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Why does an object moving in a circle at constant speed still accelerate, and what provides the force that keeps it on its circular path?

Topic 2.9 Circular Motion: analyze uniform circular motion using centripetal acceleration and the net inward (centripetal) force that produces it.

A focused answer to AP Physics 1 Topic 2.9, covering uniform circular motion, centripetal acceleration, the centripetal force as the net inward force, period and speed relationships, and common real-world examples, with full worked examples.

Generated by Claude Opus 4.810 min answer

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  1. What this topic is asking
  2. Why circular motion is accelerated motion
  3. Centripetal acceleration
  4. The centripetal force
  5. Why there is no outward force
  6. Try this

What this topic is asking

The College Board (Topic 2.9) wants you to analyze uniform circular motion: motion in a circle at constant speed. You must explain why such an object is accelerating even though its speed is constant, calculate its centripetal acceleration, and identify the net inward force (the centripetal force) that produces it. The key conceptual hurdle is accepting that "centripetal force" is not a new kind of force but the name for whatever real force points toward the center.

Why circular motion is accelerated motion

This is the conceptual heart of the topic. Velocity is a vector; turning it, even without changing its length, is a change in velocity, and any change in velocity is an acceleration. So an object circling at steady speed is accelerating at every instant.

Centripetal acceleration

The direction is always toward the center, perpendicular to the velocity (which is tangent to the circle). This perpendicular relationship is exactly why the speed stays constant: a force perpendicular to the motion changes direction but does no work to change speed.

The centripetal force

By Newton's second law, an inward acceleration requires an inward net force:

Fc=mac=mv2rF_c = m a_c = \frac{mv^2}{r}

This centripetal force is the net force, directed toward the center. The vital point is that it is not a new force; it is supplied by whatever real force happens to point inward in a given situation:

  • For a ball on a string, the tension provides it.
  • For a satellite or planet, gravity provides it.
  • For a car on a flat curve, friction provides it.
  • For a car on a banked track or a rider in a loop, a component of the normal force provides it.

To solve a circular-motion problem, draw the free-body diagram, find the net force directed toward the center, and set it equal to mv2r\dfrac{mv^2}{r}.

Why there is no outward force

A persistent misconception is that an object in circular motion feels an outward "centrifugal" force. There is no such force acting on the object. What you feel when a car turns is your own inertia: your body tends to continue in a straight line (Newton's first law), and the door or seatbelt pushes you inward to make you follow the curve. The only real horizontal force on you is that inward push, which is the centripetal force. If the inward force is suddenly removed, for example a string snaps, the object does not fly outward; it flies off tangentially, in a straight line, exactly as the first law predicts. Period and speed are also connected: for one full circle the object travels a distance 2Ï€r2\pi r in one period TT, so v=2Ï€rTv = \dfrac{2\pi r}{T}, which lets you swap between speed and period in problems about orbits, turntables, or spinning rides. Keeping the force inward, recognizing it as a real named force, and remembering the tangential escape route, are the three ideas that make circular-motion problems reliable.

Try this

Q1. A 0.500.50 kg object moves in a circle of radius 2.02.0 m at 4.04.0 m/s. Calculate the centripetal force. [2 points]

  • Cue. Fc=mv2r=(0.50)(4.0)22.0=4.0F_c = \dfrac{mv^2}{r} = \dfrac{(0.50)(4.0)^2}{2.0} = 4.0 N toward the center.

Q2. State the direction in which a ball on a string flies if the string suddenly breaks. [1 point]

  • Cue. Tangentially (in a straight line along its velocity at that instant), not outward.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

AP 2024 (style)4 marksSection II (short FRQ, quantitative). A 0.200.20 kg ball on a string moves in a horizontal circle of radius 0.600.60 m at a constant speed of 3.03.0 m/s. (a) Calculate the centripetal acceleration. (b) Calculate the centripetal force. (c) Identify what provides the centripetal force and explain why the ball accelerates even though its speed is constant.
Show worked answer →

A 4-point uniform-circular-motion FRQ.

(a) Centripetal acceleration (1 point): ac=v2r=(3.0)20.60=9.00.60=15a_c = \dfrac{v^2}{r} = \dfrac{(3.0)^2}{0.60} = \dfrac{9.0}{0.60} = 15 m/s squared, directed toward the center.
(b) Centripetal force (1 point): Fc=mac=(0.20)(15)=3.0F_c = m a_c = (0.20)(15) = 3.0 N, directed toward the center.
(c) Identify and explain (2 points): the tension in the string provides the centripetal force. The ball accelerates because acceleration is a change in velocity, and although the speed is constant the direction of the velocity continually changes, so there is a centripetal (inward) acceleration.

Markers reward the centripetal acceleration and force formulas, naming the tension as the source, and explaining acceleration as a change in the direction of velocity.

AP 2022 (style)1 marksSection I (multiple choice). A car rounds a flat circular curve at constant speed. In which direction does the net force on the car point? (A) forward, in the direction of motion (B) backward, opposing the motion (C) toward the center of the curve (D) away from the center. Justify your reasoning.
Show worked answer →

A 1-point conceptual MCQ. The answer is (C).

In uniform circular motion the acceleration, and therefore the net force, points toward the center of the circle (centripetal). For the car, this inward force is supplied by friction between the tyres and the road. There is no real outward "centrifugal" force on the car; the inward net force is what bends its path into a circle. The trap is choosing an outward direction; the required force is inward.

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