How do you write a system of two linear equations from a real-world situation and interpret the solution in context?
Write systems of two linear equations given a table, a graph, a verbal description, or a real-world problem, then solve and interpret the solution in context (TEKS A.2H, A.2I).
A STAAR Algebra I answer on writing and modeling with systems of two linear equations from real-world situations (TEKS A.2H, A.2I), defining variables, building one equation per condition, and interpreting the solution.
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What this topic is asking
Modeling with systems is where Reporting Category 3 brings everything together. TEKS A.2H and A.2I ask you to write a system of two linear equations from a table, graph, description, or real-world problem, then solve it and interpret the solution. STAAR scores these on the modeling: defining variables clearly and building one correct equation per condition, not just producing a number.
Define variables, then one equation per condition
Two habits earn the modeling credit. First, define the variables with let statements: "let = adult tickets, = child tickets". Second, write one equation for each piece of information. Most STAAR systems follow a recognizable pattern:
- A count equation: the number of items adds to a total, like .
- A value equation: each quantity times its unit value sums to a total, like .
Attaching the right number to the right variable, the price of an adult ticket to , is exactly where the distractors target.
Solving and interpreting
Once the system is written, solve by the most convenient method, then translate the answer back into the situation with units.
Break-even and comparison problems
A frequent application sets two expressions equal. In a break-even problem, cost (fixed plus per-unit) equals revenue (price times quantity), and the solution is the quantity where neither profit nor loss occurs. In a comparison problem (which plan is cheaper), set the two cost functions equal to find the crossover point, then reason about which side is cheaper.
How STAAR examines this topic
- Multiple choice. Choose the system that models a situation; wrong-price-to-variable and swapped-total distractors are standard.
- Equation editor and number entry. Build the equations and report the solution or the break-even quantity.
- Multi-step items. Define variables, write the system, solve, and interpret, with credit spread across the steps.
A clarifying idea is that each equation captures a different constraint, so the solution is the unique combination satisfying both at once, which is why a real-world system needs exactly two independent conditions to pin down two unknowns.
Recognizing the common system patterns
Most STAAR system word problems fall into a few recognizable shapes, and naming the shape tells you what the two equations should be. A ticket or purchase problem pairs a count equation with a total-cost equation. A mixture problem (nuts, solutions, coins) pairs a total-amount equation with a total-value equation. A break-even or comparison problem pairs two cost-or-revenue expressions and sets them equal. A distance or age problem encodes two relationships between the unknowns. Spotting which pattern a question fits turns an intimidating paragraph into a familiar template.
The danger with the value equation is mismatched units: the count equation adds quantities (tickets, pounds, items), while the value equation adds money (price times quantity). Mixing them, such as adding a price into the count equation, produces a system that looks plausible but models the wrong situation. Keeping the two equations in their separate units, one counting and one valuing, is the discipline that makes the model correct and the interpretation meaningful.
Try this
Q1. Pens cost 5. A student buys 8 items for $25. Write the system. [2 points]
- Cue. and .
Q2. Cost , revenue . Find break-even. [2 points]
- Cue. .
Exam-style practice questions
Practice questions written in the style of TEA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
STAAR (style)1 marksMultiple choice. Adult tickets cost 5. A group buys 12 tickets for a + c = 129a + 5c = 84a + c = 849a + 5c = 129a + 9c = 125a + 5c = 84a + c = 125a + 9c = 84$Show worked answer →
The correct answer is (A).
Let be adult tickets and be child tickets. The count equation is . The cost equation multiplies each price by its quantity: . Choice (B) swaps the totals, choice (D) attaches the wrong price to each variable. One equation counts items; the other totals their value.
STAAR (style)3 marksEquation editor. A small business has start-up costs of 4 to make each item, while selling each item for $10. Write the cost and revenue equations and find the break-even number of items.Show worked answer →
Cost , revenue , and the business breaks even at items.
Cost combines the fixed start-up and the per-item cost: . Revenue is price times quantity: . Break-even is where cost equals revenue: , so and . At 50 items, both cost and revenue are $500. Below 50 the business loses money; above 50 it profits. Defining the variables and writing one equation per quantity earns the modeling credit.
Related dot points
- Solve systems of two linear equations in two variables by graphing, substitution, and elimination, and determine whether a system has one solution, no solution, or infinitely many (TEKS A.5C, A.3E).
A STAAR Algebra I answer on solving systems of two linear equations by graphing, substitution, and elimination (TEKS A.5C, A.3E), and identifying one solution, no solution (parallel), or infinitely many (same line).
- Write linear functions that model the relationship between two quantities from a description, table, or graph, write an equation representing a functional relationship, and evaluate functions in function notation (TEKS A.2C, A.2G, A.12B).
A STAAR Algebra I answer on writing linear functions to model situations, identifying initial value and rate, function notation f(x), and evaluating functions (TEKS A.2C, A.2G, A.12B).
- Solve linear equations in one variable, including those requiring the distributive property and those with variables on both sides, and identify equations with one solution, no solution, or infinitely many (TEKS A.5A).
A STAAR Algebra I answer on solving one-variable linear equations (TEKS A.5A), the inverse-operations routine, the distributive property, variables on both sides, and recognizing one solution, no solution, or infinitely many.
- Solve linear inequalities in one variable, including those requiring the distributive property and those with variables on both sides, graph the solution, and interpret it in context (TEKS A.5B).
A STAAR Algebra I answer on solving one-variable linear inequalities (TEKS A.5B), the rule for flipping the sign when multiplying or dividing by a negative, graphing on a number line, and interpreting in context.
- Graph the solution set of linear inequalities in two variables on the coordinate plane, using a solid or dashed boundary and shading the correct half-plane (TEKS A.3D).
A STAAR Algebra I answer on graphing linear inequalities in two variables (TEKS A.3D) - dashed versus solid boundary lines, choosing the half-plane to shade with a test point, and the hot-spot item type.
Sources & how we know this
- STAAR Algebra I Assessed Curriculum — Texas Education Agency (2024)
- 19 TAC Chapter 111, Algebra I (TEKS), Adopted 2012 — Texas Education Agency (2012)