrogen tetroxide. It is a binary molecular compound (two nonmetals), so use prefixes for both elements: di- for two nitrogen, tetr(a)- for four oxygen, with the second element ending in -ide.
(b) Formula (1 point): Fe2O3\text{Fe}_2\text{O}_3. The roman numeral (III) gives iron a 3+3+ charge; oxygen is 2βˆ’2-. Crossing the charges over gives two iron and three oxygen.

Markers reward using prefixes for the molecular compound and using the roman numeral as the metal's charge for the ionic compound.

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