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How do you add, subtract, and multiply polynomial expressions in one variable?

Add, subtract, and multiply polynomial expressions in one variable, including multiplying binomials and applying special products (A.EO.4).

A Virginia SOL Algebra I answer on A.EO.4: adding and subtracting polynomials by combining like terms, multiplying monomials and binomials with the distributive property and FOIL, and the special products.

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  1. What this topic is asking
  2. Adding and subtracting polynomials
  3. Multiplying a monomial by a polynomial
  4. Multiplying two binomials (FOIL)
  5. The special products
  6. Why (a+b)2(a + b)^2 is not a2+b2a^2 + b^2
  7. How the SOL examines this topic
  8. Try this

What this topic is asking

A.EO.4 asks you to add, subtract, and multiply polynomials in one variable. On the Virginia Algebra I SOL these are core Expressions and Operations items: combine two polynomials, multiply two binomials, or apply a special product. They appear as multiple choice, fill-in-the-blank (type the standard-form result), and drag-and-drop (build the product term by term).

Adding and subtracting polynomials

A polynomial is a sum of terms, each a number times a variable raised to a whole-number power. To add, combine like terms. To subtract, first distribute the subtraction to every term of the polynomial being subtracted, then combine.

(4x2+3xβˆ’1)+(2x2βˆ’5x+6)=6x2βˆ’2x+5.(4x^2 + 3x - 1) + (2x^2 - 5x + 6) = 6x^2 - 2x + 5.

The single biggest subtraction error is sign distribution. (5x2βˆ’2x)βˆ’(3x2+4xβˆ’7)(5x^2 - 2x) - (3x^2 + 4x - 7) becomes 5x2βˆ’2xβˆ’3x2βˆ’4x+7=2x2βˆ’6x+75x^2 - 2x - 3x^2 - 4x + 7 = 2x^2 - 6x + 7: the minus flips every sign inside the second parentheses.

Multiplying a monomial by a polynomial

Distribute the monomial to each term, multiplying coefficients and adding exponents on like bases:

3x(2x2βˆ’4x+5)=6x3βˆ’12x2+15x.3x(2x^2 - 4x + 5) = 6x^3 - 12x^2 + 15x.

Multiplying two binomials (FOIL)

To multiply (a+b)(c+d)(a + b)(c + d), distribute every term of the first across the second. The shortcut FOIL names the four products:

  • First: aβ‹…ca \cdot c
  • Outer: aβ‹…da \cdot d
  • Inner: bβ‹…cb \cdot c
  • Last: bβ‹…db \cdot d

Then combine the Outer and Inner terms, which are usually like terms.

The special products

Two patterns appear so often that recognizing them saves time, and they preview the factoring topic:

  • Difference of squares. (a+b)(aβˆ’b)=a2βˆ’b2(a + b)(a - b) = a^2 - b^2. The middle terms cancel: (x+7)(xβˆ’7)=x2βˆ’49(x + 7)(x - 7) = x^2 - 49.
  • Perfect-square trinomial. (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2 and (aβˆ’b)2=a2βˆ’2ab+b2(a - b)^2 = a^2 - 2ab + b^2. So (x+5)2=x2+10x+25(x + 5)^2 = x^2 + 10x + 25.

Why (a+b)2(a + b)^2 is not a2+b2a^2 + b^2

The most common multiplication mistake is writing (x+3)2=x2+9(x + 3)^2 = x^2 + 9. Squaring a binomial means multiplying it by itself, (x+3)(x+3)(x + 3)(x + 3), which by FOIL gives x2+3x+3x+9=x2+6x+9x^2 + 3x + 3x + 9 = x^2 + 6x + 9. The missing 6x6x is the sum of the Outer and Inner products, 2ab2ab. An area picture makes it concrete: a square of side (x+3)(x + 3) has area (x+3)2(x + 3)^2, and it splits into a big square x2x^2, a small square 99, and two rectangles each 3x3x. Forgetting the two rectangles is forgetting the 2ab2ab term. The exponent does not distribute across a sum, which is the same reason a+b≠a+b\sqrt{a + b} \ne \sqrt{a} + \sqrt{b}.

How the SOL examines this topic

  • Fill-in-the-blank. Multiply or combine polynomials and type the standard-form result.
  • Multiple choice. Pick the correct product or sum, with distractors built from sign and middle-term errors.
  • Drag-and-drop. Assemble a product term by term, or order the steps of a multiplication.

Try this

Q1. Simplify (3x2+x)+(x2βˆ’4x+2)(3x^2 + x) + (x^2 - 4x + 2). [1 point]

  • Cue. 4x2βˆ’3x+24x^2 - 3x + 2.

Q2. Expand (x+6)(xβˆ’2)(x + 6)(x - 2). [2 points]

  • Cue. x2βˆ’2x+6xβˆ’12=x2+4xβˆ’12x^2 - 2x + 6x - 12 = x^2 + 4x - 12.

Exam-style practice questions

Practice questions written in the style of VDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SOL (style)2 marksFill in the blank. Multiply (2xβˆ’3)(x+5)(2x - 3)(x + 5) and write the result in standard form ax2+bx+cax^2 + bx + c.
Show worked answer β†’

The product is 2x2+7xβˆ’152x^2 + 7x - 15.

Use FOIL (distribute each term): First 2xβ‹…x=2x22x \cdot x = 2x^2; Outer 2xβ‹…5=10x2x \cdot 5 = 10x; Inner βˆ’3β‹…x=βˆ’3x-3 \cdot x = -3x; Last βˆ’3β‹…5=βˆ’15-3 \cdot 5 = -15. Combine the middle terms: 10xβˆ’3x=7x10x - 3x = 7x. The result is 2x2+7xβˆ’152x^2 + 7x - 15. Forgetting to combine the two middle terms, or mishandling the sign of βˆ’3-3, are the usual errors.

SOL (style)1 marksMultiple choice. Which is equivalent to (3x+4)βˆ’(x2βˆ’2x+1)(3x + 4) - (x^2 - 2x + 1)? (A) βˆ’x2+5x+3-x^2 + 5x + 3 (B) βˆ’x2+x+5-x^2 + x + 5 (C) x2+5x+3x^2 + 5x + 3 (D) βˆ’x2+5x+5-x^2 + 5x + 5
Show worked answer β†’

The correct answer is (A).

Subtracting a polynomial means distributing the minus to every term: βˆ’(x2βˆ’2x+1)=βˆ’x2+2xβˆ’1-(x^2 - 2x + 1) = -x^2 + 2x - 1. Now add: 3x+4βˆ’x2+2xβˆ’13x + 4 - x^2 + 2x - 1. Combine like terms: βˆ’x2-x^2, 3x+2x=5x3x + 2x = 5x, and 4βˆ’1=34 - 1 = 3, giving βˆ’x2+5x+3-x^2 + 5x + 3. The classic trap is distributing the minus to only the first term.

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