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How do amplitude, period, midline, and phase shift shape the graph of a sine or cosine function?

Identify the amplitude, period, midline, and phase shift of a sinusoidal function from its equation; graph sine and cosine functions; and build a sinusoidal model of a periodic real-world situation.

A NY Regents Algebra II answer on sinusoidal functions: reading amplitude, period, midline, and phase shift from the equation, graphing sine and cosine, and modeling periodic phenomena such as tides and temperature.

Generated by Claude Opus 4.89 min answer

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  1. What this topic is asking
  2. The four parameters
  3. Graphing a sinusoid
  4. Modeling a periodic situation
  5. Try this

What this topic is asking

The Regents Algebra II exam (the Trigonometric Functions, F-TF, and Interpreting Functions, F-IF, clusters) wants you to read the amplitude, period, midline, and phase shift of a sinusoidal function from its equation, graph sine and cosine functions, and build a sinusoidal model of a periodic real-world situation such as tides, temperature, or a Ferris wheel. Sinusoidal modeling is a frequent Part III task.

The four parameters

A sinusoidal function is fully described by four numbers in its equation.

The amplitude is the height from the midline to a peak; the period is the horizontal length of one full cycle; the midline is the horizontal line the curve oscillates around; the phase shift moves the whole curve left or right. Note that the period depends on BB through 2πB\frac{2\pi}{B}, so a larger BB compresses the cycle.

Graphing a sinusoid

To graph, start from the midline y=Dy = D, mark the maximum D+AD + |A| and minimum DAD - |A|, and lay out one period of length 2πB\frac{2\pi}{B} divided into quarters (the sine pattern is midline, max, midline, min, midline across one period). Apply any phase shift by sliding the starting point.

Modeling a periodic situation

To build a model from data such as a tide table, extract the four parameters from the situation:

  • Midline DD = the average of the maximum and minimum values.
  • Amplitude AA = half the difference between the maximum and minimum.
  • BB from the period: B=2πperiodB = \frac{2\pi}{\text{period}}.

A clarifying point that protects credit is the distinction between the amplitude and the maximum value: the amplitude is the distance from the midline to a peak, while the maximum is the midline plus the amplitude. A tide with amplitude 4 and midline 7 has a maximum of 11, not 4. The Regents frequently tests this by asking for the maximum height, and answering with the amplitude alone is a common, costly slip. Likewise, the period and the value of BB are reciprocally related through the factor 2π2\pi, so keep them straight.

A second useful idea is the difference between sine and cosine starting points, which matters when you choose a model. A cosine curve y=Acos(Bx)+Dy = A\cos(Bx) + D starts at its maximum when x=0x = 0, while a sine curve y=Asin(Bx)+Dy = A\sin(Bx) + D starts at the midline and rises. So when a real situation begins at its highest value (a Ferris wheel rider boarding at the top, a temperature peaking at noon), a cosine model is the natural fit; when it begins at the average value and increases, sine fits directly. You can always convert between them with a phase shift, but choosing the function that matches the starting behavior keeps the model simpler and the parameters easier to read.

Try this

Q1. State the amplitude and period of y=5sin(3x)y = 5\sin(3x). [2 credits]

  • Cue. Amplitude 55; period 2π3\frac{2\pi}{3}.

Q2. A sinusoid has maximum 10 and minimum 2. Find its midline and amplitude. [2 credits]

  • Cue. Midline 10+22=6\frac{10 + 2}{2} = 6; amplitude 1022=4\frac{10 - 2}{2} = 4.

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (style)2 marksPart I (multiple choice). What is the period of y=3sin(2x)+1y = 3\sin(2x) + 1? (1) π\pi (2) 2π2\pi (3) 33 (4) π2\frac{\pi}{2}
Show worked answer →

The correct answer is (1).

For y=Asin(Bx)y = A\sin(Bx), the period is 2πB\frac{2\pi}{B}. Here B=2B = 2, so the period is 2π2=π\frac{2\pi}{2} = \pi. The amplitude 3 and vertical shift 1 do not affect the period. Choice (2) ignores the factor of BB; choice (3) confuses the amplitude with the period.

Regents (style)4 marksPart III (constructed response). The height of a tide, in feet, is modeled by h(t)=4sin(π6t)+7h(t) = 4\sin\left(\frac{\pi}{6}t\right) + 7, where tt is hours after midnight. (a) State the amplitude, midline, and period. (b) Find the maximum height and the first time after midnight it occurs.
Show worked answer →

A 4-credit question with credits across the parts.

(a) Amplitude =4= 4; midline y=7y = 7; period =2ππ/6=12= \frac{2\pi}{\pi/6} = 12 hours.
(b) The maximum is midline plus amplitude =7+4=11= 7 + 4 = 11 feet. The sine reaches its first maximum a quarter-period after the midline crossing at t=0t = 0, so at t=124=3t = \frac{12}{4} = 3 hours (3 a.m.). Confusing the amplitude with the maximum (giving 4 instead of 11), or the period formula, costs credits.

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