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How do you set up and solve ratio, rate, and proportion problems, including unit conversions?

Ratios, rates, proportional relationships, and units: solve proportions, work with unit rates and constant of proportionality, and convert between units including compound units.

A focused answer to the Digital SAT Problem-Solving and Data Analysis skill of ratios, rates and proportional relationships: setting up proportions, finding unit rates and the constant of proportionality, and converting units including speeds and densities.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this skill is asking
  2. Setting up proportions
  3. A worked unit-conversion
  4. Unit rates and the constant of proportionality
  5. Proportional reasoning shortcuts

What this skill is asking

A ratio compares two quantities, a rate is a ratio of quantities with different units (like miles per hour), and a proportional relationship is one where two quantities keep a constant ratio. The Digital SAT (Problem-Solving and Data Analysis domain) tests setting up and solving proportions, finding and using unit rates, and converting units, including compound units such as speed and density. These are word-problem heavy and reward careful setup.

Setting up proportions

The reliable method is to write a ratio with consistent units on both sides.

A worked unit-conversion

Conversions are about cancelling units cleanly.

Unit rates and the constant of proportionality

A unit rate answers "how much per one?" and is found by division: 150 miles2.5 hours=60\frac{150 \text{ miles}}{2.5 \text{ hours}} = 60 miles per hour. In a proportional relationship y=kxy = kx, that unit rate is the constant kk, and it is also the slope of the straight line through the origin that represents the relationship. So a question that gives a proportional table and asks for kk is asking for the unit rate: divide any yy by its xx. Recognising that "constant of proportionality", "unit rate", and "slope through the origin" all name the same number lets you answer many PSDA questions with a single division.

Proportional reasoning shortcuts

Many proportion questions yield to a quick scale factor rather than full cross-multiplication. If 1212 cups of flour is 44 times the 33 cups in the ratio, then every other ingredient also scales by 44. Spotting the multiplier between the given value and the ratio value often beats setting up and solving an equation. For inverse relationships (where one quantity goes up as the other goes down, like speed and travel time for a fixed distance), the product stays constant rather than the ratio, so set x1y1=x2y2x_1 y_1 = x_2 y_2. Telling a direct proportion (constant ratio) from an inverse one (constant product) is the key reading skill.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Digital SAT Math (style)1 marksA recipe uses 3 cups of flour for every 2 cups of sugar. If a baker uses 12 cups of flour, how many cups of sugar are needed? (A) 66 (B) 88 (C) 1313 (D) 1818
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The correct answer is (B), 8.

Set up a proportion keeping flour over sugar: 32=12s\frac{3}{2} = \frac{12}{s}. Cross-multiply: 3s=243s = 24, so s=8s = 8. (Equivalently, 1212 cups of flour is 44 times the 33 in the ratio, so the sugar is 4×2=84 \times 2 = 8.)

Digital SAT Math (style)1 marksA car travels 150 miles in 2.5 hours at a constant speed. At this rate, how far does it travel in 4 hours? (A) 200200 (B) 225225 (C) 240240 (D) 375375
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The correct answer is (C), 240 miles.

The unit rate (speed) is 150 miles2.5 hours=60\frac{150 \text{ miles}}{2.5 \text{ hours}} = 60 miles per hour. In 44 hours the distance is 60×4=24060 \times 4 = 240 miles.

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