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Why is carbon special, and how are the hydrocarbon families organized and named?

Organic chemistry and hydrocarbons: classify alkanes, alkenes and alkynes using their general formulas, and name simple hydrocarbons using Table P and Table Q.

A focused Regents Chemistry answer on organic chemistry and hydrocarbons: why carbon forms so many compounds, the alkane, alkene and alkyne homologous series with their general formulas, isomers, and naming using the Table P and Table Q reference data.

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  1. What this topic is asking
  2. Why carbon is special
  3. The homologous series
  4. Naming simple hydrocarbons
  5. Isomers
  6. Try this

What this topic is asking

The Core Curriculum asks you to recognize that carbon forms a huge variety of compounds, to classify the hydrocarbon families (alkanes, alkenes, alkynes) by their general formulas, to understand isomers, and to name simple hydrocarbons using Table P (carbon-chain prefixes) and Table Q (the homologous series). This is the entry point to organic chemistry on the Regents.

Why carbon is special

Organic compounds are built on carbon skeletons with hydrogen and often oxygen, nitrogen or halogens attached. The Regents focuses on hydrocarbons and a set of functional groups (the next page), keeping naming at a basic level.

The homologous series

Table Q gives the general formula and bonding of each:

  • Alkanes (CnH2n+2\text{C}_n\text{H}_{2n+2}): only single carbon-carbon bonds, so they are saturated (they hold the maximum number of hydrogen atoms). Example: methane CH4\text{CH}_4, ethane C2H6\text{C}_2\text{H}_6.
  • Alkenes (CnH2n\text{C}_n\text{H}_{2n}): contain one carbon-carbon double bond, so they are unsaturated. Example: ethene C2H4\text{C}_2\text{H}_4.
  • Alkynes (CnH2nβˆ’2\text{C}_n\text{H}_{2n-2}): contain one carbon-carbon triple bond, also unsaturated. Example: ethyne C2H2\text{C}_2\text{H}_2.

Naming simple hydrocarbons

To name a hydrocarbon from its formula: count the carbons to get the prefix from Table P, then use the general formulas on Table Q to decide the series (and so the ending). For C4H10\text{C}_4\text{H}_{10}, four carbons (but-) and the alkane formula (CnH2n+2\text{C}_n\text{H}_{2n+2} with n=4n=4) give butane.

Isomers

Isomerism is part of why carbon forms so many compounds: a single formula can correspond to more than one structure once the chain has four or more carbons. The Regents asks you to recognize that isomers share a molecular formula but differ in structure.

Try this

Q1. State the general formula of the alkane series. [1 point]

  • Cue. CnH2n+2\text{C}_n\text{H}_{2n+2} (from Table Q).

Q2. Name the straight-chain alkane with four carbon atoms. [1 point]

  • Cue. Butane (but- for four carbons, -ane for an alkane).

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (Part A style)1 marksWhich is the general formula for the alkene series of hydrocarbons? (1) CnH2n+2\text{C}_n\text{H}_{2n+2} (2) CnH2n\text{C}_n\text{H}_{2n} (3) CnH2nβˆ’2\text{C}_n\text{H}_{2n-2} (4) CnHn\text{C}_n\text{H}_n
Show worked answer β†’

A 1-point Part A item on the homologous series. The answer is (2) CnH2n\text{C}_n\text{H}_{2n}.

Table Q gives the general formulas: alkanes are CnH2n+2\text{C}_n\text{H}_{2n+2} (all single bonds, saturated), alkenes are CnH2n\text{C}_n\text{H}_{2n} (one double bond), and alkynes are CnH2nβˆ’2\text{C}_n\text{H}_{2n-2} (one triple bond). The alkene formula has two fewer hydrogens than the alkane because of the double bond.

Markers reward selecting CnH2n\text{C}_n\text{H}_{2n} for the alkenes, as listed on Table Q.

Regents (Part B-2 style)3 marksA hydrocarbon has the formula C3H8\text{C}_3\text{H}_8. (a) Identify the homologous series it belongs to. (b) State its name using Table P. (c) State whether it is saturated or unsaturated, and explain.
Show worked answer β†’

A 3-point constructed-response item on naming and classifying.

(a) Series (1 point): C3H8\text{C}_3\text{H}_8 fits CnH2n+2\text{C}_n\text{H}_{2n+2} (with n=3n = 3, 2n+2=82n+2 = 8), so it is an alkane.
(b) Name (1 point): the prefix for three carbons is "prop-" (Table P), and the alkane ending is "-ane", so the name is propane.
(c) Saturated or unsaturated (1 point): it is saturated, because it contains only single carbon-carbon bonds (the maximum number of hydrogen atoms).

Markers reward identifying the alkane series from the formula, naming it with the Table P prefix and the -ane ending, and explaining that single bonds mean it is saturated.

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