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United StatesPhysics C: MechanicsSyllabus dot point

How do we represent the forces acting on an object with a free-body diagram, and how do we resolve those forces to set up the equations of motion?

Topic 2.2 Forces and Free-Body Diagrams: identify the forces acting on a chosen object, represent them on a free-body diagram, and resolve them into components on chosen axes to find the net force.

A focused answer to AP Physics C: Mechanics Topic 2.2, covering contact and field forces, drawing a correct free-body diagram showing only the forces on the chosen object, choosing convenient axes (including tilted axes on an incline), and resolving forces into components to compute the net force, with worked examples.

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  1. What this topic is asking
  2. Contact and field forces
  3. Drawing a correct free-body diagram
  4. Choosing axes and resolving
  5. Try this

What this topic is asking

The College Board (Topic 2.2) wants you to identify the forces acting on a chosen object, represent them on a free-body diagram, and resolve them into components on convenient axes to find the net force. The free-body diagram is the single most important habit in the course: nearly every dynamics problem, from inclines to pulleys to circular motion, begins with one, and AP graders award points for it directly.

Contact and field forces

The forces in AP Physics C: Mechanics fall into two kinds. Field forces act at a distance, chiefly gravity (weight mgmg). Contact forces act where objects touch: the normal force perpendicular to a surface, friction along it, tension in ropes, the spring force, and any applied push or pull. Drag (a resistive force) also acts on objects moving through a fluid. Every force on a free-body diagram must have an identifiable source, another object that exerts it.

Drawing a correct free-body diagram

The discipline is to ask, for each candidate arrow, "what object exerts this force on my object?" If you cannot name a source, the arrow does not belong. In AP Physics C the convention is to draw each force as a single straight arrow from the dot, not broken into components on the diagram itself; you resolve into components in the equations afterwards. Getting this right prevents the most common error in the course, inventing a forward "force of motion."

Choosing axes and resolving

Once the diagram is drawn, pick a coordinate system and resolve every force onto it. The smart choice often is not horizontal and vertical: on an incline, tilt the axes so one points along the slope and the other perpendicular to it, so the normal force and the acceleration each lie along an axis. With angle θ\theta, the weight resolves into mgsinθmg\sin\theta along the slope (down it) and mgcosθmg\cos\theta perpendicular (into it). Then the net force on each axis is the algebraic sum of the components:

Fnet,x=Fx,Fnet,y=Fy.F_{net,x} = \sum F_x, \qquad F_{net,y} = \sum F_y.

These net components feed straight into Newton's second law, Fnet,x=maxF_{net,x} = ma_x and Fnet,y=mayF_{net,y} = ma_y, in the next topic.

Try this

Q1. List every force on a book resting on a horizontal table, and name the object that exerts each. [2 points]

  • Cue. Weight (Earth, down) and normal force (table, up). With no horizontal push there is no friction.

Q2. A 5.05.0 kg sign hangs from two symmetric cables each at 3030^\circ from the horizontal. Calculate the tension in each cable (g=9.8g = 9.8 m/s squared). [3 points]

  • Cue. Vertical balance: 2Tsin30=mg2T\sin 30^\circ = mg, so T=(5.0)(9.8)2(0.5)=49T = \dfrac{(5.0)(9.8)}{2(0.5)} = 49 N.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2022 (style)4 marksSection II (FRQ, representation). A block of mass mm is held at rest on a frictionless incline of angle θ\theta by a horizontal applied force F\vec{F}. (a) Draw a free-body diagram of the block. (b) Choosing axes along and perpendicular to the incline, write the two equilibrium equations. (c) Derive an expression for the magnitude of F\vec{F} in terms of mm, gg and θ\theta.
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A 4-point FRQ on drawing and using a free-body diagram.

(a) Free-body diagram (1 point): three forces from a single point - weight mgmg straight down, normal force NN perpendicular to the incline surface, and the horizontal applied force FF. No other forces (frictionless).
(b) Equilibrium equations (2 points): with axes along (xx) and perpendicular (yy) to the slope, resolve. Along the slope: Fcosθmgsinθ=0F\cos\theta - mg\sin\theta = 0. Perpendicular: NmgcosθFsinθ=0N - mg\cos\theta - F\sin\theta = 0.
(c) Solve for FF (1 point): from the along-slope equation, F=mgtanθF = mg\tan\theta.

Markers reward a diagram with exactly the three real forces and a clean resolution onto tilted axes.

AP 2020 (style)1 marksSection I (multiple choice). Which of the following should NEVER appear on a free-body diagram of a single sliding block? (A) the normal force from the surface (B) the weight of the block (C) a 'force of motion' in the direction of travel (D) kinetic friction. Justify your reasoning.
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A 1-point conceptual MCQ. The answer is (C).

A free-body diagram shows only the real forces acting on the object: weight, normal force and friction are all real and belong. There is no 'force of motion' pushing an object along in the direction it happens to move; once moving, an object needs no forward force to continue (Newton's first law). The trap is the intuition that motion requires a sustaining force.

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