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How do you model and graph exponential growth and decay, and how do you tell an exponential situation from a linear one?

Construct and graph exponential functions, distinguish exponential from linear growth, and interpret growth and decay models (TN A1.F.IF.D.7e, A1.F.LE.A.1, A1.F.LE.A.2).

A TNReady Algebra I answer on exponential functions (TN A1.F.IF.D.7e, A1.F.LE.A.1-2), the growth and decay models, the meaning of the base, graphing with the y-intercept and asymptote, and linear versus exponential.

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  1. What this topic is asking
  2. The growth and decay models
  3. Graphing exponentials
  4. Linear versus exponential
  5. How TNReady examines this topic
  6. Why exponential eventually beats linear
  7. Try this

What this topic is asking

The Linear, Quadratic, and Exponential Models standards cover exponential functions. A1.F.LE.A.1 distinguishes exponential from linear situations; A1.F.LE.A.2 builds exponential models; A1.F.IF.D.7e graphs them, showing intercepts and end behavior. The model forms are not on the reference sheet, so memorize growth y=a(1+r)ty = a(1 + r)^t and decay y=a(1r)ty = a(1 - r)^t.

The growth and decay models

A percent change becomes a base near 11. Memorize these, since they are not on the reference sheet.

A 5%5\% increase gives base 1.051.05; a 5%5\% decrease gives base 0.950.95. The base is not the rate rr itself.

Graphing exponentials

The graph of f(x)=abxf(x) = ab^x has two reliable features:

  • yy-intercept at (0,a)(0, a): set x=0x = 0, since b0=1b^0 = 1.
  • Horizontal asymptote at y=0y = 0: the curve approaches but never touches the xx-axis (for the basic model).

Growth curves rise to the right and flatten toward the asymptote on the left; decay curves fall to the right toward the asymptote.

Linear versus exponential

The defining test (A1.F.LE.A.1): a quantity is linear if it changes by a constant amount per step (add the same number), and exponential if it changes by a constant factor or percent per step (multiply by the same number). "5050 per month" is linear; "5%5\% per month" is exponential. From a table, check whether successive differences are constant (linear) or successive ratios are constant (exponential).

How TNReady examines this topic

  • Numeric response. Write a model and evaluate it at a given time.
  • Multiple choice. Choose the growth or decay model, with base-versus-rate and linear-versus-exponential distractors.
  • Graphing / inline choice. Identify the yy-intercept, the asymptote, or whether a table is linear or exponential.

A clarifying idea is that exponential functions are the continuous cousins of geometric sequences: both multiply by a constant factor, so the base bb plays the role of the common ratio rr.

Why exponential eventually beats linear

A key TNReady idea (A1.F.LE.A.3) is that a quantity growing exponentially eventually exceeds one growing linearly, no matter how large the linear rate or how small the exponential rate. The reason is that linear growth adds a fixed amount each step, while exponential growth multiplies, so the increments themselves keep getting bigger. Early on, a line with a steep slope can be far ahead of a slow-growing exponential, which is why a table or graph might show the linear function winning at first. But because the exponential's step size compounds, it accelerates and overtakes the line, then pulls away for good. This is the mathematics behind compound interest outpacing simple savings, and behind why "5%5\% growth" beats "$50 per year" once enough time passes. Recognizing the constant-percent signature, and remembering that it always wins in the long run, is exactly what the standard tests.

Try this

Q1. Write a model for \800growingat growing at 3%peryear,andfindtheamountafter per year, and find the amount after 1$ year. [2 points]

  • Cue. A=800(1.03)tA = 800(1.03)^t; at t=1t = 1, A=824A = 824.

Q2. Is "a tank loses 1010 liters per hour" linear or exponential? [1 point]

  • Cue. Linear: a constant amount lost per hour (constant difference).

Exam-style practice questions

Practice questions written in the style of TDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

TNReady (style)2 marksNumeric response. A population of 500500 grows by 4%4\% per year. Write a model and find the population after 33 years (round to the nearest whole number).
Show worked answer →

The model is P=500(1.04)tP = 500(1.04)^t, and after 33 years P562P \approx 562.

Exponential growth is y=a(1+r)ty = a(1 + r)^t, with a=500a = 500 and r=0.04r = 0.04, so the growth factor is 1.041.04 and P=500(1.04)tP = 500(1.04)^t. For t=3t = 3: P=500(1.04)3=500(1.124864)562P = 500(1.04)^3 = 500(1.124864) \approx 562. The base is 1+r1 + r, so a 4%4\% increase gives 1.041.04, not 0.040.04. This model is not on the reference sheet, so memorize it.

TNReady (style)2 marksMultiple choice. A car worth 20,00020{,}000 loses 15%15\% of its value each year. Which model gives its value after tt years? (A) V=20000(0.85)tV = 20000(0.85)^t (B) V=20000(1.15)tV = 20000(1.15)^t (C) V=20000(0.15)tV = 20000(0.15)^t (D) V=2000015tV = 20000 - 15t
Show worked answer →

The correct answer is (A).

Exponential decay is y=a(1r)ty = a(1 - r)^t, so a 15%15\% loss gives a decay factor of 10.15=0.851 - 0.15 = 0.85: V=20000(0.85)tV = 20000(0.85)^t. Choice (B) is growth, (C) uses 0.150.15 (which would keep only 15%15\% each year), and (D) is linear (a constant dollar loss, not a constant percent). A constant percent change signals exponential, not linear.

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