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How do you write arithmetic and geometric sequences recursively and explicitly?

Recognize sequences as functions and write arithmetic and geometric sequences both recursively and explicitly (NC.M1.F-IF.3, F-BF.2).

An NC Math 1 EOC answer on sequences (NC.M1.F-IF.3, F-BF.2): the common difference and common ratio, explicit and recursive rules, sequences as functions on the integers, and finding a term.

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  1. What this topic is asking
  2. Two kinds of sequence
  3. Explicit versus recursive rules
  4. Writing an arithmetic sequence
  5. Writing a geometric sequence
  6. How the NC Math 1 EOC examines this topic
  7. Why sequences are functions in disguise
  8. Try this

What this topic is asking

NC.M1.F-IF.3 says sequences are functions whose domain is a subset of the integers. NC.M1.F-BF.2 asks you to write arithmetic and geometric sequences both recursively (in terms of the previous term) and explicitly (in terms of nn), and to translate between the forms. Sequences connect to linear functions (arithmetic) and exponential functions (geometric).

Two kinds of sequence

The difference is whether you add or multiply.

To tell them apart: subtract consecutive terms (constant difference means arithmetic) or divide consecutive terms (constant ratio means geometric).

Explicit versus recursive rules

Both forms describe the same sequence but answer different questions.

  • Explicit gives the nnth term directly from nn: best for "find the 5050th term."
  • Recursive gives each term from the previous one: best for showing the step-by-step pattern.

Since NC Math 1 provides no reference sheet, memorize both explicit forms.

Writing an arithmetic sequence

Writing a geometric sequence

For 2,6,18,54,…2, 6, 18, 54, \ldots: a1=2a_1 = 2 and r=3r = 3. The recursive rule is an=an−1⋅3a_n = a_{n-1}\cdot 3 with a1=2a_1 = 2; the explicit rule is an=2⋅3 n−1a_n = 2\cdot 3^{\,n-1}. The 55th term is a5=2⋅34=2⋅81=162a_5 = 2\cdot 3^4 = 2\cdot 81 = 162.

How the NC Math 1 EOC examines this topic

  • Gridded response. Find a specific term using the explicit rule.
  • Multiple choice. Identify the common difference or ratio, or choose the correct rule.
  • Technology-enhanced. Match sequences to rules, or fill in missing terms.

Sequences bridge two families: arithmetic sequences behave like linear functions (constant difference is like constant slope), while geometric sequences behave like exponential functions (constant ratio is like a growth factor). This link is central to comparing function families.

Why sequences are functions in disguise

Listing terms can hide the structure, but seeing a sequence as a function of its position reveals it. The arithmetic sequence 7,10,13,…7, 10, 13, \ldots is just the linear function an=3n+4a_n = 3n + 4 evaluated at n=1,2,3,…n = 1, 2, 3, \ldots; the geometric sequence 2,6,18,…2, 6, 18, \ldots is the exponential an=23⋅3na_n = \frac{2}{3}\cdot 3^{n} at integer inputs. This is why F-IF.3 places sequences inside the Functions strand: the explicit rule is a function rule with a restricted domain. Recognizing the connection means you can use everything you know about lines and exponentials, slope as common difference, growth factor as common ratio, to analyze sequences, instead of treating them as a separate topic.

Try this

Q1. Find the 88th term of the arithmetic sequence 4,9,14,…4, 9, 14, \ldots. [1 point]

  • Cue. a1=4a_1 = 4, d=5d = 5; a8=4+5(7)=39a_8 = 4 + 5(7) = 39.

Q2. Write the explicit rule for the geometric sequence 5,10,20,…5, 10, 20, \ldots. [2 points]

  • Cue. a1=5a_1 = 5, r=2r = 2; an=5â‹…2 n−1a_n = 5\cdot 2^{\,n-1}.

Exam-style practice questions

Practice questions written in the style of NCDPI exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

NC Math 1 EOC (style)2 marksAn arithmetic sequence starts 5,8,11,14,…5, 8, 11, 14, \ldots. Write an explicit rule and find the 1010th term.
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The explicit rule is an=5+(n−1)(3)a_n = 5 + (n - 1)(3), and the 1010th term is 3232.

The first term is a1=5a_1 = 5 and the common difference is d=3d = 3 (each term adds 33). The explicit rule an=a1+(n−1)da_n = a_1 + (n - 1)d gives an=5+3(n−1)a_n = 5 + 3(n - 1). For n=10n = 10: a10=5+3(9)=5+27=32a_{10} = 5 + 3(9) = 5 + 27 = 32. Identifying a1a_1 and dd, then using the explicit form, is the F-BF.2 skill.

NC Math 1 EOC (style)1 marksA geometric sequence is 3,6,12,24,…3, 6, 12, 24, \ldots. What is the common ratio? (A) 33 (B) 22 (C) 66 (D) 12\tfrac{1}{2}
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The correct answer is (B), 22.

In a geometric sequence each term is the previous one times a fixed common ratio. Here 6÷3=26 \div 3 = 2, 12÷6=212 \div 6 = 2, 24÷12=224 \div 12 = 2, so r=2r = 2. (A common difference would apply to an arithmetic sequence; this one multiplies.)

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