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How do you rewrite algebraic expressions into equivalent forms by factoring, expanding, and using exponent rules?

Equivalent expressions: factor and expand polynomials, simplify rational expressions, apply exponent and radical rules, and rewrite an expression to reveal a needed feature.

A focused answer to the Digital SAT Advanced Math skill of equivalent expressions: factoring and expanding, the laws of exponents, simplifying rational expressions, and rewriting an expression to reveal the feature a question asks for.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this skill is asking
  2. The toolkit
  3. A worked simplification
  4. Choosing the right form
  5. Exponents and radicals
  6. Completing the square to rewrite a quadratic

What this skill is asking

Equivalent expressions questions ask you to rewrite an algebraic expression in a different but equal form: expand a product, factor a polynomial, simplify a rational expression, or apply exponent and radical rules. The Digital SAT (Advanced Math domain) uses these to test algebraic fluency, often by asking which of four forms is equal to a given one, or by asking you to rewrite an expression so a particular feature (a zero, a coefficient) becomes visible.

The toolkit

A few standard manipulations cover almost every question.

A worked simplification

Rational-expression questions reward factoring first.

Choosing the right form

The reason the SAT cares about equivalent forms is that different forms reveal different features. Factored form a(xr1)(xr2)a(x - r_1)(x - r_2) shows the zeros (r1r_1 and r2r_2) at a glance. Standard form ax2+bx+cax^2 + bx + c shows the yy-intercept (cc) and the leading behaviour. Vertex form a(xh)2+ka(x - h)^2 + k shows the vertex (h,k)(h, k), the maximum or minimum. So when a question asks "which equivalent form displays the xx-intercepts as constants", it wants factored form; when it asks for the minimum value, it wants vertex form. Matching the requested feature to the form that displays it is the real skill behind these questions.

Exponents and radicals

Many "equivalent expression" questions are really exponent-rule questions in disguise. Rewrite radicals as fractional exponents (x=x1/2\sqrt{x} = x^{1/2}, x23=x2/3\sqrt[3]{x^2} = x^{2/3}) so the exponent laws apply cleanly, then combine. For example, x5x2x1=x521=x2\frac{x^5}{x^2} \cdot x^{-1} = x^{5-2-1} = x^2, and (x1/2)4=x2(x^{1/2})^4 = x^2. A negative exponent moves a factor across the fraction bar (x3=1x3x^{-3} = \frac{1}{x^3}), and a fractional exponent is a root. Treating every radical and reciprocal as an exponent turns a tangle into one addition or multiplication of exponents.

Completing the square to rewrite a quadratic

A specific rewriting the SAT rewards is turning a quadratic from standard form into vertex form by completing the square, because vertex form displays the maximum or minimum directly. To rewrite x2+6x+1x^2 + 6x + 1, take half of the middle coefficient (62=3\frac{6}{2} = 3), square it (99), and add and subtract it: x2+6x+99+1=(x+3)28x^2 + 6x + 9 - 9 + 1 = (x + 3)^2 - 8. The expression is unchanged in value but now shows that the minimum is 8-8 at x=3x = -3. When the leading coefficient is not 11, factor it out of the xx terms first. Completing the square is also the bridge to the quadratic formula and to circle equations in the coordinate plane, so it is worth being fluent at this single rewriting move.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Digital SAT Math (style)1 marksWhich expression is equivalent to (2x+3)(x5)(2x + 3)(x - 5)? (A) 2x27x152x^2 - 7x - 15 (B) 2x210x152x^2 - 10x - 15 (C) 2x2+13x152x^2 + 13x - 15 (D) 2x27x+152x^2 - 7x + 15
Show worked answer →

The correct answer is (A), 2x27x152x^2 - 7x - 15.

Expand with FOIL: (2x)(x)+(2x)(5)+(3)(x)+(3)(5)=2x210x+3x15=2x27x15(2x)(x) + (2x)(-5) + (3)(x) + (3)(-5) = 2x^2 - 10x + 3x - 15 = 2x^2 - 7x - 15. The middle term combines 10x-10x and +3x+3x to 7x-7x.

Digital SAT Math (style)1 marksThe expression x29x+3\dfrac{x^2 - 9}{x + 3} is equivalent to which of the following for x3x \neq -3? (A) x3x - 3 (B) x+3x + 3 (C) x9x - 9 (D) 1x+3\dfrac{1}{x + 3}
Show worked answer →

The correct answer is (A), x3x - 3.

Factor the numerator as a difference of squares: x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3). Then (x3)(x+3)x+3=x3\frac{(x-3)(x+3)}{x+3} = x - 3, cancelling the common factor x+3x + 3 (valid because x3x \neq -3).

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