How do you recognize and predict the products of the five reaction types?
Types of chemical reactions: classify reactions as synthesis, decomposition, single replacement, double replacement or combustion, and predict their products.
A focused Virginia SOL Chemistry answer on reaction types under CH.3: the five categories (synthesis, decomposition, single replacement, double replacement, combustion), how to recognize each, and how to predict the products including using an activity series.
Reviewed by: AI editorial process; not yet individually human-reviewed
Have a quick question? Jump to the Q&A page
Jump to a section
What this topic is asking
Standard CH.3 asks you to classify reactions into five types and to predict their products. Virginia expects you to recognize synthesis, decomposition, single replacement, double replacement and combustion from the pattern of reactants and products, and to use an activity series to decide whether a single replacement happens. Recognizing the type tells you what products to expect and how to write the equation.
Synthesis and decomposition
These two are mirror images: synthesis builds up, decomposition breaks down. Recognizing which way the change runs (fewer substances to one, or one to several) tells you the type immediately.
Single and double replacement
For a single replacement, use the activity series: a metal will replace another metal (or hydrogen) only if it is more active. Zinc replaces copper in copper sulfate () because zinc is more active, but copper cannot replace zinc. A double replacement runs to completion when one product leaves the solution as an insoluble precipitate, a gas, or water; otherwise the ions stay mixed and no net reaction occurs.
Combustion
A combustion reaction is the rapid reaction of a fuel with oxygen, releasing energy. Complete combustion of a hydrocarbon always gives carbon dioxide and water: . Because the products are fixed (carbon dioxide and water), combustion is easy to spot from a hydrocarbon plus oxygen, and it is also exothermic, releasing heat.
Try this
Q1. Classify the reaction . [1 point]
- Cue. Decomposition; one compound breaks into two simpler substances.
Q2. Will copper replace silver in silver nitrate, given that copper is more active than silver? [1 point]
- Cue. Yes; a more active metal (copper) replaces a less active one (silver), so .
Exam-style practice questions
Practice questions written in the style of VDOE exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
SOL (multiple choice)1 marksThe reaction is best classified as (A) decomposition (B) synthesis (C) single replacement (D) double replacementShow worked answer β
The answer is (B) synthesis.
Two simpler substances (hydrogen and oxygen) combine to form a single more complex product (water). That is the pattern of a synthesis (combination) reaction, . Decomposition is the reverse, single and double replacement involve swapping ions or atoms, and none of those fit here.
The trap is calling any reaction with oxygen a combustion; combustion produces carbon dioxide and water from a fuel, which this is not.
SOL (tech-enhanced, drag and drop)3 marksClassify each reaction: (a) ; (b) ; (c) .Show worked answer β
A 3-point classification item.
(a) Decomposition (1 point): one compound breaks into two simpler substances, .
(b) Single replacement (1 point): an element (zinc) replaces another (hydrogen) in a compound, .
(c) Double replacement (1 point): two compounds swap ions, , here forming the precipitate .
Markers reward matching each reaction to its general pattern.
Related dot points
- Balancing equations and conservation of mass: balance chemical equations by adjusting coefficients to satisfy the law of conservation of mass.
A focused Virginia SOL Chemistry answer on chemical equations under CH.3: the law of conservation of mass, why only coefficients (not subscripts) may change, and a reliable method for balancing equations including combustion.
- Stoichiometry and the mole ratio: use the mole ratio from a balanced equation to convert between moles and masses of reactants and products, including gas volumes at STP.
A focused Virginia SOL Chemistry answer on stoichiometry under CH.3: reading the mole ratio from a balanced equation, mole-to-mole and mass-to-mass calculations, and using the molar volume of a gas at STP, with the full three-step chain.
- The mole and molar mass: use the mole, molar mass and Avogadro's number to convert between mass, moles and number of particles.
A focused Virginia SOL Chemistry answer on the mole under CH.3: Avogadro's number, finding the molar mass from the periodic table, and converting between mass, moles and number of particles, the master skill behind all chemical calculations.
- Limiting reactants and percent yield: identify the limiting and excess reactants, calculate the theoretical yield, and calculate the percent yield.
A focused Virginia SOL Chemistry answer on yield under CH.3: identifying the limiting and excess reactants, calculating the theoretical yield of product from the limiting reactant, and finding the percent yield from the actual yield.
- Neutralization and titration: write neutralization reactions that form a salt and water, and use titration data to find an unknown concentration.
A focused Virginia SOL Chemistry answer on neutralization under CH.5: the acid plus base gives salt plus water reaction, the role of indicators and the equivalence point, and using titration data with M1V1 = M2V2 to find an unknown concentration.
Sources & how we know this
- 2018 Science Standards of Learning - Chemistry β Virginia Department of Education (2018)
- Chemistry Curriculum Framework β Virginia Department of Education (2018)