Skip to main content
United StatesChemistrySyllabus dot point

How does the Beer-Lambert law let us find the concentration of a colored solution from how much light it absorbs?

Topic 3.13 Beer-Lambert Law: use the Beer-Lambert law to relate the absorbance of a solution to its concentration, and apply a calibration to find an unknown concentration.

A focused answer to AP Chemistry Topic 3.13, covering the Beer-Lambert law A equals epsilon b c, the meaning of absorbance, molar absorptivity and path length, and how a calibration curve determines an unknown concentration, with full worked examples.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this topic is asking
  2. The Beer-Lambert law
  3. Proportionality and the calibration curve
  4. Why the wavelength matters
  5. Try this

What this topic is asking

The College Board (Topic 3.13) wants you to use the Beer-Lambert law to relate the absorbance of a colored solution to its concentration, and to apply a calibration (a standard or a calibration curve) to find an unknown concentration. This is the quantitative payoff of the spectroscopy topics: because absorbance is proportional to concentration, a simple light measurement becomes an analytical tool.

The Beer-Lambert law

Absorbance measures how much light a solution removes from a beam passing through it. The law says that absorbance grows with three things: how strongly the species absorbs at that wavelength (ε\varepsilon), how far the light travels through the solution (bb), and how concentrated the solution is (cc). The more absorbing species in the path, the more light is absorbed.

Proportionality and the calibration curve

This is how the law is used in practice. You prepare several standards of known concentration, measure their absorbances, and plot AA against cc. The points fall on a line through the origin with slope εb\varepsilon b. An unknown's concentration is then found either by reading its absorbance off the line or by dividing its absorbance by the slope. Choosing the wavelength of maximum absorbance makes the measurement most sensitive.

Why the wavelength matters

The molar absorptivity ε\varepsilon depends on wavelength, because a species absorbs different wavelengths to different extents (its color). Measurements are made at the wavelength where the species absorbs most strongly, giving the largest ε\varepsilon and so the steepest calibration line and the best precision. At a wavelength the species does not absorb, ε\varepsilon and therefore AA would be near zero and the method would not work. This ties back to Topic 3.11: absorbance happens only where the photon energy matches an electronic transition.

Try this

Q1. State the Beer-Lambert law and the meaning of each term. [2 points]

  • Cue. A=εbcA = \varepsilon b c: absorbance equals molar absorptivity times path length times concentration.

Q2. A solution's absorbance is 0.6000.600 and the calibration slope is 30.0 M130.0\ \text{M}^{-1}. Calculate the concentration. [1 point]

  • Cue. c=Aεb=0.60030.0=0.0200c = \dfrac{A}{\varepsilon b} = \dfrac{0.600}{30.0} = 0.0200 M.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2023 (style)4 marksSection II (long FRQ, part). A student measures the absorbance of several standard solutions of a colored complex at a fixed wavelength and finds that absorbance is directly proportional to concentration, with a 0.02000.0200 M standard giving an absorbance of 0.4800.480. (a) State the Beer-Lambert law and define each term. (b) Calculate the constant of proportionality (the value of εb\varepsilon b). (c) An unknown solution gives an absorbance of 0.3600.360 in the same cell. Calculate its concentration. (d) Justify why a calibration curve through the origin is appropriate.
Show worked answer →

A 4-point quantitative FRQ on the Beer-Lambert law.

(a) Law (1 point): A=εbcA = \varepsilon b c, where AA is absorbance (unitless), ε\varepsilon is the molar absorptivity, bb is the path length, and cc is the concentration.
(b) Constant (1 point): εb=Ac=0.4800.0200=24.0 M1\varepsilon b = \dfrac{A}{c} = \dfrac{0.480}{0.0200} = 24.0\ \text{M}^{-1}.
(c) Unknown (1 point): c=Aεb=0.36024.0=0.0150c = \dfrac{A}{\varepsilon b} = \dfrac{0.360}{24.0} = 0.0150 M.
(d) Justify (1 point): a solution with zero concentration absorbs no light (A=0A = 0), so the line must pass through the origin, and the Beer-Lambert law predicts a straight line of absorbance against concentration.

Markers reward the correct law with terms defined, the slope from a standard, the unknown concentration from the slope, and the reasoning that zero concentration gives zero absorbance.

AP 2021 (style)1 marksSection I (multiple choice). According to the Beer-Lambert law, if the concentration of an absorbing solution is doubled (with the same cell and wavelength), the absorbance will (A) halve (B) stay the same (C) double (D) quadruple. Justify your reasoning.
Show worked answer →

A 1-point quantitative MCQ. The answer is (C).

The Beer-Lambert law A=εbcA = \varepsilon b c makes absorbance directly proportional to concentration when path length and wavelength (and therefore ε\varepsilon and bb) are fixed. Doubling the concentration doubles the absorbance.

Related dot points

Sources & how we know this