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TennesseeMathsSyllabus dot point

How do you write the equation of a line from a slope and a point, two points, a graph, or a context?

Write linear functions and equations of lines using slope-intercept and point-slope form, from a graph, two points, or a real-world description (TN A1.F.LE.A.2, A1.A.CED.A.2).

A TNReady Algebra I answer on writing linear functions (TN A1.F.LE.A.2, A1.A.CED.A.2), the slope formula, slope-intercept and point-slope forms, and building a line from two points or a context.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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Jump to a section
  1. What this topic is asking
  2. The slope formula and the line forms
  3. Writing a line from two points
  4. Writing a line from a context
  5. How TNReady examines this topic
  6. Why two forms, and when to convert
  7. Try this

What this topic is asking

This page covers writing a linear function from various starting points: a slope and a point, two points, a graph, or a context (A1.F.LE.A.2 and A1.A.CED.A.2). The tools are the slope formula and the slope-intercept and point-slope forms. The reference sheet gives the slope formula, but the line forms are not on it, so memorize them.

The slope formula and the line forms

Slope-intercept is best when you know the slope and the yy-intercept; point-slope is best when you know the slope and any point.

Writing a line from two points

The reliable two-step routine: find the slope, then substitute a point into point-slope.

Writing a line from a context

In a word problem, the constant rate is the slope and the fixed/starting value is the yy-intercept. "1515 per month with a 4040 setup fee" is y=15x+40y = 15x + 40. If you are given a rate and a non-starting point, use point-slope and simplify, the pool example does exactly this with a negative slope for draining.

How TNReady examines this topic

  • Equation response. Write a line in slope-intercept or point-slope form, scored by exact match.
  • Numeric response. Find the slope, the yy-intercept, or a starting value from a context.
  • Multiple choice. Choose the equation matching a graph or table, with slope-sign and intercept distractors.

A clarifying idea is that the slope is the average rate of change of a linear function, constant on every interval, and in a data setting it is the slope of the linear model fitted to points. The same number appears across the Functions and Statistics categories.

Why two forms, and when to convert

Slope-intercept and point-slope describe the same line, so why keep both? Because each is fastest for a different starting point. If you already know where the line crosses the yy-axis, slope-intercept is immediate. If you know the slope and some other point, point-slope lets you write the equation in one step without solving for bb. The test often supplies a slope and a point that is not the yy-intercept, which is exactly when point-slope shines, you plug in and simplify. Converting between the forms is just algebra: distribute and isolate yy to go from point-slope to slope-intercept. Knowing both, and converting fluently, means you are never stuck regardless of which information the item hands you. A negative slope simply means the line falls (a decreasing function), as in a draining or depreciation context, and the method is identical.

Try this

Q1. Write the line with slope 33 through (0,βˆ’2)(0, -2). [1 point]

  • Cue. Slope-intercept directly: y=3xβˆ’2y = 3x - 2.

Q2. Write the line through (1,5)(1, 5) and (4,14)(4, 14). [2 points]

  • Cue. m=14βˆ’54βˆ’1=3m = \frac{14 - 5}{4 - 1} = 3; yβˆ’5=3(xβˆ’1)β‡’y=3x+2y - 5 = 3(x - 1) \Rightarrow y = 3x + 2.

Exam-style practice questions

Practice questions written in the style of TDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

TNReady (style)2 marksEquation response. Write the equation of the line through (2,3)(2, 3) and (6,11)(6, 11) in slope-intercept form.
Show worked answer β†’

The equation is y=2xβˆ’1y = 2x - 1.

First find the slope: m=11βˆ’36βˆ’2=84=2m = \frac{11 - 3}{6 - 2} = \frac{8}{4} = 2. Then use point-slope with (2,3)(2, 3): yβˆ’3=2(xβˆ’2)y - 3 = 2(x - 2), so yβˆ’3=2xβˆ’4y - 3 = 2x - 4, giving y=2xβˆ’1y = 2x - 1. Check with the other point: 2(6)βˆ’1=112(6) - 1 = 11, correct. Computing the slope first, then substituting one point, is the standard route.

TNReady (style)2 marksNumeric response. A pool drains at a constant rate. After 22 minutes it holds 440440 gallons; after 55 minutes it holds 380380 gallons. What was the starting amount (at t=0t = 0)?
Show worked answer β†’

The starting amount was 480480 gallons.

The rate (slope) is 380βˆ’4405βˆ’2=βˆ’603=βˆ’20\frac{380 - 440}{5 - 2} = \frac{-60}{3} = -20 gallons per minute (draining). Use point-slope with (2,440)(2, 440): Vβˆ’440=βˆ’20(tβˆ’2)V - 440 = -20(t - 2), so V=βˆ’20t+40+440=βˆ’20t+480V = -20t + 40 + 440 = -20t + 480. At t=0t = 0, V=480V = 480 gallons (the yy-intercept). The negative slope correctly reflects draining.

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