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Why does a substance dissolve in one solvent but not another, and how do temperature and pressure affect solubility?

Topic 3.10 Solubility: explain solubility in terms of the intermolecular forces between solute and solvent (like dissolves like), and describe how temperature and pressure affect the solubility of solids and gases.

A focused answer to AP Chemistry Topic 3.10, covering the like dissolves like principle, solute-solvent intermolecular forces, the role of ion-dipole and hydrogen bonding, and how temperature and pressure shift solubility, with full worked examples.

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  1. What this topic is asking
  2. Like dissolves like
  3. Why ionic and polar solutes dissolve in water
  4. Temperature and pressure effects
  5. Try this

What this topic is asking

The College Board (Topic 3.10) wants you to explain solubility, why a substance dissolves in one solvent but not another, in terms of the intermolecular forces between solute and solvent. The guiding rule is "like dissolves like": a solute dissolves well when the solute-solvent attractions are comparable in kind and strength to the forces being broken. You should also describe how temperature and pressure shift the solubility of solids and gases.

Like dissolves like

Dissolving is a competition of forces. To dissolve, a solute particle must be pulled away from its neighbors and surrounded by solvent. That only happens readily when the solvent can form attractions with the solute that are about as strong as the ones being broken. A polar solvent surrounds and stabilizes polar or ionic solutes; a nonpolar solvent does the same for nonpolar solutes.

Why ionic and polar solutes dissolve in water

This is why salt and sugar dissolve in water but oil does not. The oil molecules cannot form attractions with water strong enough to break into water's hydrogen-bonded structure, so the two stay separate. Conversely, oil dissolves in nonpolar solvents such as hexane, where dispersion forces on both sides match.

Temperature and pressure effects

The solubility of most solids in water increases with temperature, because the dissolving process is usually favored by added energy. The solubility of a gas in a liquid decreases with temperature (warm water holds less dissolved gas, which is why a warm soft drink goes flat faster) and increases with pressure. The pressure effect on gases is Henry's law: doubling the partial pressure of a gas above a liquid roughly doubles the amount that dissolves, which is how carbonated drinks are made under high CO2\text{CO}_2 pressure.

Try this

Q1. Predict whether ammonia (NH3\text{NH}_3) is soluble in water and justify. [2 points]

  • Cue. Yes; ammonia has N-H bonds and can hydrogen bond with water (like dissolves like).

Q2. Explain why opening a warm bottle of soda releases gas faster than a cold one. [1 point]

  • Cue. Gas solubility decreases as temperature rises, so warm soda holds less dissolved CO2\text{CO}_2 and loses it more readily.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2023 (style)3 marksSection II (short FRQ). Consider whether each solute dissolves well in water: sodium chloride (NaCl\text{NaCl}), oil (a nonpolar hydrocarbon mixture), and ethanol (CH3CH2OH\text{CH}_3\text{CH}_2\text{OH}). (a) Predict the water solubility of each. (b) Justify each prediction in terms of solute-solvent intermolecular forces. (c) Explain why a carbonated drink goes flat faster when warm.
Show worked answer β†’

A 3-point FRQ on solubility.

(a) Predictions (1 point): NaCl\text{NaCl} is highly soluble; oil is insoluble; ethanol is highly soluble (miscible).
(b) Justify (1 point): water molecules form strong ion-dipole attractions with Na+\text{Na}^+ and Clβˆ’\text{Cl}^-, so NaCl\text{NaCl} dissolves; oil is nonpolar and can only form weak dispersion forces with water, which cannot replace water's hydrogen bonds, so it does not dissolve; ethanol's O-H lets it hydrogen bond with water, so it is miscible.
(c) Carbonation (1 point): the solubility of a gas (CO2\text{CO}_2) in a liquid decreases as temperature rises, so a warm drink holds less dissolved CO2\text{CO}_2 and loses it faster.

Markers reward correct solubility predictions, justifications based on matching intermolecular forces, and the temperature-solubility relationship for a gas.

AP 2021 (style)1 marksSection I (multiple choice). Which substance is expected to be most soluble in water? (A) CCl4\text{CCl}_4 (B) C6H14\text{C}_6\text{H}_{14} (C) CH3OH\text{CH}_3\text{OH} (D) I2\text{I}_2. Justify your choice.
Show worked answer β†’

A 1-point conceptual MCQ. The answer is (C).

Methanol (CH3OH\text{CH}_3\text{OH}) has an O-H group, so it can hydrogen bond with water and is highly soluble (like dissolves like). CCl4\text{CCl}_4, C6H14\text{C}_6\text{H}_{14} and I2\text{I}_2 are all nonpolar and interact with water only through weak dispersion forces, so they are poorly soluble.

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