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How do you model a real-world situation with a system of equations or inequalities, and interpret the solution as viable constraints?

Represent constraints by systems of equations and inequalities and interpret solutions as viable or nonviable options in a modeling context (TN A1.A.CED.A.3).

A TNReady Algebra I answer on modeling with systems (TN A1.A.CED.A.3), writing two equations or inequalities from a context, solving, and interpreting the solution as a viable option.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. Setting up two equations
  3. Constraints as inequalities
  4. How TNReady examines this topic
  5. Why viability is part of the answer
  6. Try this

What this topic is asking

Standard A1.A.CED.A.3 is the modeling end of systems: represent a situation's constraints with a system of equations or inequalities, then solve and decide which solutions are viable. A system of equations pins down an exact answer (how many of each); a system of inequalities describes a feasible region of all acceptable options.

Setting up two equations

The reliable pattern: each independent fact about the situation becomes one equation. A ticket problem has a count fact and a money fact, so it yields two equations in the two unknowns.

Constraints as inequalities

When the situation involves limits rather than exact totals, use inequalities. "No more than 20 hours" is x+y20x + y \le 20; "at least 150 dollars earned" is an earnings inequality. The feasible region is the overlap, and often a hidden constraint applies: hours and counts are non-negative, so x0x \ge 0 and y0y \ge 0 usually belong to the system even when unstated.

How TNReady examines this topic

  • Numeric response. Set up and solve a two-equation system, entering one quantity.
  • Multiple choice. Choose the system (equations or inequalities) that models the constraints, with sign-direction distractors.
  • Multiple select. Choose all viable combinations from a feasible region.

A clarifying idea is that this standard reuses the solving skills from solving systems and the region skills from graphing systems; the new work is the translation from words and the viability judgement.

Why viability is part of the answer

A system can produce a mathematically correct solution that makes no sense in context, and recognizing that is graded. If a ticket model returned a=2.5a = 2.5 adult tickets, the algebra might be right but the answer is nonviable, you cannot buy half a ticket, so either the problem expects whole numbers (signaling a setup to recheck) or the scenario is impossible as stated. In a feasible-region item, only the integer points inside the region may be viable when the quantities are discrete (people, items, tickets), even though the shaded region contains infinitely many real points. Always close a modeling problem by asking whether the numbers can exist in the real situation, and report the answer with units and meaning, not just a bare value.

Try this

Q1. Two numbers sum to 3030 and differ by 88. Write a system and find them. [2 points]

  • Cue. x+y=30x + y = 30, xy=8x - y = 8; add to get 2x=382x = 38, x=19x = 19, y=11y = 11.

Q2. A vendor needs at least 100100 items total (x+yx + y) and at most 400400 dollars spent at 55 and 33 dollars each. Write the system. [2 points]

  • Cue. x+y100x + y \ge 100, 5x+3y4005x + 3y \le 400 (with x,y0x, y \ge 0).

Exam-style practice questions

Practice questions written in the style of TDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

TNReady (style)2 marksNumeric response. Adult tickets cost 88 and child tickets cost 55. A family buys 66 tickets for 3939 dollars. How many adult tickets did they buy?
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They bought 33 adult tickets.

Let aa be adult tickets and cc be child tickets. The count gives a+c=6a + c = 6, and the cost gives 8a+5c=398a + 5c = 39. Solve by substitution: c=6ac = 6 - a, so 8a+5(6a)=398a + 5(6 - a) = 39, which is 8a+305a=398a + 30 - 5a = 39, then 3a=93a = 9, so a=3a = 3. Then c=3c = 3. Defining two variables and writing one equation per piece of information (count and cost) is the modeling skill.

TNReady (style)2 marksMultiple choice. A student works at most 2020 hours per week and must earn at least 150150 dollars. Tutoring pays 1212 per hour (xx) and a shop pays 1010 per hour (yy). Which system models this? (A) x+y20, 12x+10y150x + y \le 20,\ 12x + 10y \ge 150 (B) x+y20, 12x+10y150x + y \ge 20,\ 12x + 10y \le 150 (C) x+y20, 12x+10y150x + y \le 20,\ 12x + 10y \le 150 (D) x+y=20, 12x+10y=150x + y = 20,\ 12x + 10y = 150
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The correct answer is (A).

"At most 2020 hours" limits total hours: x+y20x + y \le 20. "At least 150150 dollars" sets an earnings floor on 12x+10y12x + 10y: 12x+10y15012x + 10y \ge 150. The two constraints are inequalities, not equations (ruling out (D)), and the directions follow "at most" (\le) and "at least" (\ge). The solution region holds every viable combination of hours.

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