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How do you work with arithmetic and geometric sequences on the ACT, including finding a term and a sum?

Identify arithmetic and geometric sequences, find a specified term using the explicit rule, and compute simple sums (Functions).

An ACT Functions answer on sequences and series: recognising arithmetic (constant difference) and geometric (constant ratio) sequences, finding the nth term with the explicit formula, and computing simple sums, with worked ACT-style questions and common traps.

Generated by Claude Opus 4.810 min answer

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  1. What this topic is asking
  2. Arithmetic sequences
  3. Geometric sequences
  4. Classifying a sequence
  5. Simple sums
  6. Recursive versus explicit rules
  7. Sequences as functions
  8. Why the nβˆ’1n - 1 matters
  9. Try this

What this topic is asking

A sequence is an ordered list of numbers following a rule. The ACT tests the two standard kinds, arithmetic (a constant difference) and geometric (a constant ratio), asking you to find a specific term or a simple sum. Recognising which kind you have, then applying its explicit formula, is the whole task.

Arithmetic sequences

An arithmetic sequence grows by a fixed amount.

Geometric sequences

A geometric sequence grows by a fixed factor.

The common ratio is r=an+1anr = \frac{a_{n+1}}{a_n}, the same between any consecutive terms, and the nnth term is an=a1β‹…rnβˆ’1a_n = a_1 \cdot r^{n-1}. For 4,12,36,…4, 12, 36, \ldots, a1=4a_1 = 4 and r=3r = 3, so the 5th term is a5=4β‹…34=4β‹…81=324a_5 = 4 \cdot 3^{4} = 4 \cdot 81 = 324. Geometric sequences are exponential in nn, which links this topic to exponential functions: the term number is the exponent (minus one).

Classifying a sequence

To decide which kind you have, test consecutive terms. If the difference is constant (9βˆ’5=13βˆ’9=49 - 5 = 13 - 9 = 4), it is arithmetic. If the ratio is constant (63=126=2\frac{6}{3} = \frac{12}{6} = 2), it is geometric. Some sequences are neither, such as 1,4,9,161, 4, 9, 16 (the squares), where neither the difference nor the ratio is constant. Checking both a difference and a ratio on the first few terms quickly tells you the type.

Simple sums

The ACT occasionally asks for a sum. A short arithmetic sum can be added directly, or use that the sum of nn terms equals nn times the average of the first and last terms: Sn=nβ‹…a1+an2S_n = n \cdot \frac{a_1 + a_n}{2}. For 1+2+β‹―+101 + 2 + \cdots + 10, this is 10β‹…1+102=5510 \cdot \frac{1 + 10}{2} = 55. For a short geometric sum, adding the listed terms directly is usually fastest on the ACT. Recognising the "average of first and last, times count" shortcut handles most arithmetic-sum questions without a long addition.

Recursive versus explicit rules

A sequence can be described two ways. A recursive rule gives the next term from the previous one, such as a1=5a_1 = 5, an=anβˆ’1+4a_n = a_{n-1} + 4 (arithmetic) or an=2anβˆ’1a_n = 2 a_{n-1} (geometric). An explicit rule gives any term directly from nn, such as an=5+(nβˆ’1)4a_n = 5 + (n - 1)4. Recursive rules are easy to read but slow for a far-off term, since you must build up term by term; the explicit rule jumps straight to the answer. When a question asks for the 50th term, convert a recursive description to the explicit formula first, rather than listing 50 terms.

Sequences as functions

A sequence is really a function whose inputs are the term numbers 1,2,3,…1, 2, 3, \ldots An arithmetic sequence is a linear function of nn (constant difference, like a slope), and a geometric sequence is an exponential function of nn (constant ratio, like a growth factor). This link explains the formulas: an=a1+(nβˆ’1)da_n = a_1 + (n-1)d mirrors y=mx+by = mx + b, and an=a1rnβˆ’1a_n = a_1 r^{n-1} mirrors y=abxy = a b^{x}. Seeing sequences this way connects the topic to the rest of the Functions area and makes the explicit rules easier to remember.

Why the nβˆ’1n - 1 matters

The single most reliable point of care is the (nβˆ’1)(n - 1) in both explicit formulas. Because the first term is n=1n = 1, it has had no additions (arithmetic) or no multiplications (geometric) applied, so the 55th term involves 44 steps, not 55. Writing an=a1+(nβˆ’1)da_n = a_1 + (n - 1)d or a1β‹…rnβˆ’1a_1 \cdot r^{n-1} and substituting carefully prevents the off-by-one error that is the most common mistake on these questions.

Try this

Q1. Find the 8th term of the arithmetic sequence 3,7,11,…3, 7, 11, \ldots [1 point]

  • Cue. a8=3+(8βˆ’1)(4)=3+28=31a_8 = 3 + (8 - 1)(4) = 3 + 28 = 31.

Q2. Find the 4th term of the geometric sequence 5,10,20,…5, 10, 20, \ldots [1 point]

  • Cue. a4=5β‹…23=5β‹…8=40a_4 = 5 \cdot 2^{3} = 5 \cdot 8 = 40.

Exam-style practice questions

Practice questions written in the style of ACT exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

ACT Math (style)1 marksIn the arithmetic sequence 5, 9, 13, 17, ..., what is the 10th term? (A) 41 (B) 45 (C) 37 (D) 50
Show worked answer β†’

The correct answer is (A), 41.

The first term is a1=5a_1 = 5 and the common difference is d=4d = 4. The explicit rule is an=a1+(nβˆ’1)da_n = a_1 + (n - 1)d, so a10=5+(10βˆ’1)(4)=5+36=41a_{10} = 5 + (10 - 1)(4) = 5 + 36 = 41. Choice (B) uses 5+10Γ—45 + 10 \times 4, forgetting the (nβˆ’1)(n - 1).

ACT Math (style)1 marksIn the geometric sequence 3, 6, 12, 24, ..., what is the 6th term? (A) 48 (B) 96 (C) 192 (D) 72
Show worked answer β†’

The correct answer is (B), 96.

The first term is a1=3a_1 = 3 and the common ratio is r=2r = 2. The explicit rule is an=a1β‹…rnβˆ’1a_n = a_1 \cdot r^{n-1}, so a6=3β‹…25=3β‹…32=96a_6 = 3 \cdot 2^{5} = 3 \cdot 32 = 96. Choice (C) uses 262^{6} instead of 252^{5}.

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