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How do significant figures and unit conversions keep a chemistry calculation honest?

Measurement, significant figures and dimensional analysis: use SI units, significant figures and scientific notation, convert units by dimensional analysis, and calculate density and percent error.

A focused Virginia SOL Chemistry answer on measurement under CH.1: SI units, the rules for significant figures, scientific notation, converting units by dimensional analysis (factor-label), and calculating density and percent error.

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  1. What this topic is asking
  2. SI units and scientific notation
  3. Significant figures
  4. Dimensional analysis
  5. Density and percent error
  6. Try this

What this topic is asking

This part of standard CH.1 is the numeracy of chemistry. Virginia expects you to measure and report quantities in SI units, apply the rules for significant figures, use scientific notation for very large or very small numbers, convert between units by dimensional analysis (the factor-label method), and calculate density and percent error. The on-screen calculator does the arithmetic; the marks are for setting the calculation up correctly and reporting the answer to a sensible precision.

SI units and scientific notation

Chemistry uses the metric (SI) system: mass in grams or kilograms, volume in liters or milliliters, length in meters or centimeters, temperature in kelvin or degrees Celsius. Prefixes scale the base unit: kilo- (10310^3), centi- (10210^{-2}), milli- (10310^{-3}), micro- (10610^{-6}), nano- (10910^{-9}).

Significant figures

Significant figures show how precisely a quantity was measured. The rules:

  • All nonzero digits are significant (4.564.56 has three).
  • Zeros between nonzero digits are significant (10051005 has four).
  • Leading zeros (before the first nonzero digit) are not significant (0.00420.0042 has two).
  • Trailing zeros after a decimal point are significant (2.3002.300 has four).
  • Trailing zeros in a whole number with no decimal point are ambiguous; scientific notation removes the ambiguity (2.0×1022.0 \times 10^{2} has two).

In calculations: when multiplying or dividing, the answer keeps the fewest significant figures of any factor. When adding or subtracting, the answer keeps the fewest decimal places. Round only at the end.

Dimensional analysis

Set the calculation up so the unit you are leaving cancels diagonally. If your units do not cancel to what the question wants, a factor is upside down.

Density and percent error

Two formulas appear constantly:

d=mV,percent error=measuredacceptedaccepted×100d = \frac{m}{V}, \qquad \text{percent error} = \left|\frac{\text{measured} - \text{accepted}}{\text{accepted}}\right| \times 100

Density relates a substance's mass to the space it fills (g/mL for liquids and solids, g/L for gases) and is an intensive property that identifies a substance. Percent error reports how far a measured value is from the accepted value, as a percentage; the absolute-value bars keep it positive.

Try this

Q1. Express 0.0000670.000\,067 in scientific notation. [1 point]

  • Cue. 6.7×1056.7 \times 10^{-5} (move the decimal five places right, so the exponent is negative five).

Q2. A student measures a boiling point of 98.6C98.6\,^{\circ}\text{C} for a liquid whose accepted boiling point is 100.0C100.0\,^{\circ}\text{C}. Calculate the percent error. [2 points]

  • Cue. 98.6100.0100.0×100=1.4%\left|\dfrac{98.6 - 100.0}{100.0}\right| \times 100 = 1.4\%.

Exam-style practice questions

Practice questions written in the style of VDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SOL (multiple choice)1 marksHow many significant figures are in the measurement 0.040300.04030 kg? (A) 2 (B) 3 (C) 4 (D) 5
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The answer is (C) 4.

Leading zeros (the zeros before the 4) are never significant; they only set the decimal place. The 4, the 0 between 4 and 3, and the 3 are significant, and the final trailing zero after the decimal point is significant because it is written deliberately. So the significant figures are 4, 0, 3, 0, which is four.

The trap is counting the two leading zeros; zeros to the left of the first nonzero digit do not count.

SOL (tech-enhanced, fill in blank)2 marksA metal block has a mass of 54.054.0 g and a volume of 20.020.0 mL. (a) Calculate its density to the correct number of significant figures. (b) If the accepted density is 2.702.70 g/mL, calculate the percent error.
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A 2-point calculation item using the density and percent-error formulas.

(a) Density (1 point): d=mV=54.0 g20.0 mL=2.70d = \dfrac{m}{V} = \dfrac{54.0\ \text{g}}{20.0\ \text{mL}} = 2.70 g/mL (three significant figures, matching the data).
(b) Percent error (1 point): percent error=2.702.702.70×100=0%\text{percent error} = \left|\dfrac{2.70 - 2.70}{2.70}\right| \times 100 = 0\%.

Markers reward dividing mass by volume with units and applying the percent-error formula. Here the measured value equals the accepted value, so the percent error is zero.

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