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How do physicists distinguish quantities that need a direction from those that do not, and how are vectors combined?

Distinguish scalar and vector quantities, represent vectors as scaled arrows, and find the resultant of vectors by graphical and component methods, including resolving a vector into perpendicular components.

A Regents Physics answer on scalars versus vectors: what each is, how to draw vectors as scaled arrows, how to add vectors graphically (head-to-tail) and by components, and how to resolve a vector into perpendicular components, with worked examples and Reference-Table notes.

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  1. What this topic is asking
  2. Scalars and vectors
  3. Representing vectors as arrows
  4. Adding vectors head to tail
  5. Resolving a vector into components
  6. Reference Tables note
  7. Try this

What this topic is asking

The Physical Setting/Physics Core Curriculum opens mechanics by asking you to separate scalar quantities, which have magnitude only, from vector quantities, which have both magnitude and direction, and then to combine vectors correctly. On the Regents this surfaces as quick multiple-choice items ("which of these is a vector?") and as constructed-response problems that ask for the magnitude and direction of a resultant or the components of a single vector. Getting the distinction right is the foundation for every later mechanics topic, because displacement, velocity, acceleration, force and momentum are all vectors.

Scalars and vectors

The difference matters because vectors do not add like ordinary numbers. Walking 66 km east and then 88 km north leaves you 1010 km from the start, not 1414 km, because the directions are different. Whenever a Regents problem mentions a direction, or asks "how far from the start" rather than "how far travelled", you are working with vectors.

Representing vectors as arrows

A vector is drawn as an arrow on a chosen scale: its length is proportional to the magnitude, and it points in the direction of the quantity. A velocity of 2020 m/s east and one of 4040 m/s east are parallel arrows, the second twice as long. Two velocities of equal speed in opposite directions are equal-length arrows pointing opposite ways, and they are different vectors even though their speeds (the scalars) are equal.

Adding vectors head to tail

For two perpendicular vectors (a very common Regents setup, such as a boat crossing a river or a hiker turning a right angle), the resultant is the hypotenuse of a right triangle:

R=A2+B2,θ=tan1 ⁣(BA)R = \sqrt{A^2 + B^2}, \qquad \theta = \tan^{-1}\!\left(\frac{B}{A}\right)

where θ\theta is measured from vector AA. For two vectors at a general angle, you add them by components (below) or, on a diagram, by careful head-to-tail construction and measurement.

Resolving a vector into components

The reverse move, used constantly in projectile and force problems, is to split one vector into two perpendicular components. With the angle θ\theta measured from the horizontal:

Ax=Acosθ,Ay=AsinθA_x = A\cos\theta, \qquad A_y = A\sin\theta

The horizontal component uses cosine and the vertical component uses sine when the angle is taken from the horizontal. Resolving turns an awkward diagonal vector into two independent one-dimensional problems, which is exactly how projectile motion and inclined-plane forces are handled.

To add several vectors by components, resolve each into xx and yy parts, add the xx parts and the yy parts separately to get RxR_x and RyR_y, then recombine: R=Rx2+Ry2R = \sqrt{R_x^2 + R_y^2} with direction θ=tan1(Ry/Rx)\theta = \tan^{-1}(R_y/R_x).

Reference Tables note

The Reference Tables for Physical Setting/Physics give you the constants and the kinematics, force and energy equations, but they do not print the vector formulas R=A2+B2R = \sqrt{A^2 + B^2}, Ax=AcosθA_x = A\cos\theta or Ay=AsinθA_y = A\sin\theta. You are expected to know the Pythagorean theorem and basic right-triangle trigonometry and apply them. The tables do include the trigonometric definitions of sine, cosine and tangent for reference.

Try this

Q1. State one example each of a scalar and a vector quantity, other than those used above. [2 points]

  • Cue. A scalar example: temperature (or distance, speed, mass). A vector example: weight (or any force, acceleration, momentum).

Q2. A car drives 3030 m east then 4040 m west. Calculate the magnitude of its resultant displacement. [2 points]

  • Cue. These are along one line, so subtract: 4030=1040 - 30 = 10 m west. (The distance travelled is 7070 m, but displacement is the net vector.)

Exam-style practice questions

Practice questions written in the style of NYSED exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Regents (style)1 marksPart A (multiple choice). Which pair of quantities are both vectors? (1) speed and distance (2) displacement and velocity (3) mass and time (4) energy and speed. Justify your choice.
Show worked answer →

A 1-point Part A item on the scalar-vector distinction. The answer is (2).

A vector has both magnitude and direction; a scalar has magnitude only. Displacement (how far and in which direction) and velocity (speed with a direction) are both vectors. Speed, distance, mass, time and energy are scalars: they are fully described by a number with a unit and need no direction. The trap is choosing (1), since speed and distance feel like they should be vectors, but neither carries a direction.

Regents (style)2 marksPart B-2 (constructed response). A hiker walks 6.06.0 km due east, then 8.08.0 km due north. Determine the magnitude of the hiker's resultant displacement, and state its direction relative to east.
Show worked answer →

A 2-point constructed-response vector-addition item. Because the two legs are perpendicular, the resultant is the hypotenuse of a right triangle.

Magnitude (1 point): R=(6.0)2+(8.0)2=36+64=100=10.R = \sqrt{(6.0)^2 + (8.0)^2} = \sqrt{36 + 64} = \sqrt{100} = 10. km.
Direction (1 point): θ=tan1 ⁣(8.06.0)=53\theta = \tan^{-1}\!\left(\dfrac{8.0}{6.0}\right) = 53^\circ north of east.

Markers reward the Pythagorean magnitude and a direction stated as an angle from a named reference (here, north of east). A common error is adding the legs to get 1414 km, which ignores that displacement is a vector.

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