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How do you write arithmetic and geometric sequences explicitly and recursively, and how are they related to linear and exponential functions?

Write arithmetic and geometric sequences both recursively and explicitly, and recognize sequences as functions on the integers (TN A1.F.BF.A.2, A1.F.IF.B.3).

A TNReady Algebra I answer on arithmetic and geometric sequences (TN A1.F.BF.A.2, A1.F.IF.B.3), the explicit and recursive forms from the reference sheet, common difference versus common ratio, and the link to linear and exponential functions.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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Jump to a section
  1. What this topic is asking
  2. Arithmetic versus geometric
  3. Explicit and recursive forms
  4. Sequences as functions
  5. How TNReady examines this topic
  6. Why the formula uses n minus 1
  7. Try this

What this topic is asking

Standard A1.F.BF.A.2 asks you to write arithmetic and geometric sequences both explicitly (a formula for the nnth term) and recursively (each term from the previous one). A1.F.IF.B.3 notes that sequences are functions whose domain is the integers. The Math EOC reference sheet provides the explicit formulas, so the skill is identifying a1a_1, dd or rr, and substituting.

Arithmetic versus geometric

The first move is to decide which type by checking consecutive terms.

  • Arithmetic: a constant difference between terms (+d+d each step). Example 4,7,10,134, 7, 10, 13 has d=3d = 3.
  • Geometric: a constant ratio between terms (Γ—r\times r each step). Example 4,8,16,324, 8, 16, 32 has r=2r = 2.

Explicit and recursive forms

The explicit form computes any term directly from nn; the recursive form needs the previous term. Both require the first term a1a_1.

Sequences as functions

A1.F.IF.B.3 frames a sequence as a function with input nn (a positive integer) and output ana_n. This is why an arithmetic sequence graphs as evenly spaced points on a line (slope dd) and a geometric sequence as points on an exponential curve (base rr). The link is exact: arithmetic is linear with the difference as slope, geometric is exponential with the ratio as base.

How TNReady examines this topic

  • Numeric response. Find a specific term (a20a_{20}) or the common difference or ratio.
  • Multiple choice. Choose the explicit or recursive rule, with arithmetic-versus-geometric and nn-versus-(nβˆ’1)(n-1) distractors.
  • Drag and drop. Match sequences to their rules.

A clarifying idea is that arithmetic sequences and linear functions share the constant-difference, constant-slope structure, while geometric sequences and exponential functions share the constant-ratio, constant-base structure. The sequence is just the function sampled at the integers.

Why the formula uses n minus 1

The (nβˆ’1)(n - 1) in both explicit forms is the most-missed detail, and it has a clear reason: the first term should come out when n=1n = 1, with no difference or ratio applied yet. For arithmetic, a1=a1+(1βˆ’1)d=a1+0=a1a_1 = a_1 + (1 - 1)d = a_1 + 0 = a_1, correct; using nn instead would add one extra dd and start the sequence at the wrong value. The same logic holds for geometric: a1=a1r1βˆ’1=a1r0=a1a_1 = a_1 r^{1-1} = a_1 r^0 = a_1, since any base to the zero power is 11. So (nβˆ’1)(n - 1) counts the number of steps taken from the first term, which is one fewer than the term number. Holding this idea, "steps from the start, not the term number", prevents the off-by-one error that the distractors are designed to catch.

Try this

Q1. Find the 1010th term of 2,5,8,11,…2, 5, 8, 11, \dots. [1 point]

  • Cue. d=3d = 3, a10=2+(10βˆ’1)(3)=2+27=29a_{10} = 2 + (10 - 1)(3) = 2 + 27 = 29.

Q2. Write the explicit rule for the geometric sequence 5,15,45,…5, 15, 45, \dots. [2 points]

  • Cue. r=3r = 3, an=5(3)nβˆ’1a_n = 5(3)^{n-1}.

Exam-style practice questions

Practice questions written in the style of TDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

TNReady (style)2 marksNumeric response. An arithmetic sequence starts 5,8,11,14,…5, 8, 11, 14, \dots. Find the 2020th term.
Show worked answer β†’

The 2020th term is 6262.

The reference sheet gives the arithmetic rule an=a1+(nβˆ’1)da_n = a_1 + (n - 1)d. Here a1=5a_1 = 5 and the common difference is d=8βˆ’5=3d = 8 - 5 = 3. For n=20n = 20: a20=5+(20βˆ’1)(3)=5+57=62a_{20} = 5 + (20 - 1)(3) = 5 + 57 = 62. The frequent slip is using nn instead of (nβˆ’1)(n - 1), which would give 5+60=655 + 60 = 65; the formula multiplies dd by one less than the term number.

TNReady (style)2 marksMultiple choice. A geometric sequence is 3,6,12,24,…3, 6, 12, 24, \dots. Which explicit formula gives the nnth term? (A) an=3(2)nβˆ’1a_n = 3(2)^{n-1} (B) an=3+2(nβˆ’1)a_n = 3 + 2(n-1) (C) an=2(3)nβˆ’1a_n = 2(3)^{n-1} (D) an=3(2)na_n = 3(2)^n
Show worked answer β†’

The correct answer is (A).

The reference sheet gives the geometric rule an=a1(r)nβˆ’1a_n = a_1 (r)^{n-1}. The first term is a1=3a_1 = 3 and the common ratio is r=63=2r = \frac{6}{3} = 2, so an=3(2)nβˆ’1a_n = 3(2)^{n-1}. Distractor (B) is arithmetic (adds rather than multiplies), (C) swaps a1a_1 and rr, and (D) uses nn instead of nβˆ’1n - 1, which would start the sequence at 66.

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