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How do you perform basic vector and matrix operations on the ACT?

Add, subtract and scalar-multiply vectors and matrices, find a vector's magnitude, and multiply small matrices (Number and Quantity).

An ACT Number and Quantity answer on vectors and matrices: adding, subtracting and scaling vectors, finding magnitude, and adding, scaling and multiplying small matrices, with worked ACT-style questions and common traps.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. Vector operations
  3. Magnitude is the Pythagorean theorem
  4. Matrix operations
  5. Matrix multiplication
  6. Why these stay simple on the ACT
  7. Try this

What this topic is asking

The ACT includes a small number of vector and matrix questions in the Number and Quantity area. They test basic operations only: adding and scaling vectors, a vector's magnitude, and adding, scaling and multiplying small matrices. None require deep linear algebra, so a handful of mechanical rules covers what appears.

Vector operations

A vector lists components, usually written a,b\langle a, b \rangle or as a column.

Geometrically, adding vectors places them tip to tail, but on the ACT the component arithmetic is all you need.

Magnitude is the Pythagorean theorem

The magnitude of a,b\langle a, b \rangle is the length of the arrow from the origin to the point (a,b)(a, b), which by the Pythagorean theorem is a2+b2\sqrt{a^{2} + b^{2}}. For 6,8\langle 6, 8 \rangle this is 36+64=100=10\sqrt{36 + 64} = \sqrt{100} = 10. Recognising the common right-triangle triples (3-4-5, 6-8-10, 5-12-13) lets you read many magnitudes instantly.

Matrix operations

A matrix is a rectangular array; its size is rows by columns.

Addition and subtraction require matching sizes; you cannot add a 2-by-2 matrix to a 2-by-3 matrix.

Matrix multiplication

Multiplying matrices is the one operation with a twist. To find the entry in row ii, column jj of the product, take row ii of the first matrix and column jj of the second, multiply matching entries, and add. For two 2-by-2 matrices:

[abcd][efgh]=[ae+bgaf+bhce+dgcf+dh].\begin{bmatrix} a & b \\ c & d \end{bmatrix}\begin{bmatrix} e & f \\ g & h \end{bmatrix} = \begin{bmatrix} ae+bg & af+bh \\ ce+dg & cf+dh \end{bmatrix}.

The inner dimensions must match (the first matrix's column count equals the second's row count), and the product has the outer dimensions. Matrix multiplication is not commutative: ABAB usually does not equal BABA.

Why these stay simple on the ACT

ACT vector and matrix questions reward knowing the mechanical rules, not theory. The two reliable checks are to operate component by component (or entry by entry) for sums and scalar multiples, and to remember that magnitude is a square root of a sum of squares. For the rare matrix-multiplication item, work one entry at a time using "row times column", and confirm the sizes are compatible before you start.

Try this

Q1. If w=2,5\vec{w} = \langle -2, 5 \rangle, what is 3w3\vec{w}? [1 point]

  • Cue. Multiply each component by 3: 6,15\langle -6, 15 \rangle.

Q2. Find the magnitude of 5,12\langle 5, 12 \rangle. [1 point]

  • Cue. 25+144=169=13\sqrt{25 + 144} = \sqrt{169} = 13 (a 5-12-13 triple).

Exam-style practice questions

Practice questions written in the style of ACT exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

ACT Math (style)1 marksIf u=3,1\vec{u} = \langle 3, -1 \rangle and v=2,4\vec{v} = \langle 2, 4 \rangle, what is u+v\vec{u} + \vec{v}? (A) 5,3\langle 5, 3 \rangle (B) 1,5\langle 1, -5 \rangle (C) 6,4\langle 6, -4 \rangle (D) 5,3\langle 5, -3 \rangle
Show worked answer →

The correct answer is (A), 5,3\langle 5, 3 \rangle.

Add vectors component by component: the first components 3+2=53 + 2 = 5, the second components 1+4=3-1 + 4 = 3. So u+v=5,3\vec{u} + \vec{v} = \langle 5, 3 \rangle. Choice (C) multiplies the components instead of adding them.

ACT Math (style)1 marksWhat is the magnitude of the vector 6,8\langle 6, 8 \rangle? (A) 10 (B) 14 (C) 48 (D) 100
Show worked answer →

The correct answer is (A), 10.

The magnitude is x2+y2=62+82=36+64=100=10\sqrt{x^{2} + y^{2}} = \sqrt{6^{2} + 8^{2}} = \sqrt{36 + 64} = \sqrt{100} = 10. This is the Pythagorean theorem applied to the components. Choice (B) adds the components; (D) forgets the square root.

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