Why must a chemical equation be balanced, and how does balancing express the conservation of mass?
Write and balance chemical equations, and use them to show that atoms and mass are conserved in a reaction (MA STE HS-PS1-7(MA), conservation of mass).
A standard-level answer on balancing chemical equations and the conservation of mass for Massachusetts high school chemistry: reading a formula equation, balancing by coefficients, and using the balanced equation to show atoms and mass are conserved, grounded in HS-PS1-7(MA).
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What this topic is asking
Standard HS-PS1-7(MA) asks you to use the formula of an equation to show that the mass of the reactants equals the mass of the products. The skill underneath it is balancing equations: adjusting coefficients until every kind of atom appears in equal numbers on both sides. Once an equation is balanced, it becomes a model of the conservation of mass and the starting point for every calculation in this module.
Reading a chemical equation
A chemical equation shows reactants on the left, products on the right, and an arrow meaning "produces". For example:
Two pieces of notation matter:
- A subscript (the small number, as in ) tells you how many atoms are in one molecule. It is fixed by the substance: is oxygen gas, is ozone.
- A coefficient (the big number in front, as in ) tells you how many of that whole unit take part. Coefficients are what you adjust to balance.
The golden rule: balance with coefficients, never by editing subscripts. Changing to to "get more oxygen" turns water into hydrogen peroxide, a different substance.
The law of conservation of mass
This is why an equation must balance. Antoine Lavoisier established it in the 1700s by reacting substances in sealed vessels and weighing them: the mass never changed. If a reaction appears to lose mass (wood burning to a small pile of ash) or gain mass (steel wool rusting), it is because a gas has left or joined the system. Carry the reaction out in a closed system and the balance holds exactly.
How to balance an equation
A reliable routine for a first chemistry course:
- Write the correct formula for every reactant and product. Do not change these afterwards.
- Count the atoms of each element on each side.
- Add coefficients to equalise the counts, one element at a time, leaving hydrogen and oxygen until last because they appear in many compounds.
- Recount every element to check, then reduce the coefficients to the smallest whole-number ratio.
Balancing tells you the conservation of mass
Once balanced, the equation is a statement that mass is conserved. In , the same 4 carbon, 12 hydrogen, and 14 oxygen atoms exist on both sides. Because each atom keeps its mass, the total mass of reactants equals the total mass of products. This is the bridge to stoichiometry: the coefficients give the exact ratio in which substances react, developed in stoichiometric calculations.
Try this
Q1. Balance . [1]
- Cue. (4 aluminum, 6 oxygen each side).
Q2. A candle loses mass as it burns in open air. Does this break the law of conservation of mass? Explain. [2]
- Cue. No; the products carbon dioxide and water vapor escape as gases, so they are not weighed. In a closed system the total mass would be unchanged.
Exam-style practice questions
Practice questions written in the style of MA DESE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
MA Chemistry (style)3 marksPropane burns in oxygen: . (a) Balance the equation. (b) State the law it illustrates. (c) Explain how the balanced equation shows that law.Show worked answer β
A 3-point item on balancing and conservation of mass.
(a) 1 point: (3 carbon, 8 hydrogen, 10 oxygen on each side).
(b) 1 point: the law of conservation of mass.
(c) 1 point: every atom present in the reactants reappears in the products, just rearranged, so the same number of each kind of atom (and therefore the same total mass) exists before and after. Markers reward linking equal atom counts to equal mass.
MA Chemistry (style)2 marksIn a sealed flask, 8 g of methane reacts completely with 32 g of oxygen. (a) State the total mass of products. (b) Justify your answer.Show worked answer β
A 2-point item testing conservation of mass in a closed system.
(a) 1 point: 40 g of products (8 g + 32 g).
(b) 1 point: in a closed (sealed) system no atoms can enter or leave, so by the law of conservation of mass the total mass of products must equal the total mass of reactants. Markers reward naming the closed system as the reason the masses must be equal.
Related dot points
- Classify reactions as synthesis, decomposition, single replacement, double replacement, or combustion, and predict the products from the reactants (MA STE HS-PS1-2, predicting reaction outcomes).
A standard-level answer on classifying chemical reactions for Massachusetts high school chemistry: the five main reaction types (synthesis, decomposition, single replacement, double replacement, combustion), how to recognize each, and using the type and an activity series to predict products, grounded in HS-PS1-2.
- Calculate molar mass, convert between mass, moles, and particles, and find percent composition and empirical formulas (MA STE HS-PS1-7(MA), proportional reasoning with chemical formulas).
A standard-level answer on molar mass and percent composition for Massachusetts high school chemistry: finding molar mass from a formula, converting between mass, moles, and particles with Avogadro's number, and calculating percent composition and empirical formulas, grounded in HS-PS1-7(MA).
- Use mole ratios from a balanced equation to calculate the amounts of reactants and products in mole-to-mole and mass-to-mass problems (MA STE HS-PS1-7(MA), proportional reasoning in reactions).
A standard-level answer on stoichiometric calculations for Massachusetts high school chemistry: reading mole ratios from a balanced equation and using them for mole-to-mole and mass-to-mass calculations through the mole-ratio bridge, grounded in HS-PS1-7(MA).
- Write chemical formulas by balancing ionic charges (including polyatomic ions), and name ionic and simple covalent compounds using the standard rules (MA STE HS-PS1-2 support, formulas and naming).
A standard-level answer on chemical nomenclature for Massachusetts high school chemistry: writing ionic formulas by balancing charge, using polyatomic ions, naming ionic compounds and those with multivalent metals, and naming covalent compounds with prefixes.
- Calculate average atomic mass from isotope abundances, and explain the mole and Avogadro's number as the bridge between numbers of particles and grams (MA STE HS-PS1-7 support, the mole).
A standard-level answer on average atomic mass and the mole for Massachusetts high school chemistry: weighted average atomic mass from isotope abundances, Avogadro's number, and the mole as the link between particle count and mass, supporting HS-PS1-7.
Sources & how we know this
- Massachusetts Science and Technology/Engineering Curriculum Framework (2016) β Massachusetts Department of Elementary and Secondary Education (2016)
- Science and Technology/Engineering (STE) Test Design and Development β Massachusetts Department of Elementary and Secondary Education (2024)