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United StatesMathsSyllabus dot point

How do you read one-variable data, compute and compare measures of center and spread, and reason about samples and statistical claims?

One-variable data: mean, median, mode and range, standard deviation as spread, the effect of outliers, and inference from sample statistics including margin of error and evaluating statistical claims.

A focused answer to the Digital SAT Problem-Solving and Data Analysis skill of one-variable data: mean, median, mode and range, standard deviation as spread, outlier effects, and reasoning about sampling, margin of error, and statistical claims.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this skill is asking
  2. Center and spread
  3. A worked center comparison
  4. Outliers, skew, and which measure to use
  5. Sampling, margin of error, and statistical claims

What this skill is asking

One-variable data questions give a list, table, dot plot, histogram, or box plot and ask about its center and spread. The Digital SAT (Problem-Solving and Data Analysis domain) tests the mean, median, mode, and range, treats standard deviation as a conceptual measure of spread, asks how outliers shift these, and extends to inference: what a sample says about a population, margin of error, and judging statistical claims.

Center and spread

Each statistic captures a different feature of the data.

A worked center comparison

Comparing mean and median reveals skew.

Outliers, skew, and which measure to use

The relationship between mean and median signals the shape of the data. If the data is roughly symmetric, mean and median are close. If a few large values stretch the right tail (right skew), the mean exceeds the median; if a few small values stretch the left tail (left skew), the mean is below the median. Because the median is resistant to outliers and the mean is not, the median is the better summary of a typical value when outliers or strong skew are present (incomes are the classic example). The SAT often asks which measure a change affects: adding an extreme value shifts the mean noticeably and the range a lot, but may leave the median unchanged.

Sampling, margin of error, and statistical claims

The domain also tests inference. A sample is used to estimate a population parameter, and the estimate is only trustworthy if the sample is randomly selected and representative; a biased sampling method (volunteers, a convenient group) undermines any conclusion. The margin of error describes how far the true population value might be from the sample estimate; a larger and more random sample produces a smaller margin of error, so a result like "52%52\% plus or minus 3%3\%" means the population value plausibly lies between 49%49\% and 55%55\%. When judging a statistical claim, ask two questions: was the sample random and representative (so results generalise to the stated population), and does the data actually support the conclusion drawn? Only a randomised experiment can support a cause-and-effect claim; an observational study can show association but not causation.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Digital SAT Math (style)1 marksThe data set is 4, 7, 7, 9, 13. Which statement is true? (A) The mean is greater than the median (B) The mean equals the median (C) The mode is 9 (D) The range is 7
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The correct answer is (A), the mean is greater than the median.

Mean =4+7+7+9+135=405=8= \frac{4 + 7 + 7 + 9 + 13}{5} = \frac{40}{5} = 8. The median (middle value of the sorted set) is 77. So the mean (88) is greater than the median (77), pulled up by the large value 1313. The mode is 77 (not 99), and the range is 134=913 - 4 = 9 (not 77).

Digital SAT Math (style)1 marksTwo classes take the same test. Class A scores cluster tightly around 75; Class B scores are spread widely around 75. Both have a mean of 75. Which has the larger standard deviation? (A) Class A (B) Class B (C) They are equal (D) Cannot be determined
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The correct answer is (B), Class B.

Standard deviation measures spread around the mean. The two classes share a mean of 7575, but Class B's scores are spread more widely, so its values sit farther from the mean on average. Greater spread means a larger standard deviation, so Class B has the larger standard deviation.

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