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How do you state the hypotheses and check the conditions for a significance test about a population proportion?

Topic 6.4 Setting Up a Test for a Population Proportion: state null and alternative hypotheses about a population proportion, identify the significance level, and verify the conditions for a one-sample z-test.

A focused answer to AP Statistics Topic 6.4, on writing the null and alternative hypotheses for a population proportion, choosing the significance level, and checking the random, large-counts (using the null value), and 10% conditions for a one-sample z-test.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. Hypotheses are about the parameter
  3. Choosing the significance level
  4. Checking the conditions, with the null twist
  5. Why the setup must come first
  6. Try this

What this topic is asking

The College Board (Topic 6.4) wants you to set up a significance test for a population proportion: write the null and alternative hypotheses about pp, identify the significance level α\alpha, and check the conditions for the one-sample z-test, using the null value p0p_0 in the large-counts check.

Hypotheses are about the parameter

Hypotheses always concern the population proportion pp, never the statistic p^\hat{p}; p^\hat{p} is the evidence we will weigh, not the claim. The null is an equality at the boundary value p0p_0. Choose the alternative from the wording: "more than" gives >>, "less than" gives <<, "different from" or "changed" gives \ne. Always define pp in words first ("let pp be the true proportion of ... who ...") so the hypotheses are anchored in context.

Choosing the significance level

You set α\alpha in advance to fix how much risk of a false alarm you will accept. A high-stakes decision (a costly or harmful wrong rejection) calls for a small α\alpha like 0.010.01. The level chosen here is the line a P-value (Topic 6.5) will be compared against to reach a conclusion (Topic 6.6).

Checking the conditions, with the null twist

The distinctive feature of a test (versus an interval) is that the large-counts check and the standard deviation use the null value p0p_0, because the entire test is conducted under the assumption that H0H_0 is true. This contrasts with the interval of Topic 6.2, which used the observed p^\hat{p}. Mixing these up is one of the most common setup errors, so name p0p_0 explicitly. The same p0p_0 will appear in the standard deviation p0(1p0)/n\sqrt{p_0(1-p_0)/n} of the test statistic in Topic 6.6.

Why the setup must come first

The conclusion of a test is only as trustworthy as its setup. Clearly defined hypotheses about pp keep you from testing the wrong thing; a stated α\alpha prevents you from moving the goalposts after seeing the data; and checked conditions earn the normal model that the P-value depends on. Examiners award setup points independently, and a missing condition or a hypothesis about p^\hat{p} loses marks even if the later arithmetic is correct.

Try this

Q1. A claim is that exactly 25%25\% of items pass; you suspect the rate has changed. Write the hypotheses. [1 point]

  • Cue. H0:p=0.25H_0: p = 0.25 versus Ha:p0.25H_a: p \ne 0.25 (two-sided, because "changed").

Q2. In the large-counts check for a test, do you use p^\hat{p} or p0p_0, and why? [1 point]

  • Cue. Use p0p_0; the test reasons under the assumption that H0H_0 is true, so normality is checked at the null value.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2018 (style)1 marksSection I (multiple choice). A company claims that more than 30%30\% of customers reorder. To test this with a sample, the hypotheses should be (A) H0:p^=0.30H_0: \hat{p} = 0.30, Ha:p^>0.30H_a: \hat{p} > 0.30 (B) H0:p=0.30H_0: p = 0.30, Ha:p0.30H_a: p \ne 0.30 (C) H0:p=0.30H_0: p = 0.30, Ha:p>0.30H_a: p > 0.30 (D) H0:p>0.30H_0: p > 0.30, Ha:p=0.30H_a: p = 0.30
Show worked answer →

The correct answer is (C).

Hypotheses are about the parameter pp, not the statistic p^\hat{p}. The null is the status-quo equality H0:p=0.30H_0: p = 0.30; the alternative matches the claim "more than 30%30\%," so Ha:p>0.30H_a: p > 0.30.

(A) wrongly uses p^\hat{p}. (B) is two-sided, not matching "more than." (D) reverses the roles of null and alternative.

AP 2020 (style)3 marksSection II (free response). A health official suspects that fewer than 40%40\% of a region's adults meet an activity guideline. A random sample of n=350n = 350 adults is taken. (a) State the hypotheses in context. (b) Check the conditions for a one-sample z-test for a proportion, using the appropriate value in the large-counts check. (c) State what significance level you would use and what it represents.
Show worked answer →

A 3-point set-up question.

(a) (1 point) Let pp be the true proportion of the region's adults who meet the guideline. H0:p=0.40H_0: p = 0.40 versus Ha:p<0.40H_a: p < 0.40 ("fewer than 40%40\%").
(b) (1 point) Random: stated random sample. Large counts using the null value p0=0.40p_0 = 0.40: np0=350(0.40)=14010np_0 = 350(0.40) = 140 \ge 10 and n(1p0)=350(0.60)=21010n(1-p_0) = 350(0.60) = 210 \ge 10. The 10%10\% condition: 350350 is plausibly under 10%10\% of the region's adults.
(c) (1 point) Use α=0.05\alpha = 0.05 (a common choice); it is the probability of rejecting H0H_0 when it is actually true (a Type I error rate) that we are willing to tolerate.

Markers reward hypotheses about pp in context, the large-counts check using p0p_0, and a correct meaning of α\alpha.

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