Skip to main content
North CarolinaMathsSyllabus dot point

How do exponential functions model growth and decay, and how do you read their parameters?

Construct and interpret exponential functions for growth and decay, and interpret their parameters in context (NC.M1.F-LE.1, F-LE.2, F-LE.5).

An NC Math 1 EOC answer on exponential functions (NC.M1.F-LE.1, F-LE.2, F-LE.5): the form a times b to the x, growth versus decay, building from two points, and interpreting the initial value and growth factor.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this topic is asking
  2. Linear versus exponential
  3. The parts of an exponential model
  4. Building an exponential function
  5. Reading growth and decay rates
  6. How the NC Math 1 EOC examines this topic
  7. Why a constant percent means exponential
  8. Try this

What this topic is asking

Three standards combine. NC.M1.F-LE.1 asks you to distinguish linear from exponential situations (constant additive change versus constant multiplicative change). NC.M1.F-LE.2 asks you to construct an exponential function from a description, a graph, or two points. NC.M1.F-LE.5 asks you to interpret the parameters (initial value and growth or decay factor) in context.

Linear versus exponential

The first decision is which model fits.

The parts of an exponential model

For f(x)=abxf(x) = ab^x:

  • aa is the initial value, the output when x=0x = 0 (since b0=1b^0 = 1).
  • bb is the growth/decay factor. Growth if b>1b > 1; decay if 0<b<10 < b < 1.
  • Writing b=1+rb = 1 + r (growth) or b=1rb = 1 - r (decay) shows the rate rr as a percent.

A balance growing 4%4\% a year from \500is is y = 500(1.04)^t;apopulationfalling; a population falling 10%ayearfrom a year from 800is is y = 800(0.90)^t$.

Building an exponential function

Reading growth and decay rates

The growth factor and the rate are related but different. A factor of 1.041.04 is a 4%4\% growth rate (r=0.04r = 0.04); a factor of 0.880.88 is a 12%12\% decay rate (r=0.12r = 0.12). To find the rate, compare the factor to 11: subtract for growth, or subtract from 11 for decay.

How the NC Math 1 EOC examines this topic

  • Gridded response. Evaluate an exponential model at a given input.
  • Multiple choice. Choose the exponential function for a context, or identify growth versus decay.
  • Calculator-active. Exponential evaluations usually sit in the calculator-active section.

Exponential functions are the continuous cousins of geometric sequences (the common ratio is the growth factor) and are central to comparing function families. Evaluating abxab^x uses the exponent properties.

Why a constant percent means exponential

The deep distinction in F-LE.1 is between adding and multiplying. Linear growth adds the same amount each step, so it climbs at a steady pace. Exponential growth multiplies by the same factor each step, so the increase itself grows: 4%4\% of a larger balance is a larger dollar amount than 4%4\% of a smaller one. That is why exponential graphs curve upward ever more steeply (or, for decay, flatten toward zero), while linear graphs stay straight. Recognizing "constant percent" or "doubling" or "halving" as the fingerprint of exponential behavior lets you pick the right model immediately, which is the most common decision the EOC tests in this strand.

Try this

Q1. Write a function for a \1000investmentgrowing investment growing 5%$ per year. [1 point]

  • Cue. y=1000(1.05)ty = 1000(1.05)^t (factor 1+0.05=1.051 + 0.05 = 1.05).

Q2. A substance halves every day, starting at 8080 g. Find the amount after 33 days. [2 points]

  • Cue. y=80(0.5)ty = 80(0.5)^t; y=80(0.5)3=80(0.125)=10y = 80(0.5)^3 = 80(0.125) = 10 g.

Exam-style practice questions

Practice questions written in the style of NCDPI exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

NC Math 1 EOC (style)2 marksA car worth \20{,}000loses loses 12\%ofitsvalueeachyear.Writeafunctionforitsvalue of its value each year. Write a function for its value Vafter after tyears,andfindthevalueafter years, and find the value after 2$ years.
Show worked answer →

The function is V=20000(0.88)tV = 20000(0.88)^t, and after 22 years the value is \15{,}488$.

Decay multiplies by (1r)(1 - r) each year. Here r=0.12r = 0.12, so the decay factor is 10.12=0.881 - 0.12 = 0.88, and V=20000(0.88)tV = 20000(0.88)^t. For t=2t = 2: V=20000(0.88)2=20000(0.7744)=15488V = 20000(0.88)^2 = 20000(0.7744) = 15488. Identifying the initial value and the decay factor is the F-LE.2 and F-LE.5 skill.

NC Math 1 EOC (style)1 marksWhich situation is exponential rather than linear? (A) save \20eachweek(B)abalancegrows each week (B) a balance grows 3\%eachyear(C)walk each year (C) walk 4milesperhour(D)add miles per hour (D) add 5$ each step
Show worked answer →

The correct answer is (B), a balance grows 3%3\% each year.

A constant percent change (a constant multiplicative rate) is exponential. Options (A), (C), and (D) add a fixed amount each step, a constant difference, which is linear. Distinguishing constant additive change (linear) from constant multiplicative change (exponential) is the F-LE.1 idea.

Related dot points

Sources & how we know this