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United StatesMathsSyllabus dot point

How do you solve percent problems, including percent change, successive percentages, and reverse percentages?

Percentages: compute a percent of a number, percent increase and decrease, percent change, successive percent changes, and find an original amount from a percentage (reverse percent).

A focused answer to the Digital SAT Problem-Solving and Data Analysis skill of percentages: percent of a number, percent increase and decrease, percent change, successive percentages, and finding an original amount from a known percentage.

Generated by Claude Opus 4.811 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this skill is asking
  2. The percent toolkit
  3. A worked successive-percentage
  4. Percent change and direction
  5. Reverse percent: the most missed type
  6. Percent in tables, taxes and tips

What this skill is asking

A percent is a fraction out of 100. The Digital SAT (Problem-Solving and Data Analysis domain) tests finding a percent of a number, computing percent increase and decrease, finding the percent change between two values, chaining successive percentages, and the trickier reverse-percent problem of recovering an original amount from a known percentage of it.

The percent toolkit

Almost every percent question reduces to a multiplier.

A worked successive-percentage

Chained percentages multiply, which surprises many students.

Percent change and direction

The percent change formula always divides by the original (old) value, not the new one: newoldold×100%\frac{\text{new} - \text{old}}{\text{old}} \times 100\%. A positive result is an increase and a negative result is a decrease. A frequent SAT trap is dividing by the wrong base; the percent change from 4040 to 5050 is 504040=25%\frac{50 - 40}{40} = 25\%, but from 5050 to 4040 it is 405050=20%\frac{40 - 50}{50} = -20\%, so the "up" and "down" percentages differ even though the absolute change is the same. Always anchor the denominator on the starting value.

Reverse percent: the most missed type

The hardest percent questions give you the result of a percent change and ask for the original. The mistake is to take the percentage of the result. Instead, recognise the multiplier and divide. If a 20%20\% increase produced 72007200, the original satisfies 1.20×original=72001.20 \times \text{original} = 7200, so original =72001.20=6000= \frac{7200}{1.20} = 6000, not 72000.20×72007200 - 0.20 \times 7200. The same logic handles reverse discounts: if a 25%25\%-off sale price is \60,theoriginalis, the original is \frac{60}{0.75} = \8080. Writing the multiplier equation first and dividing is the reliable route through every reverse-percent question.

Percent in tables, taxes and tips

Many SAT percent questions arrive dressed as everyday money problems: sales tax, tips, commissions, and markups, sometimes layered. A price plus an 8%8\% tax is the price times 1.081.08; a bill plus a 15%15\% tip is the bill times 1.151.15. When two percentages apply, decide whether they stack (multiply the factors) or apply to different bases. For instance, a \200itemwitha item with a 10%discountandthen discount and then 8%taxonthediscountedpriceis tax on the discounted price is 200 \times 0.90 \times 1.08 = \194.40194.40, because the tax is charged on the already-discounted amount. Percent questions also appear inside two-way tables and survey data, where "what percent of the juniors play a sport" means dividing the relevant cell by the junior total and multiplying by 100100. The constant skill across all of these is identifying the correct base (the "percent of what?") before you multiply or divide.

Exam-style practice questions

Practice questions written in the style of College Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Digital SAT Math (style)1 marksA jacket priced at \80isdiscountedby2580 is discounted by 25%. What is the sale price? (A) \20 (B) \55 (C) \60 (D) \$75
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The correct answer is (C), $60.

A 25%25\% discount means the customer pays 100%25%=75%100\% - 25\% = 75\% of the price. Multiply: 0.75×80=600.75 \times 80 = 60. (Or compute the discount 0.25×80=200.25 \times 80 = 20 and subtract: 8020=6080 - 20 = 60.)

Digital SAT Math (style)1 marksAfter a 20% increase, a town's population is 7,200. What was the population before the increase? (A) 5,7605{,}760 (B) 6,0006{,}000 (C) 6,4806{,}480 (D) 9,0009{,}000
Show worked answer →

The correct answer is (B), 6,000.

A 20%20\% increase multiplies the original by 1.201.20, so 1.20×(original)=72001.20 \times (\text{original}) = 7200. Divide: original=72001.20=6000\text{original} = \frac{7200}{1.20} = 6000. (Checking: 6000×1.20=72006000 \times 1.20 = 7200.) Reverse-percent questions require dividing by the multiplier, not taking 20%20\% of the new value.

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