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How is an overall reaction built from a sequence of elementary steps, and what is an intermediate?

Topic 5.7 Introduction to Reaction Mechanisms: represent a reaction as a sequence of elementary steps, identify reaction intermediates and catalysts, and confirm that the steps sum to the overall equation.

A focused answer to AP Chemistry Topic 5.7, covering reaction mechanisms as sequences of elementary steps, identifying intermediates and catalysts, and checking that the steps add up to the overall equation, with full worked examples.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. What a mechanism is
  3. Summing the steps
  4. Intermediates and catalysts
  5. Try this

What this topic is asking

The College Board (Topic 5.7) wants you to represent an overall reaction as a sequence of elementary steps (its mechanism), identify reaction intermediates and catalysts within that sequence, and verify that the steps sum to the overall equation. A mechanism is the detailed story of how a reaction actually happens at the molecular level.

What a mechanism is

Most reactions do not happen in a single collision; they proceed through a few elementary steps involving short-lived species. The mechanism tells you what those species are and the order in which bonds break and form, which the overall equation hides.

Summing the steps

This summation is the bookkeeping check on every proposed mechanism. Species that cancel are either intermediates or catalysts, depending on the order in which they appear; species that survive are the net reactants and products.

Intermediates and catalysts

The distinction is the order of appearance. An intermediate is made first, then used up (it never existed before the reaction began). A catalyst is used up first, then remade (it was there from the start and returns). Both cancel when you sum the steps, so you must read the steps in sequence to tell them apart.

Try this

Q1. In the mechanism Step 1: Cl2→2Cl\text{Cl}_2 \rightarrow 2\text{Cl}; Step 2: Cl+O3→ClO+O2\text{Cl} + \text{O}_3 \rightarrow \text{ClO} + \text{O}_2; Step 3: ClO+O→Cl+O2\text{ClO} + \text{O} \rightarrow \text{Cl} + \text{O}_2, identify a catalyst. [2 points]

  • Cue. Cl is consumed in step 2 and regenerated in step 3, so Cl is the catalyst (ClO is an intermediate).

Q2. Explain how you would check that a proposed mechanism is consistent with the overall reaction. [1 point]

  • Cue. Add the elementary steps and cancel common species; the result must equal the overall balanced equation.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2023 (style)4 marksSection II (long FRQ, part). A proposed mechanism for 2NO2+F2β†’2NO2F2\text{NO}_2 + \text{F}_2 \rightarrow 2\text{NO}_2\text{F} is: Step 1: NO2+F2β†’NO2F+F\text{NO}_2 + \text{F}_2 \rightarrow \text{NO}_2\text{F} + \text{F}; Step 2: F+NO2β†’NO2F\text{F} + \text{NO}_2 \rightarrow \text{NO}_2\text{F}. (a) Show that the steps sum to the overall reaction. (b) Identify any reaction intermediate and justify the identification. (c) State the molecularity of each step. (d) Explain why F is not part of the overall equation.
Show worked answer β†’

A 4-point conceptual FRQ on mechanisms.

(a) Sum (1 point): adding the steps gives NO2+F2+F+NO2β†’NO2F+F+NO2F\text{NO}_2 + \text{F}_2 + \text{F} + \text{NO}_2 \rightarrow \text{NO}_2\text{F} + \text{F} + \text{NO}_2\text{F}; cancelling the F that appears on both sides leaves 2NO2+F2β†’2NO2F2\text{NO}_2 + \text{F}_2 \rightarrow 2\text{NO}_2\text{F}, the overall reaction.
(b) Intermediate (1 point): F is the intermediate; it is produced in step 1 and consumed in step 2, so it appears in the mechanism but not in the overall equation.
(c) Molecularity (1 point): step 1 is bimolecular (NO2+F2\text{NO}_2 + \text{F}_2); step 2 is bimolecular (F+NO2\text{F} + \text{NO}_2).
(d) Justify (1 point): F cancels because it is made and then used up within the mechanism, so its net amount is zero and it does not appear in the overall equation.

Markers reward the summed equation, identifying F as the intermediate, the molecularities, and the cancellation reasoning.

AP 2021 (style)1 marksSection I (multiple choice). In a reaction mechanism, a species that is consumed in an early step and regenerated in a later step is best called a (A) reaction intermediate (B) catalyst (C) transition state (D) product. Justify your choice.
Show worked answer β†’

A 1-point conceptual MCQ. The answer is (B).

A catalyst is used up early and regenerated later, so it does not appear in the overall equation but is not net consumed. An intermediate is the opposite order: produced first, then consumed. A transition state is a peak on the energy diagram, not a species. The trap is confusing a catalyst with an intermediate.

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