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How do elastic and inelastic collisions differ, and which quantities are conserved in each?

Topic 4.4 Collisions: analyze elastic and inelastic collisions using conservation of momentum, and distinguish them by whether kinetic energy is conserved.

A focused answer to AP Physics 1 Topic 4.4, covering elastic, inelastic and perfectly inelastic collisions, the conservation of momentum in all collisions, the conservation of kinetic energy only in elastic collisions, and solving collision problems, with full worked examples.

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  1. What this topic is asking
  2. Momentum is always conserved; kinetic energy is not
  3. The three types of collision
  4. Solving collision problems
  5. Try this

What this topic is asking

The College Board (Topic 4.4) wants you to analyze collisions using conservation of momentum, and to classify them as elastic or inelastic by asking whether kinetic energy is conserved. Momentum is conserved in every collision with no external force; kinetic energy is conserved only in elastic collisions. A perfectly inelastic collision, in which the objects stick together, loses the most kinetic energy.

Momentum is always conserved; kinetic energy is not

This split is the heart of the topic. Momentum conservation always gives you one equation (per dimension). Whether you get a second equation depends on the collision type: elastic collisions add kinetic-energy conservation, while inelastic ones do not, so you need extra information (such as the objects sticking together).

The three types of collision

Most real collisions are inelastic to some degree. A car crash, a ball of clay hitting a wall, and two railway carriages coupling are inelastic; the coupling case is perfectly inelastic. A perfectly inelastic collision is the easiest to solve, because the single common final velocity is found from momentum conservation alone.

Solving collision problems

The reliable routine is to start with momentum conservation and then decide what else you know:

  • For a perfectly inelastic collision, the objects share one final velocity, so momentum conservation alone gives it: m1v1+m2v2=(m1+m2)vfm_1 v_1 + m_2 v_2 = (m_1 + m_2)v_f.
  • For an elastic collision, write both momentum conservation and kinetic-energy conservation, giving two equations for the two unknown final velocities.
  • For a general inelastic collision, you usually need additional data (such as one final velocity) since kinetic energy is not conserved.

To check the type after solving, compare the total kinetic energy before and after: if it is unchanged the collision is elastic, if it drops it is inelastic, and the amount lost is the mechanical energy converted to heat and sound. This connects directly to the energy bookkeeping of Topic 3.4: the kinetic energy "lost" in an inelastic collision is not destroyed, it becomes thermal and other internal energy, so total energy is still conserved even though mechanical energy is not. Two-dimensional collisions (such as glancing impacts) are handled by conserving momentum in each direction separately, since momentum is a vector. The strategic insight for the exam is that momentum conservation is the universal first step in every collision, and the question's wording, "stick together", "bounce elastically", "lose energy", tells you whether and how to bring in kinetic energy.

Try this

Q1. A 3.03.0 kg cart at 2.02.0 m/s collides with and sticks to a 1.01.0 kg cart at rest. Calculate the common final speed. [2 points]

  • Cue. pi=(3.0)(2.0)=6.0p_i = (3.0)(2.0) = 6.0; pf=(4.0)vp_f = (4.0)v, so v=6.0/4.0=1.5v = 6.0/4.0 = 1.5 m/s.

Q2. In a collision the total kinetic energy before is 2020 J and after is 2020 J. State whether the collision is elastic or inelastic. [1 point]

  • Cue. Kinetic energy is unchanged, so the collision is elastic.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2024 (style)6 marksSection II (short FRQ, quantitative). A 2.02.0 kg cart moving right at 3.03.0 m/s collides with and sticks to a 1.01.0 kg cart at rest. Take right as positive. (a) Calculate the common velocity of the two carts after the collision. (b) Calculate the kinetic energy before and after the collision. (c) State whether the collision is elastic or inelastic and justify your answer using your results.
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A 6-point FRQ on a perfectly inelastic collision.

(a) Common velocity (2 points): momentum is conserved. pi=(2.0)(3.0)+(1.0)(0)=6.0p_i = (2.0)(3.0) + (1.0)(0) = 6.0 kgâ‹…\cdotm/s. After sticking, pf=(2.0+1.0)vp_f = (2.0 + 1.0)v, so 6.0=3.0v6.0 = 3.0v and v=2.0v = 2.0 m/s (right).
(b) Kinetic energy (2 points): before, Ki=12(2.0)(3.0)2=9.0K_i = \tfrac{1}{2}(2.0)(3.0)^2 = 9.0 J. After, Kf=12(3.0)(2.0)2=6.0K_f = \tfrac{1}{2}(3.0)(2.0)^2 = 6.0 J.
(c) Type (2 points): kinetic energy fell from 9.09.0 J to 6.06.0 J, so 3.03.0 J was lost; kinetic energy is not conserved. The collision is inelastic (in fact perfectly inelastic, since the carts stick together).

Markers reward momentum conservation for the velocity, kinetic energies before and after, and identifying the collision as inelastic from the energy loss.

AP 2022 (style)1 marksSection I (multiple choice). In which type of collision is kinetic energy conserved? (A) all collisions (B) perfectly inelastic only (C) elastic only (D) inelastic only. Justify your reasoning.
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A 1-point MCQ on the defining property of collision types. The answer is (C).

Momentum is conserved in every collision (with no external force), but kinetic energy is conserved only in an elastic collision. Inelastic collisions lose kinetic energy to heat, sound and deformation, and a perfectly inelastic collision (objects stick) loses the most. The trap is assuming kinetic energy is conserved whenever momentum is; only elastic collisions conserve both.

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