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How do you use a confidence interval for a proportion to justify a claim about the population?

Topic 6.3 Justifying a Claim Based on a Confidence Interval for a Population Proportion: use a confidence interval for a proportion to evaluate whether a claimed value is plausible, and discuss the effect of confidence level and sample size on the interval.

A focused answer to AP Statistics Topic 6.3, on using a one-sample proportion confidence interval to judge whether a claimed value of p is plausible, and explaining how confidence level and sample size change the interval, with worked justifications.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. The plausible-values logic
  3. Reading the whole interval, not an endpoint
  4. How confidence level changes the interval
  5. How sample size changes the interval
  6. Try this

What this topic is asking

The College Board (Topic 6.3) wants you to use a confidence interval for a proportion to justify a claim: decide whether a claimed value of pp is plausible (is it inside the interval?), and explain how the confidence level and sample size affect the interval's width and the conclusion.

The plausible-values logic

This is the bridge from estimation to decision. You do not need a separate test to assess a single claimed value: check whether it falls within the interval. A two-sided significance test at significance level α=1C\alpha = 1 - C reaches the same verdict, which is why Topic 6.3 previews the duality with hypothesis testing in Topic 6.6.

Reading the whole interval, not an endpoint

A common error is to judge a claim by whether it is "close to" an endpoint. The rule is strictly inside or outside. Equally, when a claim is directional ("at least 0.300.30" or "more than half"), you must read the entire interval against it. If a claim is "more than 0.500.50" and the interval is (0.52,0.60)(0.52, 0.60), every plausible value exceeds 0.500.50, so the data support the claim. If the interval is (0.48,0.56)(0.48, 0.56), some plausible values are below 0.500.50, so the data do not establish that the proportion exceeds 0.500.50, even though the point estimate does. The interval, not the point estimate, carries the justification.

How confidence level changes the interval

Raising confidence from 90%90\% to 99%99\% raises zz^{*} from 1.6451.645 to 2.5762.576, widening the interval around the same p^\hat{p}. The trade-off is real: more confidence (more often correct) costs precision (a wider, less informative interval). A wider interval makes more claimed values plausible, so it is less able to rule a claim out; a narrower one is more decisive but correct less often. Exam questions ask you to predict and explain this direction, not just compute.

How sample size changes the interval

A larger sample shrinks the standard error p^(1p^)/n\sqrt{\hat{p}(1-\hat{p})/n}, so for a fixed confidence level the margin of error and width decrease. Precision improves with n\sqrt{n}: to halve the margin of error you must quadruple the sample. A larger sample therefore yields a narrower interval that can exclude (rule out) more claimed values, sharpening any justification. Crucially, a larger sample changes precision, not the center on average, so it does not bias the estimate toward any claim; it just makes the interval more informative.

Try this

Q1. A 95%95\% interval for pp is (0.22,0.30)(0.22, 0.30). Is a claimed value of p=0.25p = 0.25 plausible? [1 point]

  • Cue. Yes; 0.250.25 lies inside the interval, so it is a plausible value of pp.

Q2. Holding confidence fixed, how does increasing the sample size affect the ability to rule out a claim? [1 point]

  • Cue. It narrows the interval, so more claimed values fall outside and can be ruled out; the justification becomes more decisive.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2017 (style)1 marksSection I (multiple choice). A 95%95\% confidence interval for a population proportion is (0.41, 0.49)(0.41,\ 0.49). A manufacturer claims the proportion is 0.500.50. Based on the interval, the claim is (A) supported, because 0.500.50 is close to the interval (B) not plausible, because 0.500.50 is not in the interval (C) confirmed true (D) impossible to assess
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The correct answer is (B).

Because 0.500.50 lies outside the 95%95\% interval (0.41,0.49)(0.41, 0.49), values that plausible would have included it; since it is excluded, 0.500.50 is not a plausible value for pp at this confidence level.

(A) misjudges "close": being outside the interval is what matters. (C) overstates: an interval never confirms a value as true. (D) is wrong: the interval is exactly the tool for this judgement.

AP 2021 (style)4 marksSection II (free response). A consumer group constructs a 99%99\% confidence interval for the proportion pp of a brand's chips that are broken, obtaining (0.08, 0.14)(0.08,\ 0.14) from a random sample of n=600n = 600. (a) The company claims at most 10%10\% of chips are broken. Justify in context whether the interval supports the claim. (b) Explain how the interval would change if the group had used a 90%90\% confidence level instead, and why. (c) Explain how the interval would change with a larger sample, holding everything else fixed.
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A 4-point justification-and-effects question.

(a) (2 points) The interval (0.08,0.14)(0.08, 0.14) contains values both below and above 0.100.10, so 0.100.10 is a plausible value of pp, but so are values above 0.100.10. The data do not rule out a broken-chip proportion exceeding 10%10\%, so the interval does not clearly support the claim of "at most 10%10\%"; the claim is plausible but not established.
(b) (1 point) A 90%90\% interval uses a smaller zz^{*} (1.6451.645 vs 2.5762.576), so it would be narrower, centered on the same p^\hat{p}.
(c) (1 point) A larger nn shrinks the standard error p^(1p^)/n\sqrt{\hat{p}(1-\hat{p})/n}, so the margin of error and the interval width would decrease, giving a more precise estimate.

Markers reward judging the claim against the whole interval, and correctly linking lower confidence and larger samples to a narrower interval.

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