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How do arithmetic and geometric sequences work, and how do you sum a series?

Write explicit and recursive formulas for arithmetic and geometric sequences; find a specified term; use sigma notation; and apply the arithmetic and finite geometric series sum formulas.

A NY Regents Algebra II answer on sequences and series: explicit and recursive formulas for arithmetic and geometric sequences, finding a term, sigma notation, and the arithmetic and finite geometric series sums.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this topic is asking
  2. Arithmetic versus geometric
  3. Finding a term
  4. Sigma notation and series sums
  5. Choosing the right tool
  6. Try this

What this topic is asking

The Regents Algebra II exam (the Building Functions, F-BF, and Linear, Quadratic, and Exponential Models, F-LE, clusters) wants you to write explicit and recursive formulas for arithmetic and geometric sequences, find a given term, use sigma notation, and apply the arithmetic and finite geometric series sum formulas. Sequences connect to linear and exponential growth and appear in modeling contexts.

Arithmetic versus geometric

A sequence is arithmetic if each term differs from the previous by a constant common difference dd, and geometric if each term is the previous one times a constant common ratio rr.

Arithmetic sequences grow linearly (constant difference) and geometric sequences grow exponentially (constant ratio), mirroring the linear-versus-exponential distinction. A recursive formula always needs a stated first term.

Finding a term

To find a specific term, substitute into the explicit formula. The exponent and the multiplier use nβˆ’1n - 1, not nn, because the first term corresponds to n=1n = 1 with no change applied yet. For a geometric sequence with a1=2a_1 = 2 and r=4r = 4, the 5th term is a5=2(4)5βˆ’1=2(4)4=2(256)=512a_5 = 2(4)^{5-1} = 2(4)^4 = 2(256) = 512.

Sigma notation and series sums

A series is the sum of the terms of a sequence, written compactly with sigma notation: βˆ‘k=1nak\sum_{k=1}^{n} a_k means add aka_k from k=1k = 1 to k=nk = n. The sum formulas (both on the reference sheet) let you total many terms at once.

Choosing the right tool

A clarifying point that prevents the most frequent errors is to identify arithmetic versus geometric first, then pick the matching formula. A constant difference signals arithmetic (use a1+(nβˆ’1)da_1 + (n-1)d and the n2(a1+an)\frac{n}{2}(a_1 + a_n) sum); a constant ratio signals geometric (use a1rnβˆ’1a_1 r^{n-1} and the a1βˆ’a1rn1βˆ’r\frac{a_1 - a_1 r^n}{1 - r} sum). The arithmetic sum formula also requires the last term ana_n, so compute that term first if you are not given it. Because both explicit formulas and both sum formulas are printed on the reference sheet, the credit lies in selecting the correct one and substituting accurately, not in memorizing them.

Try this

Q1. Find the 6th term of an arithmetic sequence with a1=4a_1 = 4 and d=5d = 5. [1 credit]

  • Cue. a6=4+5(5)=29a_6 = 4 + 5(5) = 29.

Q2. Write the recursive formula for a geometric sequence with first term 3 and ratio 2. [1 credit]

  • Cue. a1=3a_1 = 3, an=2anβˆ’1a_n = 2 a_{n-1}.

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (style)2 marksPart I (multiple choice). A geometric sequence has first term 5 and common ratio 3. What is the 4th term? (1) 135135 (2) 4545 (3) 1515 (4) 1414
Show worked answer β†’

The correct answer is (1).

The explicit formula is an=a1rnβˆ’1a_n = a_1 r^{n-1} (on the reference sheet). With a1=5a_1 = 5, r=3r = 3, n=4n = 4: a4=5(3)4βˆ’1=5(3)3=5(27)=135a_4 = 5(3)^{4-1} = 5(3)^3 = 5(27) = 135. Choice (3) uses n=2n = 2; choice (4) treats it as arithmetic with d=3d = 3. The exponent is nβˆ’1n - 1, not nn.

Regents (style)4 marksPart III (constructed response). A theater has 20 seats in the first row, and each row has 3 more seats than the row before. (a) Write an explicit formula for the number of seats in row nn. (b) Find the total number of seats in the first 15 rows.
Show worked answer β†’

A 4-credit question: credit for the formula and the series sum.

(a) Arithmetic with a1=20a_1 = 20 and d=3d = 3: an=20+(nβˆ’1)(3)=17+3na_n = 20 + (n - 1)(3) = 17 + 3n.
(b) The 15th term is a15=20+14(3)=62a_{15} = 20 + 14(3) = 62. The arithmetic series sum is Sn=n2(a1+an)=152(20+62)=152(82)=615S_n = \frac{n}{2}(a_1 + a_n) = \frac{15}{2}(20 + 62) = \frac{15}{2}(82) = 615 seats. Using the wrong term count or the geometric sum formula by mistake loses credit.

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