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New YorkPhysicsSyllabus dot point

How are magnetism and electric current related, and what force acts on a moving charge in a magnetic field?

Describe magnetic fields and the field produced by an electric current, apply FB=qvBF_B = qvB to the force on a moving charge in a magnetic field, and explain the force on a current-carrying wire that underlies the electric motor.

A Regents Physics answer on magnetism and the motor effect: magnetic fields and field lines, the magnetic field of a current, the force on a moving charge using the Reference-Table equation, and the force on a current-carrying wire that drives electric motors, with worked examples.

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  1. What this topic is asking
  2. Magnetic fields and field lines
  3. The magnetic field of a current
  4. The force on a moving charge
  5. The motor effect
  6. Reference Tables note
  7. Try this

What this topic is asking

This dot point introduces magnetism and its deep link to electric current. The Physical Setting/Physics course asks you to describe magnetic fields and their field lines, to recognize that an electric current produces a magnetic field, to calculate the force on a moving charge in a magnetic field with FB=qvBF_B = qvB, and to understand the force on a current-carrying wire that makes electric motors turn (the motor effect). The Regents tests field directions, the conditions for a magnetic force, and the FB=qvBF_B = qvB calculation.

Magnetic fields and field lines

Like magnetic poles repel and unlike poles attract, echoing electric charges, but magnetic poles always come in north-south pairs; a single isolated pole has never been found. Field lines are closer together where the field is stronger (near the poles) and never cross. Reading field-line diagrams and the direction of the field is a common Regents task.

The magnetic field of a current

This connection, that electricity and magnetism are two aspects of one phenomenon, is the heart of the strand. A current creates a magnetic field (electromagnetism), and, conversely, a changing magnetic field creates a current (electromagnetic induction). Electromagnets are used in motors, relays, loudspeakers and maglev systems.

The force on a moving charge

The dependence on the angle is important: only the component of velocity perpendicular to the field contributes, so a charge moving along the field lines feels no force. Because the force is always perpendicular to the velocity, it changes the charge's direction but not its speed, which makes charged particles move in circles in a uniform field (as in a mass spectrometer). The Regents most often gives the perpendicular case so FB=qvBF_B = qvB applies directly.

The motor effect

The moving charges in a current-carrying wire in a magnetic field each feel the FB=qvBF_B = qvB force, and together they produce a force on the wire. The size of this force is F=BILF = BIL (recall, not on the tables), where II is the current and LL the length of wire in the field, and its direction is perpendicular to both the current and the field. This motor effect is what makes an electric motor turn: a current-carrying coil in a magnetic field experiences forces that rotate it. Reversing the current or the field reverses the force.

Reference Tables note

The equation FB=qvBF_B = qvB is printed in the Electricity section of the Reference Tables (it is the only magnetic equation there). The force on a current-carrying wire, F=BILF = BIL, is not printed, so you recall it. The field-line conventions, the right-hand rules for direction, and the fact that a current produces a magnetic field are qualitative ideas the Regents expects you to know rather than read from the booklet.

Try this

Q1. State the condition under which a moving charge feels the maximum magnetic force, and the condition for zero force. [2 points]

  • Cue. Maximum when the velocity is perpendicular to the field; zero when the velocity is parallel to the field.

Q2. A 3.03.0 C charge moves at 2.02.0 m/s perpendicular to a 0.400.40 T field. Calculate the magnetic force. [2 points]

  • Cue. FB=qvB=(3.0)(2.0)(0.40)=2.4F_B = qvB = (3.0)(2.0)(0.40) = 2.4 N.

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (style)2 marksPart B-2 (constructed response). A charge of 2.02.0 C moves at 3.03.0 m/s perpendicular to a magnetic field of strength 0.500.50 T. Calculate the magnitude of the magnetic force on the charge. Show the equation, substitution and answer.
Show worked answer →

A 2-point constructed-response calculation using the Reference-Table equation FB=qvBF_B = qvB (charge moving perpendicular to the field).

Equation: FB=qvBF_B = qvB.
Substitution: FB=(2.0)(3.0)(0.50)F_B = (2.0)(3.0)(0.50).
Answer: FB=3.0F_B = 3.0 N.

Markers reward the equation from the tables, correct substitution with units, and the force in newtons. The equation FB=qvBF_B = qvB applies when the velocity is perpendicular to the field, as stated here.

Regents (style)1 marksPart A (multiple choice). A charged particle moves parallel to a uniform magnetic field. The magnetic force on the particle is (1) maximum (2) zero (3) equal to its weight (4) directed along the field. Justify your choice.
Show worked answer →

A 1-point Part A conceptual item on the magnetic force. The answer is (2).

The magnetic force on a moving charge is greatest when the velocity is perpendicular to the field and is zero when the velocity is parallel to the field (no component crosses the field lines). Since the particle moves parallel to the field here, the magnetic force is zero. The equation FB=qvBF_B = qvB assumes the perpendicular case.

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