How do you graph the solution set of a linear inequality in two variables, choosing the boundary line style and the side to shade?
Graph the solution set of linear inequalities in two variables on the coordinate plane, using a solid or dashed boundary and shading the correct half-plane (TEKS A.3D).
A STAAR Algebra I answer on graphing linear inequalities in two variables (TEKS A.3D) - dashed versus solid boundary lines, choosing the half-plane to shade with a test point, and the hot-spot item type.
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What this topic is asking
TEKS A.3D asks you to graph the solution set of a linear inequality in two variables. On the redesigned STAAR this appears as a traditional question (match the description or the graph) and as a hot-spot item (select the matching inequality or shade a region). Two decisions define the graph: the boundary line style (solid or dashed) and which half-plane to shade.
Step one: the boundary line and its style
Replace the inequality symbol with an equals sign and graph that line. The symbol decides the style:
- or : solid line, because points on the line satisfy the inequality.
- or : dashed line, because points on the line are not solutions.
So uses a solid line; uses a dashed line. Choosing the wrong style is a frequent error on hot-spot items, where the solid-versus-dashed choice is part of the answer.
Step two: which half-plane to shade
Once the boundary is drawn, shade the region containing all the solution points. Two reliable methods:
- Solve for . With isolated, shade above for or and below for or .
- Test a point. Pick a point not on the line, often , and substitute. If the inequality is true, shade that point's side; if false, shade the other side.
Why the test point works
A boundary line splits the plane into two half-planes, and a linear inequality is true on exactly one of them. So a single test point settles the whole region: whichever side that point lands on, the truth value of the inequality there is the truth value for the entire half-plane. Choosing the origin is convenient whenever the line does not pass through it.
How STAAR examines this topic
- Multiple choice. Describe the graph (dashed or solid, above or below), or match an inequality to a shaded graph.
- Hot spot. Select the inequality that matches a shown graph, or identify the boundary and region. Both the line style and the shading must be right.
- In systems. Two-variable inequalities reappear when shading the overlap region for a system of inequalities.
A clarifying idea is that the boundary is the set of equality cases, so a solid line literally includes those edge points as solutions while a dashed line marks them as the cutoff that is not reached.
Inequalities in context and vertical or horizontal boundaries
In a real-world constraint, the shaded region is the set of feasible combinations. If a worker earns x15 per car wash () and needs at least 10x + 15y \ge 120xy$) makes sense. Restricting to sensible values is the interpretive step a context item rewards.
Boundaries are not always slanted. A horizontal boundary comes from an inequality like (shade everything on or below the horizontal line ), and a vertical boundary comes from (a dashed vertical line , shaded to the right). The same two decisions apply: the symbol sets solid versus dashed, and a test point or the direction of the inequality sets the shaded side. These simpler boundaries are easy points when you do not over-think them.
Try this
Q1. State the boundary style and shading for . [1 point]
- Cue. Dashed line (strict), shaded above.
Q2. Is a solution of ? [1 point]
- Cue. is true, so yes.
Exam-style practice questions
Practice questions written in the style of TEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
STAAR (style)1 marksMultiple choice. Which describes the graph of ? (A) Dashed line, shaded below (B) Solid line, shaded below (C) Dashed line, shaded above (D) Solid line, shaded aboveShow worked answer →
The correct answer is (A).
The inequality is strict (), so the boundary line is dashed (points on the line are not solutions). Because is less than the expression, the solution is the half-plane below the line. Test the origin : is false, so is not in the solution set, confirming you shade the side away from the origin, which here is below the line.
STAAR (style)2 marksHot spot. The graph of a linear inequality has a solid boundary line through and , with the region above the line shaded. Select the inequality that matches: , , , .Show worked answer →
The correct inequality is .
The boundary line through and has slope and -intercept 1, so it is . A solid line means the inequality includes equality ( or ). The region above the line is where is greater than the expression, so . A dashed line would have used a strict inequality; shading above rules out the options.
Related dot points
- Graph linear functions on the coordinate plane and identify key features, including x-intercept, y-intercept, zeros, and slope, in mathematical and real-world problems (TEKS A.3A).
A STAAR Algebra I answer on graphing linear functions and reading their key features (TEKS A.3A) - the x-intercept, y-intercept, zeros, and slope - from slope-intercept and standard form, including the hot-spot graphing item type.
- Solve linear inequalities in one variable, including those requiring the distributive property and those with variables on both sides, graph the solution, and interpret it in context (TEKS A.5B).
A STAAR Algebra I answer on solving one-variable linear inequalities (TEKS A.5B), the rule for flipping the sign when multiplying or dividing by a negative, graphing on a number line, and interpreting in context.
- Write linear equations in two variables in various forms (, , ) given one point and the slope, two points, a table, a graph, or a verbal description (TEKS A.2B, A.2C, A.2G).
A STAAR Algebra I answer on writing linear equations in slope-intercept, point-slope, and standard form (TEKS A.2B, A.2C, A.2G) from a point and slope, two points, a table, a graph, or a verbal description.
- Solve systems of two linear equations in two variables by graphing, substitution, and elimination, and determine whether a system has one solution, no solution, or infinitely many (TEKS A.5C, A.3E).
A STAAR Algebra I answer on solving systems of two linear equations by graphing, substitution, and elimination (TEKS A.5C, A.3E), and identifying one solution, no solution (parallel), or infinitely many (same line).
- Write systems of two linear equations given a table, a graph, a verbal description, or a real-world problem, then solve and interpret the solution in context (TEKS A.2H, A.2I).
A STAAR Algebra I answer on writing and modeling with systems of two linear equations from real-world situations (TEKS A.2H, A.2I), defining variables, building one equation per condition, and interpreting the solution.
Sources & how we know this
- STAAR Algebra I Assessed Curriculum — Texas Education Agency (2024)
- 19 TAC Chapter 111, Algebra I (TEKS), Adopted 2012 — Texas Education Agency (2012)